When fractions are raised to a positive power there value does what

Answers

Answer 1

Answer:

Answer:

increases

Step-by-step explanation:

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What is the domain and range of this function?
{(1,3),(2,6),(3,9),(4,12)}

Answers

Answer:

Domain: {1, 2, 3, 4}

Range: {3, 6, 9, 12}

Step-by-step explanation:

In a function the domain represents the values of 'x' and the range represents the values of 'y'. For any given set of points, they are in the form of (x, y). So the domain would be the 'x' value in each point and the range is the 'y' value for each point:

Domain: {1, 2, 3, 4}

Range: {3, 6, 9, 12}

In a certain county, the number of charter schools is 6 less than twice the number of alternative schools. We know that there are 52 charter schools in the county. How many alternative schools are in the county?

Answers

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

So, 52 charter schools and the number is 6 less than the alternative schools doubled. In order to find the number of alternative schools, we need to reverse the equation. 52+6=58. That means 58 is twice the amount of alternative schools. 58/2 equals 29, therefore the answer is 29

How old am I if 400 reduced by 2 times my age is 244? (answer with steps)

Answers

400 reduced (minus) 2 times my age (2x) is 244 (= 244).

400 - 2x = 244 Subtract 400 from both sides
-2x = -156 Divide both sides by -2
x = 78

I am 78 years old.

What's an extraneous solution?

In your own words

Answers

Answer:

You get this solution while solving your problem but it still is not the correct answer to your question...

(I think)

a bag contains yellow marbles and blue marbles, 49 in total. the number of yellow marbles is 7 less than 3 times the number of blue marbles. how many yellow marbles are there ?

Answers

In short there are 35 yellow marbles and 14 blue marbles. For a long explanation, lol, keep on reading.

We know there are 49 marbles but we also know that there are only two colors, yellow and blue. So, we can assume that the yellow + blue marbles = 49. I'm going to use Y for yellow and B for blue. I'm going to rewrite the same equation with these variables. Y + B = 49. The problem continues with telling us that the yellow marbles are three times more than the blue ones with seven subtracted from that. I rephrased what they told us for better comprehension. So, we can assume that Y = 3B - 7. I gave Y that equation because of what the problem told us about Y. Continuing on, we know that Y + B = 49 and Y = 3B - 7. With this information, we can substitute Y into the Y + B = 49 equation. We now get, once we substitute Y into that equation, (3B - 7) + B = 49. We can add the B's together and get 4B - 7 = 49. Now, add the 7 and we get 4B = 56. Divide the B by 4 and we get B = 14. So, we now know what B is; we plug into the original equation to find Y. We plug in B = 14 into this equation, Y + B = 49. Once B is plugged in, Y + 14 = 49. Subtract 14 from 49 and we get Y = 35. Hope this helped. Good luck!

F(x)=(lnx)²/2x
give f '(x)=??

Answers

$f(x)=((lnx)^2)/(2x);\ D_f:x\in\mathbb{R^+}\n\nuse:\left[(f(x))/(g(x))\right]'=(f'(x)g(x)-f(x)g'(x))/([g(x)]^2)\n\nf'(x)=([(lnx)^2]'\cdot2x-(lnx)^2\cdot(2x)')/((2x)^2)=(*)\n\n\ [(lnx)^2]'=2lnx\cdot(1)/(x)=(2lnx)/(x)\n\n(2x)'=2\n\n(*)=((2lnx)/(x)\cdot2x-(lnx)^2\cdot2)/(4x^2)=(4lnx-2(lnx)^2)/(4x^2)=([4lnx-2(lnx)^2]:2)/(4x^2:2)=(2lnx-(lnx)^2)/(2x^2)$

$f(x)=((\ln x)^2)/(2x)\n\nf'(x)=(2\ln x\cdot (1)/(x)\cdot2x-(\ln x)^2\cdot2)/((2x)^2)\nf'(x)=(2\ln x(2-\ln x))/(4x^2)\nf'(x)=-(\ln x(\ln x-2))/(2x^2)$

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