Calculate the change in momentum of a 45 kg runner who starts out at 1 m/s and speeds up to 3 m/s. Which anser choice is correct 90 kg⋅m/s 45 kg⋅m/s 135 kg⋅m/s 0 kg⋅m/s

Answers

Answer 1
Answer:

momentum can also be defined in terms of newton second

that is P=F.V

now v =vf-vi

v=3 m/s-1m/s=2 m/s

now F=W=45 kg

therefore

change in momentum=F.v

P=45*2=90 kg.m/s


Related Questions

The velocity of a car traveling in a straight line increases from 0 meters/second to 30 meters/second in 8 seconds. What is the average acceleration of the car?
What is the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?A. 12,000 JB. 6,000 JC. 2,940 JD. 5,880 J
Sound waves, water waves, and light waves are all alike in that they all
Which process produces the energy radiated by the star when it becomes a main sequence star?
Jose’s lab instructor gives him a solution of sodium phosphate that is buffered to a pH of 4. Because of an error that he made while calibrating the pH meter, Jose’s measurements of the pH of the sodium phosphate solution are 5.4, 5.4, and 5.4. Which statement best describes his results?

The Cenozoic Era is best described as the era in which

Answers

The era after the KT event occurred

What do scientists believe the moon’s core might be formed of?a. Iron
c. Carbon
b. Silicon
d. Lava

Answers

Answer:

A. Iron.

Explanation:

The Moon´s core is smaller in comparison with other terrestrial bodies. About 20% of the entire mass of it is the core.

The moon is composed of distinct crust, mantle, and core. While the crust is composed of freeze magma the core is believed to be formed by a mixture of metallic iron with a small amount of sulfur and nickel.

I hope this answer helps you.

Scientists believe the moon’s core might be formed of iron.

What does the object on the screen below model?A. Molecules
B. The orbit of the moon around the Earth
C. The orbits of the planets around the Sun
D. Electronic circuits

Answers

Answer:

A, molecules

Explanation:

Molecules were viewable around the time period of the computers shown on the screen

Answer:

correct option is (A)........

When two point charges are a distance d apart, the magnitude of the electrostatic force between them is F. If the distance between the point charges is increased to 3d, the magnitude of the electrostatic force between the two charges will be

Answers

Answer:

The magnitude of the electrostatic force decreases by a factor 9

Explanation:

The electrostatic force between two charges is given by:

F=k(q_1 q_2)/(d^2)

where

k is the Coulomb's constant

q1 and q2 are the two charges

d is the distance between the two charges

We see that the magnitude of the force is inversely proportional to the square of the distance. If the distance is increased to 3d: d' = 3d, the new electrostatic force would be:

F'=k(q_1 q_2)/((d')^2)=k(q_1 q_2)/((3d)^2)=(1)/(9) k(q_1 q_2)/(d^2)=(F)/(9)

So, the electrostatic force decreases by a factor 9.

Decreased by a factor of 9

At what point in the motion is the velocity zero and the acceleration zero simultaneously?At what point in the motion is the velocity zero and the acceleration zero simultaneously?

A. x>0 but xB. x=A
C. x<0.
D. x=0.
E. None of the above

Answers

Answer:

The correct answer is option E. This is because when a body is undergoing simple harmonic motion, the displacement, velocity and acceleration are constantly changing with respect to position and time.

Explanation:

When the body is passing through the equilibrium position so that the displacement at that point is zero, the velocity at that point is either maximum or minimum (Vmax or Vmin) which is dependent on which way the body is moving (the chosen direction of positive sense of motion). At the equilibrium position the acceleration is zero because the net force acting on the body is zero (that is the sun of the forces acting on the body along both directions of motion is equal to zero). Also when the body is at either its maximum positive displacemt, x = +A, or its maximum negative displacement x = -A, the velocity is zero and the body is instantaneously at rest. At this points the force (in either direction) acting on the body has it maximum value and as a result the acceleration has it maximum magnitude whether negative or positive depending on the chosen direction positive sense of motion.

At any other point in the course of the SHM (simple harmonic motion), the velocity (V) and acceleration (a) of the always have nonzero values and as a result they are never simultaneously equal to zero.

Thank you very much reading and I hope this is helpful to you.

A sample of gold has a mass of 38.6 grams and a volume of 2 cm3. What is the density of gold

Answers

The density of the sample of gold whose mass is 38.6 grams and with a volume of 2 cm³ is 19300 kg/m

Density: This can be defined as the ratio of mass and velocity. The S.I unit of density is kg/m³.

The question above can be solved using the formula below

D = m/V.................... Equation 1

Where D = density of the sample of gold, m = mass of gold, V = volume of gold.

From the question,

Given: m = 38.6 g, = 0.0386 kg, V = 2 cm³ = 0.000002 m³

Substitute these values into equation 1

D = 0.0386/0.000002

D = 19300 kg/m³

Hence the density of the sample of gold is 19300 kg/m³

Learn more about density here: brainly.com/question/23562510

Answer:

19.3 g/cm^3

Explanation:

The density of a material is given by

\rho = (m)/(V)

where

m is the mass of the sample

V is its volume

for the sample of gold in this problem,

m = 38.6 g

V=2 cm^3

Substituting into the formula, we find the density of gold:

\rho = (38.6)/(2)=19.3 g/cm^3