PHYSICS HIGH SCHOOL

A tennis ball is dropped from 1.16 m above theground. It rebounds to a height of 0.866 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s

Answers

Answer 1
Answer:

Final answer:

Using the principles of free fall motion, it can be determined that a tennis ball dropped from a height of 1.16 meters would hit the ground with a velocity of 4.8 m/s.

Explanation:

The objective here is to calculate the initial velocity of the tennis ball just before it hits the ground. This is a physics question related to free fall motion. We will use the equation of motion, v^2 = u^2 + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the distance. In our case, the initial velocity (u) is 0 because the ball is dropped, not thrown downwards.

The acceleration (a) is the acceleration due to gravity, which is -9.8 m/s² (it's negative because it acts downwards). The distance (s) will be the drop height, which is -1.16 m (it's negative because we're considering downwards as negative direction). Therefore, the equation becomes (v)^2 = 0 + 2*(-9.8 m/s²)*(-1.16 m). Solving this we get v = √(2*9.8*1.16) m/s = 4.8 m/s. So, the tennis ball hits the ground with a velocity of 4.8 m/s.

Learn more about Free Fall Motion here:

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Develop a mnemonic for branches of physics.

Answers

Answer:

  1. For physics, a common mnemonic is "My Very Earnest Mother Just Served Us Nine Pizzas" to help remember the order of the planets in our solar system (Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, Pluto).
  2. "SOH CAH TOA" - This helps remember the trigonometric ratios in a right triangle: Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse, Tangent = Opposite/Adjacent.
  3. "King Henry Died Drinking Chocolate Milk" - This is used to remember the metric system prefixes in order of magnitude: Kilo, Hecto, Deca, (Base Unit), Deci, Centi, Milli.
  4. "ROY G. BIV" - This helps remember the colors of the visible light spectrum: Red, Orange, Yellow, Green, Blue, Indigo, Violet.
  5. "F = ma" - This equation represents Newton's second law of motion, stating that Force equals mass times acceleration.
  6. "E = mc²" - This equation represents Einstein's theory of relativity, stating that Energy equals mass times the speed of light squared.
  7. "PEMDAS" - This mnemonic helps remember the order of operations in math: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
  8. "VIRUS" - This helps remember the formula for Ohm's Law: V (Voltage) = I (Current) x R (Resistance) or V = IR.
  9. "KE = 1/2 mv²" - This mnemonic represents the formula for kinetic energy: Kinetic Energy = 1/2 x mass x velocity squared.
  10. "PE = mgh" - This helps remember the formula for gravitational potential energy: Potential Energy = mass x gravitational acceleration x height.
  11. "F = G(m₁m₂/r²)" - This mnemonic represents Newton's law of universal gravitation, where F is the force between two masses, G is the gravitational constant, m₁ and m₂ are the masses, and r is the distance between the centers of the masses.
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A material has a net electric charge because it _____.A. has friction between electrons and protons

B. has the ability to create static discharge

C. has an excess or shortage of electrons.

D. has a large atomic nucleus

Answers

C. has an excess or shortage of electrons.

I need help ASAP.The average time that it takes for the car to travel the first 0.25m is_____

The average time to travel just between 0.25m and 0.50m is_____

Given the time taken to travel the second 0.25m section, the velocity would be____m/s

Answers

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

t=(2.24s+2.21s+2.23s)/(3)=2.227 s=2.23 s

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s =  0.92 s

So, the average time is

t=(0.92 s + 0.87 s + 0.92 s)/(3)=0.903 s=0.90 s

3. Velocity in the second 0.25 m section: 0.28 m/s

Explanation:

The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):

v=(d)/(t)=(0.25 m)/(0.90 s)=0.28 m/s

Answer:

1. 2.23

2. 0.90

3. 0.28

suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direction opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle

Answers

Answer:

p_r=(h)/(\lambda)

Explanation:

To find the momentum of the recoiling particle you can use the momentum formula for a photon:

p=(h)/(\lambda)

before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:

p_a=p_b\n\n(h)/(\lambda)-(m)/(2)v=0\n\np_r=(m)/(2)v=(h)/(\lambda)

where pr is the momentum of the recoiling particle.

The scientific unit of force is the _________.a. watt
b. joule
c. newton
d. kilogram

Answers

The correct answer is C

Answer:

The correct answer is c

Explanation:

Differentiate elastic potential energy and chemical potential energy​

Answers

Answer: Elastic energy is the energy store in a.. compacted spring; an extended elastic band; and a drawn bow.  

Chemical potential energy​​ is position of electrons in specific substance bonds that can be broken (energizes).

:

This stored energy is released and performs work when the elastic material reverts back to its original position. ... In comparison, chemical potential energy, is the energy released during the formation of chemical compounds.
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