6Which line has the steeper slope?
Line
4
has a steeper slope.
Line A
N
Line B
X
-6
4
-2.
2
4
6
-2
4
-6
6 Which line has the steeper slope? Line 4 has - 1

Answers

Answer 1
Answer: Line A has a slope of 4/3
Line B has a slope of 4/2
The answer is Line B
Answer 2
Answer:

Final answer:

The steeper line is determined by comparing the slopes of the two lines. The line with the larger slope value is the steeper line. However, the actual slopes of Line A and Line B in the question are not provided.

Explanation:

From the question, it seems like there are two given lines - Line A and Line B but no specific data is provided about their slopes. Therefore, with the information given, we can't determine which line has the steeper slope. Essentially, the steeper line would be the one with the higher slope value when represented in the form: y = mx + c, where 'm' is the slope. For instance, if Line A had an equation of y = 2x +1 and Line B an equation of y = 4x + 1, Line B's slope is steeper because it has a larger 'm' value compared to Line A.

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Related Questions

Is this correct ? .......................
THere are 7 people on the bus, and the bus picks up 4 additional people at each stop. How many stops will it take to have 31 people on the bus?
Negative 4 plus 8 equals
3 less than the quotient of 20 and x
If the domain of the square root function f(x) is x<=7, which statement must be true?7 is subtracted from the x-term inside the radical.The radical is multiplied by a negative number.7 is added to the radical term.The x-term inside the radical has a negative coefficient.

Write en rquation for the line passing through point (3,3) and parallel to the line whose equation is y=-(1)/(6)x+7

Answers

Answer:

y = - (1)/(6) x + (7)/(2)

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given the line with equation

y = - (1)/(6) x + 7 ← in slope- intercept form

with slope m = - (1)/(6)

Parallel lines have equal slopes , then

y = - (1)/(6) x + c ← is the partial equation of the parallel line

to find c, substitute the point (3, 3 )  for x/ y into the partial equation

3 = - (1)/(6) (3) + c = - (1)/(2) + c ( add(1)/(2) to both sides )

(6)/(2) + (1)/(2) = c , that is

c = (7)/(2)

y = - (1)/(6) x + (7)/(2)equation of parallel line

Final answer:

The equation of the line passing through point (3,3) and parallel to y = -(1/6)x + 7 is y = -(1/6)x + 3.5, which is achieved by knowing that parallel lines have the same slope and substituting the coordinates of the given point into the y = mx + b (slope-intercept form) and solving for the y-intercept 'b'.

Explanation:

The question asks for an equation of a line that is parallel to the equation y = -(1/6)x + 7 and also passes through the point (3,3). First, it's significant to understand that parallel lines share the same slope. Looking at the equation y = -(1/6)x + 7, we can see that the slope, or 'm' value, is -1/6. Therefore, the slope of our new line will also be -1/6. The conventional form of the equation for a line is y = mx + b where m is the slope and b is the y-intercept. Since we know the slope and have a point that lies on the line, we can substitute these values into this formula to solve for 'b'.

Here's how we do it:

First, substitute the point's coordinates into the equation for the line: 3 = (-1/6)*3 + b

This simplifies to: 3 = -1/2 + b

Then solving for 'b', we get: b = 3 + 1/2 = 3.5

Therefore, the equation of our new line that is parallel to the original line and passes through the point (3,3) is y = -(1/6)x + 3.5.

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Christopher looked at his quiz scores shown below for the first andsecond semester of his Algebra class.
Semester 1: 78, 91, 88, 83, 94
Semester 2: 91, 96, 80, 77, 88, 85, 92
Which statement about Christopher’s performance is correct?
(1) The interquartile range for semester 1 is greater than the
interquartile range for semester 2.
(2) The median score for semester 1 is greater than the median
score for semester 2.
(3) The mean score for semester 2 is greater than the mean score
for semester 1.
(4) The third quartile for semester 2 is greater than the third
quartile for semester 1.

Answers


The answer is (2) because median means the number halfway into the set and the median for semester1 is 88 and the median for semester 2 is 77
What you can do is find out everything mentioned until you find one that matches.
(1) Semester 1's IQR is 8, and semester 2's IQR is 12, so that statement is incorrect
(2) Semester 1's median is 88, and semester 2's median is 88, so that statement is incorrect
(3) Semester 1's mean is 86.8, and semester 2's mean is 87, so that statement is correct.
Since that is correct, the answer is (3).

Write 6y = x + 5 in standard form using integers. A. –x + 6y = 5
B. –6x + 6y = 30
C. -6x - 6y = 30
D. 6x - 6y = 30

Answers

I hope this helps you


-x+6y=5
Standard form is Ax+By=C, so with that knowledge, we can work with the problem to get it how we want it!

Our first step is to get x and y on the same side of the equals sign. To do that, we can subtract an x from both sides, turning 6y = x + 5 into -x +6y = 5. Lucky for us, this brings us straight to the answer, which is A) -x +6y = 5!

Find the product of the complex number and its conjugate.1 + 2i

1 - 4i
-3
5
1 + 4i

Answers

Answer:

The answer would be 5!

Step-by-step explanation:

You start with 1+2i and the conjugate of this would be 1-2i!

After that, in order to find the product, you multiply (1+2i)(1-2i)

You can use distribution or you can use the formula (a+b)(a-b)=a^2-b^2

Either way the answer will be 1-4i^2

i^2=-1 so you replace the i^2 in our equation with negative 1 and solve to get 5!

Hope this helped! <3

(8b2+6b-1) (8b2-8b+7)

Answers

=(8b2+6b+−1)(8b2+8b+7)
=(8b2)(8b2)+(8b2)(−8b)+(8b2)(7)+(6b)(8b2)+(6b)(−8b)+(6b)(7)+(−1)(8b2)+(−1)(−8b)+(−1)(7)
=64b4−64b3+56b2+48b3−48b2+42b−8b2+8b−7
Answer:
=64b4−16b3+50b−7

The sum of two numbers is 68. The larger number is 16 more than the smaller number. What are the numbers?

Answers

Answer:

x = 26

Step-by-step explanation:

68=x +(16+x) and if you plug in 26 it is 68