MATHEMATICS HIGH SCHOOL

Find the area of this triangle.7 side one
5п/6 angle
9 side two
[?] square units
Round to the nearest hundredth.

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Simplify. Write each answer in scientific notation. 15. (6 ˣ 10^-5)^3 19. 3 ˣ 10^-2 / 8 ˣ 10^-1 20. 4.1 ˣ 10^-4 / 1.28 ˣ 10^-5 21. 1.91 ˣ 10^3 / 5 ˣ 10^-4

A printer printed 68 letters in 4 seconds. If it prints letters at a constant speed, it can print ______ letters in 30 seconds.

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510 letters. 68/4=17 which means 17 letters per second. You are trying to find out how many letters you can do in 30 seconds, so you just simply multiply 17 by 30 to get 510 letters. Hope this helped!

The answer is 510, Im glad I can help! Enjoy the test!

Six is 8% of what number

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6 is 8% of 75

Change the percentage into a decimal by dividing it over 100:

8 / 100 = 0.08

Divide:

6 / 0.08 = 75

if a scale map is 1 cm: 15 Km. find the actual distance corresponding to the scale map. 13) 2.5 cm 14) 0.2 cm 15) 15 cm 16) 4.6 cm

Answers

All you gotta do is multiply the cm by 15,
For 13) you'd do 2.5*15
14) 0.2*15 
15) 15*15
then for 16) 4.6*15

Let

x-------> distance in the map in cm

y-------> actual distance in Km

we know that

Scale\ Map=(x)/(y) \n \n Scale\ Map=(1)/(15)(cm)/(Km)

so

(x)/(y)=(1)/(15)

y=15x --------> equation 1

Part 13) find the actual distance corresponding to the scale map 2.5\ cm

In this problem we have

x=2.5\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*2.5=37.5\ Km

therefore

the answer part 13) is

the actual distance is 37.5\ Km

Part 14) find the actual distance corresponding to the scale map 0.2\ cm

In this problem we have

x=0.2\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*0.2=3\ Km

therefore

the answer part 14) is

the actual distance is 3\ Km

Part 15) find the actual distance corresponding to the scale map 15\ cm

In this problem we have

x=15\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*15=225\ Km

therefore

the answer part 15) is

the actual distance is 225\ Km

Part 16) find the actual distance corresponding to the scale map 4.6\ cm

In this problem we have

x=4.6\ cm

Substitute the value of x in the equation  1 to find the actual distance

y=15*4.6=69\ Km

therefore

the answer part 16

the actual distance is 69\ Km

Anthony, who is 2 meters tall, is standing on top of a skyscraper that is 1 km tall. How many meters is it from the top of Anthony's head to the bottom of the skyscraper?

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1002 meters. 1km= 1000 meters then add 2 meters. Hope this helped.

Compare the underlined numbers using ">,< or =". 841

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8>4 because eight is more than four and 4>1 so the answer is simply 8>4>1

A repeated initial sound is the basis of _____.

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A repeated initial sound is the basis of ALLITERATION.

Examples of alliteration are:
* She sells sea shells on the sea shore.
* Peter Piper picked a pack of pickled pepper.
* How many wood would the woodchuck chuck if the woodchuck could chuck wood?

Answer: A repeated initial sound is the basis of ALLITERATION.
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