2x - 4y = 20
x =4
a. 4, -2
b. 4, 3
c. 4, 4
d. 4, -3

Answers

Answer 1

Answer: D. 4, -3 Because you plug in 4 for the x and 2•4 is 8, then you subtract 8 from both sides of the equal sign. (20-8=12) then you’re left with -4y = 12 divide by -4 on both sides of the equal sign, and y= -3 (and you’re already given the value of x)

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$3000 invested at an APR of 5% for 7 years. If interest is compounded annually , what is the amount of money after 7 years?

Answers

With annual compounding, the value of the investment after 7 years is

Value = $3,000 [ 1 + 0.05 ] to the 7th power .

Value = $3,000 [ 1.4071 ] = $4,221.30

$Sum=\$3000\cdot(1+5\%)^7=\$3000\cdot (1.05)^7\approx \$4221.30$

Simplify the expression (4x - 3)(x + 5).

Answers

=>(4x - 3) (x + 5)=>(4x × x )+( 4x × 5) - (3 × x ) -( 3 × 5)=>4x^2 + 20x -3x - 15=>4x^2 + 17x -15Hope it helps!!!

Wait I think it's 9x-3.. Sorry...

2. Which is larger?The common ratio, r , in a geometric sequence whose second term is
24 and whose fifth term is 1536
or
The common difference, d , in an arithmetic sequence whose fourth
term is 16 and whose seventh term is 31.

Answers

Answer:

The common difference d is larger than the common ratio r

Step-by-step explanation:

The common difference in the arithmetic sequence $d=u_(n)-u_(n-1)$

The nth term in the arithmetic sequence is $a_(n)=a+(n-1)d$ , where a is the first term

The common ratio in the geometric sequence $r=(u_(n))/(u_(n-1))$

The nth term in the geometric sequence is $a_(n)=a(r)^(n-1)$ , where a is the first term

Geometric sequence

∵ The second term is 24

∴ $u_(2)$ = 24

∵ $u_(2)=a(r)^(2-1)=ar$

- Equate it by its value

∴ ar = 24 ⇒ (1)

∵ The fifth term is 1536

∴ $u_(5)$ = 1536

∵ $u_(5)=a(r)^(5-1)=ar^(4)$

- Equate it by its value

∴ $ar^(4)$ = 1536 ⇒ (2)

Divide (2) by (1)

∴ $(ar^(4))/(ar)=(1536)/(24)$

- Divide up and down by ar

∴ r³ = 64

- Take ∛ for both sides

∴ r = 4

Arithmetic sequence

∵ The fourth term is 16

∴ $u_(4)$ = 16

∵ $u_(4)$ = a + (4 - 1)d

∴ $u_(4)$ = a + 3 d

- Equate it by its value

∴ a + 3d = 16 ⇒ (1)

∵ The seventh term is 31

∴ $u_(7)$ = 31

∵ $u_(7)$ = a + (7 - 1)d

∴ $u_(7)$ = a + 6 d

- Equate it by its value

∴ a + 6 d = 31 ⇒ (2)

Subtract equation (1) from equation (2) to eliminate a and find d

∵ (a - a) + (6 d - 3 d) = (31 - 16)

∴ 3 d = 15

- Divide both sides by 3

∴ d = 5

∵ r = 4 and d = 5

∴ d > r

∴ The common difference d is larger than the common ratio r

"six less than the quotient of a number cubed and nine, increased by twelve" when n
=3

Answers

Answer:

Step-by-step explanation:

Make your equation:

((n^3/9)-6)+12

Substitute in 3 for n:

((3^3/9)-6)+12

Simplify and solve:

3^3=27

27/9=3

3-6=-3

-3+12=9

Answer:

Step-by-step explanation:

i got 100%

A fast food restaurant sells two sizes of fries, small and large. On friday they sold 81 fries total. If 9 of the fries were small, what is the ratio of large fries sold to small fries sold?