A newspaper article about the danger of global warming from the accumulation of greenhouse gases such as carbon dioxide states that "reducing driving your car by 20 miles a week would prevent release of over 1000 pounds of CO 2 per year into the atmosphere." Is this a reasonable statement? Assume that gasoline is octane (molecular formula is C 8 H 18 ) and that it is burned completely to CO 2 and H 2 O in the engine of your car. Facts (or reasonable guesses) about your car's gas mileage, the density of octane, and other factors will also be needed.

Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

= 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

which can now be re-written as :

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

Answer:

The correct answer is option B.

Explanation:

Significant figures :These are figures in a number which expresses the value of the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Significant digits in the volume measurement 0.010 mL are:

= 2 significant figures

• All non-zero numbers are always significant.
• All zero’s preceding the first integers are never significant.
• All zero’s after the decimal point are always significant.

The volume measurement "0.010 mL" contains two significant digits. Significant digits are nonzero digits and trailing zeros in decimal numbers that contribute to the precision of the measurement.

In the volume measurement "0.010 mL," there are two significant digits. Significant digits are the digits in a measured quantity that contribute to its precision or accuracy. To identify significant digits, consider the following rules:

1. All nonzero digits are significant. In this case, "0" is considered a nonzero digit because it appears between two nonzero digits.

2. Leading zeros (zeros to the left of the first nonzero digit) are not significant. In "0.010 mL," the leading zero is not considered a significant digit.

3. Trailing zeros (zeros to the right of the last nonzero digit) in a decimal number are significant. So, the two trailing zeros in "0.010 mL" are significant.

Therefore, the measurement "0.010 mL" has two significant digits (the "1" and the "0"), and the correct answer is B) 2. These two significant digits represent the precision of the volume measurement.

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Answer:

(0,653±0,002) M of HNO₃

Explanation:

The reaction of standarization of HNO₃ with Na₂CO₃ is:

2 HNO₃ + Na₂CO₃ ⇒ 2 Na⁺ + H₂O + CO₂ + 2NO₃⁻

To obtain molarity of HNO₃ we need to know both moles and volume of this acid. The volume is (27,71±0,05) mL and to calculate the moles it is necessary to obtain the Na₂CO₃ moles and then convert these to HNO₃ moles, thus:

0,9585 g of Na₂CO₃ × ( 1 mole / 105,988 g) =

9,043×10⁻³ mol Na₂CO₃ × ( 2 moles of HNO₃ / 1 mole of Na₂CO₃) = 1,809×10⁻² moles of HNO₃

Molarity is moles divide liters, thus, molarity of HNO₃ is:

1,809×10⁻² moles / 0,02771 L = 0,6527 M of HNO₃

The absolute uncertainty of multiplication is the sum of relative uncertainty, thus:

ΔM = 0,6527M× (0,0007/0,9585 + 0,001/105,988 + 0,05/27,71) =

0,6527 M× 2,54×10⁻³ = 1,7×10⁻³ M

Thus, molarity of HNO₃ solution and its absolute uncertainty is:

(0,653±0,002) M of HNO₃

I hope it helps!

Answer:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄         →     Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄         →     Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.  

Molecular equation:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Final answer:

A double replacement reaction between barium chloride and sodium phosphate results in the formation of barium phosphate and sodium chloride.

Explanation:

The given chemical equation represents a double replacement reaction. The chemical reactants are barium chloride (BaCl2) and sodium phosphate (Na3PO4). In a double replacement reaction, the cations and anions of the two reactants switch places to form two new compounds.

So here is how the reaction would proceed: BaCl2 + Na3PO4 -> Ba3(PO4)2 + NaCl.

This translates to: Barium chloride reacts with sodium phosphate to form barium phosphate and sodium chloride.

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Answer:

hope it will help u

thank you