How many moles of oxygen will be released when 250.0 grams of KClO3 is thermally decomposed ? 2KClO3 --> 2KCl+3O2<br /><br /> (Must be made to fit into this chart)
Answers
2 KClO₃ ----------------> 2 KCl + 3 O₂
2 * 122.5 g KClO₃ ---------> 3 * 32 g O₂
250.0 g KClO₃ ------------> ?
mass of O₂ = 250.0 * 3 * 32 / 2 * 122.5
mass of O₂ = 24000 / 245
mass of O₂ = 97.959 g
number of moles O₂ :
1 mole --------- 32.0 g
? mole -------- 97.959 g
moles = 97.959 * 1 / 32.0
= 97.959 / 32.0
= 3.061 moles of O₂
hope this helps!
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Answer:
T = 291 K
Explanation:
A. 1
B. +1
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D. 0
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Answer:
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sulfur
anitmony
selenium
Answers
Answer: Option (a) is the correct answer.
Explanation:
Electric current is the flow of electrons and an atom that has free electrons will be able to carry current easily.
Hence, electronic configurations of the given elements are as follows.
Tin (Sn) -
Sulfur (S) -
Antimony (Sb) -
Selenium (Se) -
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Answer: currency
Explanation:
Answers
Answer:
3.3 liters of the mixture is needed to be removed and filled with 3.33 liters pure antifreeze to reach a concentration of 60% antifreeze.
Explanation:
A 10 L mixture is made up of 40% antifreeze.
Initial Volume of antifreeze in 40% mixture = 40% of 10 L = 4L
Let volume of pure antifreeze added = x
Volume of antifreeze removed = 40% of x= 0.4 x
Volume of antifreeze in 60% mixture = 60% of 10 L = 6 L
Volume of antifreeze left after removal of 0.4 x L of antifreeze and addition of x L of pure antifreeze will be equal to 6 L of antifreeze in the final solution.
4L - (0.4 x ) + x = 6L
x = 3.33 L
3.3 liters of the mixture is needed to be removed and filled with 3.3 liter pure antifreeze to reach a concentration of 60% antifreeze.