When determining an element identity what is the most important Subatomic part to look at?

Answers

Answer 1

Answer:

Answer: Protons

Explanation: When determining an element identity the most important Subatomic part to look at is the number of protons in the nucleus determines the identity of an atom .

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Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions. Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) S (s) (nonspontaneous)? Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq) (nonspontaneous)? 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq) (spontaneous?) Are these correct?

Answers

A electrochemical reaction is said to be spontaneous, if $E^(0) cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
   $S^(2-)/S // Ni^(2+)/Ni$

Hence, $E^(0)cell = E^(0) Ni^(2+/Ni) - E^(0) S/S^(2-)$
we know that, ${E^(0) Ni^(2+)/Ni = -0.25 v$
and ${E^(0) S/ S^(2-) = -0.47 v$

Therefore, $E^(0) cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^(0) cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
   $H_(2) / H^(+) // Pb^(2+) /Pb$

Hence, $E^(0)cell = E^(0) Pb/Pb^(2+) - E^(0) H_(2)/H^(+)$
we know that, ${E^(0) Pb^(2+)/Pb = -0.126 v$
and ${E^(0) H_(2)/ H^(+) = -0 v$

Therefore, $E^(0) cell$ = - 0.126 - 0 = -0.126 v

Since,   $E^(0) cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
   $Cr/Cr^(2+) // Ag^(+)/Ag$

Hence, $E^(0)cell = E^(0) Ag^(+)/Ag - E^(0) Cr/Cr^(2+)$
we know that, ${E^(0) Ag^(+)/Ag = -0.22 v$
and ${E^(0) Cr/ Cr^(2+) = -0.913 v$

Therefore, $E^(0) cell$ = - 0.22 - (-0.913) = 0.693 v

Since,   $E^(0) cell$ is positive, hence cell reaction is spontaneous

Answer: $Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)$ : non spontaneous

$Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)$ : non spontaneous

$2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)$ : spontaneous

Explanation:

a) $Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)$

Here S undergoes oxidation by loss of electrons, thus act as anode. Ni undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Ni^(2+)/Ni])=-0.25V$

$E^0_([S^(2-)/S])=0.407VV$

$E^0=E^0_([Ni^(2+)/Ni])- E^0_([S^(2-)/S])$

$E^0=-0.25-(0.407V)-0.657V$

As value of $E^0$ is negative, the reaction is non spontaneous.

b) $Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)$

Here Hydrogen undergoes oxidation by loss of electrons, thus act as anode. Pb undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Pb^(2+)/Pb])=-0.13$

$E^0_([H^(+)/H_2])=0V$

$E^0=E^0_([Pb^(2+)/Pb])- E^0_([H^(+)/H_2])$

$E^0=-0.13-(0V)=-0.13V$

As value of $E^0$ is negative, the reaction is non spontaneous.

c) $2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)$

Here Cr undergoes oxidation by loss of electrons, thus act as anode. Ag undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Ag^(+)/Ag])=+0.80V$

$E^0_([Cr^(2+)/Cr])=-0.913V$

$E^0=E^0_([Ag^(+)/Ag])- E^0_([Cr^(2+)/Cr])$

$E^0=+0.80-(-0.913V)=1.713V$

As value of $E^0$ is positive, the reaction is spontaneous.

Infrequent participation in physical activity can lead toa. high blood pressure during exercise
b. muscle strain and soreness after exercise
c. extra calories burned during exercise
d. low heart rate after exercise

Answers

We can see here that infrequent participation in physical activity can lead to: b. muscle strain and soreness after exercise

What is physical activity?

Infrequent participation in physical activity can lead to muscle strain and soreness after exercise. When individuals are not regularly engaged in physical activity, their muscles may not be conditioned or accustomed to the stress and demands placed on them during exercise. As a result, they may experience muscle strain, micro-tears in the muscle fibers, and delayed-onset muscle soreness (DOMS) following physical activity.

It's worth mentioning that leading a sedentary lifestyle, which involves minimal physical activity overall, can have broader health implications beyond muscle strain and soreness.

Learn more about physical activity on brainly.com/question/13490156

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An example of a physical property of an element is the element’s ability to(1) react with an acid(2) react with oxygen(3) form a compound with chlorine(4) form an aqueous solution

Answers

Answer is: 4) form an aqueous solution.

Physical property can be observed and measured without any changes in molecular composition. The same substance is present before and after the change. Making aqueous solution is physical change (solvatation).

Element reactions with acids, oxygen and chlorine are chemical change (chemical reaction combustion), because new substances are formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).

4: Form An Aqueous Solution

This is the only answer that can be observed without testing gear and with the naked eye.... Hope I helped ^-^

Which statement describes what occurs as two atoms of bromine combine to become a molecule of bromine?(1) Energy is absorbed as a bond is formed.
(2) Energy is absorbed as a bond is broken.
(3) Energy is released as a bond is formed.
(4) Energy is released as a bond is broken.

Answers

Answer:

The correct answer is option 3.

Explanation:

Whenever there is a formation of bond between 2 atoms energy is released. This energy release is due to stability gained by the atoms after the formation of a bond that is why extra energy is released as a heat into surroundings. Exact process is occurring when 2 bromine atoms form bond to give molecule of bromine.

Whenever there is a dissociation of bond between 2 atoms energy is given. The energy provided externally so as to break the stable bond present between the atoms.

Br + Br -> Br2 (covalent bond)

forming of bonds releases energy, since the Br's are at a lower energy state as Br2

Answer is #3

What's the balanced equation for cellular respiration?

Answers

Correct answer is:

$C_(6)H_(12)O_6+6O_(2)\Rightarrow 6CO_(2)+6H_(2)O+energy$

But how to get there?

Let's start with simple explanation of what exactly is cellular respiration.

Cellular respiration is a multistage biochemical oxidation process of organic substances when prime product is energy (ATP - adenosine triphosphate) and other are released waste products. Cellular respiration takes place even if other metabolic processes are stopped, but cellular respiration may differ in particular organism groups.Some reactions during whole process of cellular respiration are similar in all types of living organisms.

Cellular respiration is prime indication of declining living processes.Only viruses which are on the edge of living organism and chemical particle are not performing cellular respiration.But to the point :P

In cellular respiration all substrates which are in the cell might be organic, but mostly we are using sugar oxidation - glucose in the presence of oxygen. Chemical formula of sugar looks like this:

$C_(6)H_(12)O_6$

Oxygen is just

$O_2$

so for now we have just part of the equation:

$C_(6)H_(12)O_6+O_(2)\Rightarrow$

But what would be on the right hand side?

It's quite simple, remember equation of full combustion? If we want to burn something we need oxygen like in the equation, so the product of this equation would be carbon dioxide, water and of course energy (ATP).Carbon dioxide formula looks like this:

$CO_(2)$

As a reminder water formula:

$H_(2)O$

Full formula would look like that:

$C_(6)H_(12)O_6+O_(2)\Rightarrow\ CO_(2)+H_(2)O+energy$

But still as you see this equation is unbalanced, after balancing it would like that:

$C_(6)H_(12)O_6+6O_(2)\Rightarrow 6CO_(2)+6H_(2)O+energy$

At the end I would like to explain one more thing. Energy which has been released during this process is part of high-energy connection which might be used to perform chemical reactions in the cell or to move organism for example in muscles. We need to remember that production of ATP is not happening with 100% efficiency and part of this energy is released as heat.

A resource that humans can use to produce energy is

Answers

Is the sun it gives plants lots of energy and sunlight is energy

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