An object has a density of 1.75 g/mL. Will it float on water? Why?

Answers

Answer 1

Answer:

The object will not float in water because the density of the object is greater than that of water.

Explanation:

Density of object = 1.75 g/mL

Density of water = 1 g/mL

The Density of the object is 1.75 g/mL and that of water is 1 g/mL. This implies that the object is denser (i.e heavier) than water. Therefore, the object will not float in water, rather it will sink in water since it's density is greater than that of water.

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During her summer vacation, Sherry decides to go to the park to do some rollerblading (1). While rollerblading, she leaves her purse in her car (2). When comes back to her car, she realizes her lips are very dry (3). To remedy this, she gets her lip balm out of her purse (4). When she takes the cap off to apply it, some of it drips out of the tube and makes a mess all over her hands (5). A little irritated, she then goes to the bathroom and cleans the lip balm off of her hands (6).Which sentence from the scenario best shows Sherry's lack of understanding about the physical properties of her lip balm?

Note: Each number represents the sentence that comes before it in the scenario.

Answers

Answer: Sentence (4) is the correct answer.

Explanation:

Physical properties are defined as the properties that does not bring any change in chemical composition of a substance.

For example, density, volume, mass, shape, size etc are all physical properties.

So, when Sherry opens the cap of her lip balm tube then some of it drips because semi-solid state of lip balm has changed into liquid state due to absorption of heat from the car.

This means that there occurs change in only physical property of the lip balm.

Therefore, we can conclude that sentence from the scenario best shows Sherry's lack of understanding about the physical properties of her lip balm is that when she takes the cap off to apply it, some of it drips out of the tube and makes a mess all over her hands.

Sentence 4. If Sherry had known that the lip balm was melted she would have not even opened it up in the first place.

Which compound reacts with an acid to produce water and a salt(1) CH3Cl
(2) CH3COOH
(3)KCl
(3)KOH

Answers

KOH is the only base, and any neutralization reaction produces a salt and water

I'm not exactly sure which one but I do know that an acid and a base react in a aqueous solution to form water, so i would probably eliminate the ones that aren't aqueous solutions.

An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/mL; M = 62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent 50 % v/v (b) mass percent 52.7 % w/w (c) molarity M (d) molality m (e) mole fraction

Answers

Answer :

(a) The volume percent is, 50.63 %

(b) The mass percent is, 52.69 %

(c) Molarity is, 9.087 mole/L

(d) Molality is, 17.947 mole/L

(e) Moles fraction of ethylene glycol is, 0.244

Explanation : Given,

Density of ethylene glycol = 1.114 g/mL

Molar mass of ethylene glycol = 62.07 g/mole

Density of water = 1.00 g/mL

Density of solution or mixture = 1.070 g/mL

According to the question, the mixture is made by mixing equal volumes of ethylene glycol and water.

Suppose the volume of each component in the mixture is, 1 mL

First we have to calculate the mass of ethylene glycol.

$\text{Mass of ethylene glycol}=\text{Density of ethylene glycol}* \text{Volume of ethylene glycol}=1.114g/mL* 1mL=1.114g$

Now we have to calculate the mass of water.

$\text{Mass of water}=\text{Density of water}* \text{Volume of water}=1.00g/mL* 1mL=1.00g$

Now we have to calculate the mass of solution.

Mass of solution = Mass of ethylene glycol + Mass of water

Mass of solution = 1.114 + 1.00 = 2.114 g

Now we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=(2.114g)/(1.070g/mL)=1.975mL$

(a) Now we have to calculate the volume percent.

$\text{Volume percent}=\frac{\text{Volume of ethylene glycol}}{\text{Volume of solution}}* 100=(1mL)/(1.975mL)* 100=50.63\%$

(b) Now we have to calculate the mass percent.

$\text{Mass percent}=\frac{\text{Mass of ethylene glycol}}{\text{Mass of solution}}* 100=(1.114g)/(2.114g)* 100=52.69\%$

(c) Now we have to calculate the molarity.

$\text{Molarity}=\frac{\text{Mass of ethylene glycol}* 1000}{\text{Molar mass of ethylene glycol}* \text{Volume of solution (in mL)}}$

$\text{Molarity}=(1.114g* 1000)/(62.07g/mole* 1.975L)=9.087mole/L$

(d) Now we have to calculate the molality.

$\text{Molality}=\frac{\text{Mass of ethylene glycol}* 1000}{\text{Molar mass of ethylene glycol}* \text{Mass of water (in g)}}$

$\text{Molality}=(1.114g* 1000)/(62.07g/mole* 1kg)=17.947mole/kg$

(e) Now we have to calculate the mole fraction of ethylene glycol.

$\text{Mole fraction of ethylene glycol}=\frac{\text{Moles of ethylene glycol}}{\text{Moles of ethylene glycol}+\text{Moles of water}}$

$\text{Moles of ethylene glycol}=\frac{\text{Mass of ethylene glycol}}{\text{Molar of ethylene glycol}}=(1.114g)/(62.07g/mole)=0.01795mole$

$\text{Moles of water}=\frac{\text{Mass of water}}{\text{Molar of water}}=(1g)/(18g/mole)=0.0555mole$

$\text{Mole fraction of ethylene glycol}=(0.01795mole)/(0.01795mole+0.0555mole)=0.244$

Write balanced complete ionic equation for AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)

Answers

AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)
the coefficients are 1 because the equation is balanced already

The best method of developing a paragraph about a landscape would be _____.chronological
spatial
particular
contrast

Answers

The best answer is "spatial" because a landscape is by definition, a wide open area. A paragraph using the other three methods would not be the best.

Effects of warm tropical waters meeting with cool air.

Answers

The effect of warm tropical waters meeting with cool air is hurricane.

What is a hurricane?

A hurricane is formed when warm tropical water meet with air that is cool and humid. This creates a zone of pressure over the warm water causing the air to rotate.

Hence, the effect of warm tropical waters meeting with cool air is hurricane.

Learn more about hurricane:brainly.com/question/11891941

#SPJ2

A hurricane.. I believe

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