What is 2/4 + 6/8 + 2/4 + 15/24 + 7/8

Answers

Answer 1

Answer:

13/4

Step-by-step explanation:

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Evaluate inverse functions PLEASE HELPPP!!!

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use photomath its are helpful

Tell me the answer please

Answers

Answer:

(-4,-3)

Step-by-step explanation:

just use rise and run slope

you run-4 units x and rise y -3

When the equation a – bx = cx + d is solved for x, the result is x = .Use the general solution to solve 5 – 6x = 8x + 17.

Answers

The value of x in the equation a – bx = cx + d is = a - d / c + b

The value of x in the equation 5 – 6x = 8x + 17 is - 6 / 7

a - bx = cx + d

add bx to both sides of the equation

a - bx + bx = cx + bx + d

a = cx + bx + d

subtract d form both sides of the equation

a - d = cx + bx + d - d

a - d = cx + bx

Distributive law:

using distributive law on the right side of the equation

a - d = x (c + b)

divide both sides by (c + b)

Therefore,

x = a - d / c + b

Let's use the same method to solve 5 – 6x = 8x + 17

5 – 6x = 8x + 17

add 6x to both sides

5 – 6x + 6x= 8x + 6x + 17

5 = 14x + 17

subtract 17 from both sides

5 - 17 = 14x + 17 - 17

-12 = 14x

divide both sides by 14

x = -12 / 14

x = - 6 / 7

learn more on equations here: brainly.com/question/7838122

Somebody help please ASAP!

Answers

Answer: 4th box

Step-by-step explanation:

Please someone help me to prove this.

Answers

Answer: see proof below

Step-by-step explanation:

Use the Power Reducing Identity: sin² Ф = (1 - cos 2Ф)/2

Use the Double Angle Identity: sin 2Ф = 2 sin Ф · cos Ф

Use the following Sum to Product Identities:

$\sin x - \sin y = 2\cos \bigg((x+y)/(2)\bigg)\sin \bigg((x-y)/(2)\bigg)\n\n\n\cos x - \cos y = -2\sin \bigg((x+y)/(2)\bigg)\sin \bigg((x-y)/(2)\bigg)$

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \qquad (\sin^2A-\sin^2B)/(\sin A\cos A-\sin B \cos B)$

$\text{Power Reducing:}\qquad (\bigg((1-\cos 2A)/(2)\bigg)-\bigg((1-\cos 2B)/(2)\bigg))/(\sin A \cos A-\sin B\cos B)$

$\text{Half-Angle:}\qquad \qquad (\bigg((1-\cos 2A)/(2)\bigg)-\bigg((1-\cos 2B)/(2)\bigg))/((1)/(2)\bigg(\sin 2A-\sin 2B\bigg))$

$\text{Simplify:}\qquad \qquad (1-\cos 2A-1+\cos 2B)/(\sin 2A-\sin 2B)\n\n\n.\qquad \qquad \qquad =(-\cos 2A+\cos 2B)/(\sin 2A - \sin 2B)\n\n\n.\qquad \qquad \qquad =(\cos 2B-\cos 2A)/(\sin 2A-\sin 2B)$

$\text{Sum to Product:}\qquad \qquad (-2\sin \bigg((2B+2A)/(2)\bigg)\sin \bigg((2B-2A)/(2)\bigg))/(2\cos \bigg((2A+2B)/(2)\bigg)\sin \bigg((2A-2B)/(2)\bigg))$