If JL =120, what are the lengths of JK and KL
Answers
The length of JK is 42 and the length of KL is 69
Calculating Length
From the question, we are to determine the length of JK and KL
From the given information,
JK = 4x + 6
KL = 7x + 15
In the diagram,
JL = JK + KL
120 = 4x + 6 + 7x + 15
120 = 11x + 21
120 - 21 = 11x
99 = 11x
x = 99/11
x = 9
∴ JK = 4x + 6 = 4(9) + 6
JK = 36 + 6
JK = 42
and
KL = 7x + 15 = 7(9) + 6
KL = 63 + 6
KL = 69
Hence, the length of JK is 42 and the length of KL is 69
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The equation x - 6y = 0 can be written in slope-intercept form as y = (1/6)x
How to write the equation in slope intercept form
To convert the given equation into slope-intercept form (y = mx + b), we isolate y on one side of the equation.
First, we add 6y to both sides to get x = 6y.
Next, we divide both sides by 6, yielding y = (1/6)x.
The slope (m) iis1/6 which represents the change in y for every unit change in x. The intercept (b) is 0, indicating that the line passes through the origin.
In conclusion, the equation x - 6y = 0 can be written in slope-intercept form as y = (1/6)x. This form allows us to easily identify the slope and y-intercept, providing valuable information about the graph of the line. The slope of 1/6 means the line has a positive slope, and the y-intercept of 0 indicates that the line passes through the origin.
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Answers
The square can be constructed by making perpendicular on vertex A and B. Then cut an arcs and obtain the points C and D and construct perpendicular on point C and D and get ABCD is required square.
Further Explanation:
Square is a 4 sided close figure.
Square has all sides equal and all angles are of .
The all sides of the square are perpendicular to each other.
Given:
A line segment AB.
Construction:
Steps involve in constructing a square from a line segment AB are as follows.
1. Draw a line segment AB.
2. Construct perpendicular AX at point A and then construct another perpendicular BY at point B.
3. Cut an arc on perpendicular line from A at point C that is equal to the length equal to side AB
4. Cut an arc on perpendicular line from B at point D that is equal to the length equal to side AB
5. Construct perpendicular at point C and then construct another perpendicular at point D.
6. The perpendicular intersects each other at point C and D.
The required square is ABCD is shown in figure attached.
Kindly refer to the image attached.
Learn more:
1. Learn more about inverse of the function brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function brainly.com/question/3412497
Answer details:
Grade: Middle School
Subject: Mathematics
Chapter: Construction
Keywords: square, perpendicular, , intersect, construct, line, line segment, point, right angle, sides, close figure, arc, length.
1. Extend the segment AB twice left and twice right. Let the point that lies left be D and the point that lies right be C. Then AD=AB=BC.
2. Draw the circles with center at points D and B and congruent radii that are greater than AB. Denote two points of their intersection as E and F.
3. Combine points E and F. The segment EF is perpendicular to the segment AB and passes through the point A.
4. Draw the circles with center at points C and A and congruent radii that are greater than AB. Denote two points of their intersection as K and L.
5. Combine points K and L. The segment KL is perpendicular to the segment AB and passes through the point B.
6. Postpone on the segment EF point X such that AX=AB and on the segment KL point Y, such that BY=AB and X and Y lie for the same side.
7. Combine points X and Y. ABYX is required square.
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The shortest distance from the center of the inscribed circle to the triangle's sides is the circle's radius
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