Please answer asap.........
please answer asap......... - 1

Answers

Answer 1
Answer:

Answer:

1.4 i would wait for someone else to answer it I'm not sure

Step-by-step explanation:


Related Questions

Help me please!!!!!!!!!!!!!
What is the correct answer can you guys help me I really need help on this?? Please
Find the general solution of the following equation: y'(t) = 3y -5
Factor the expression X^2-9
What is the area of the circle above? (

(2 - (- 2)²)² +5 · ( -4)

Answers

Answer:

-164

Step-by-step explanation:

(2 - (- 2)²)² +5 · ( -4)

(2 + 2²) ² +5 · ( -4)

(2 + 2 + 2)² +5 · ( -4)

6² +5 · ( -4)

6 · 6 + 5 · -4

36 + 5 · -4

41 · -4

-164

Hope this helped!

Have a supercalifragilisticexpialidocious day!

Please Help!!In 2010, Martin paid $5,518.00 in Social Security tax. The SS tax rate was 6.2%. What was Martin's taxable income in 2010?

Answers

Answer:

$890 or it's $34211.6

Step-by-step explanation:

you divide 5518 by 6.2% or you multiply them

Please help fast, thanks.

Answers

I believe it is m < 5 I could be wrong sorry.

72. Which best describes the polynomial -5x^3?Third degree binomial


First degree trinomial


Third degree monomial


Third degree binomial

Answers

-5x^3?

This is a third degree monomial

It has one term so it is a monomial

the exponent is to the power of 3 so it is third degree

Answer:

Third degree monomial.

Step-by-step explanation:

because it only has one number and is to the third degree

Write the expanded form 0.45 in this way using fractions and using decimals

Answers

Using fractions, 0.45 can be written as (3)/(10)+ (3)/(20). Using decimals, 0.45 can be written in the form as 0.30 + 0.15.

What is Decimal Numbers?

Decimal number system is applicable for both integers as well as non integers. Decimal number include a whole number part and a decimal part separated using decimal point.

Fractions are the numbers which are part of a whole.

All decimal numbers can be written as fractions and fractions can be written in the form of decimal numbers.

The given number is 0.45.

0.45 can be written as (45)/(100).

(45)/(100) can be expanded in various ways like (40 + 5)/100, (42 + 3)/100 and so on.

(45)/(100) can be written in one of the form as (30)/(100) + (15)/(100).

When simplified, (30)/(100)simplified to (3)/(10)and (15)/(100) simplified to (3)/(20).

So 0.45 = (3)/(10)+ (3)/(20).

Now, in the decimal form, (3)/(10)= 0.3 and (3)/(20)= 0.15

So, 0.45 = 0.3 + 0.15

Hence 0.45 can be expanded in the fractional form as  (3)/(10)+ (3)/(20)and in the decimal form as 0.3 + 0.15.

To learn more about Decimals, click :

brainly.com/question/29765582

#SPJ2

Answer:

0.4 + 0.05= 0.45

FRACTION FORM:

4/10+ 5/100= 0.45

Step-by-step explanation:

Hope this helps!! Tell me if I'm wrong! :)

At $ 0.49 per​ bushel, the daily supply for wheat is 409 ​bushels, and the daily demand is 589 bushels. When the price is raised to $ 0.85 per​ bushel, the daily supply increases to 529 ​bushels, and the daily demand decreases to 229 bushels. Assume that the​ price-supply and​ price-demand equations are linear.(A) Find the supply equation.
(B) Find the demand equation.
(C) Find the equilibrium price and quantity

Answers

Answer:

(A) Find the supply equation.

Qs = 245.67 + 333.33Ps

(B) Find the demand equation.

Qd = 1079 - 1000Pd

(C) Find the equilibrium price and quantity

Price P = $0.625

Quantity Q = 454 bushels

Step-by-step explanation:

The demand equation is of the form;

Q = a - bP

The supply equation is of the form;

Q = c + eP

We need to determine the values of a,b,c,d;

At $ 0.49 per​ bushel, the daily supply for wheat is 409 ​bushels, and the daily demand is 589 bushels

589 = a - b(0.49) ........1

409 = c + e(0.49) .........2

When the price is raised to $ 0.85 per​ bushel, the daily supply increases to 529 ​bushels, and the daily demand decreases to 229 bushels;

229 = a - b(0.85) ........3

529 = c + e(0.85). .......4

Subtract equation 3 from 1

589-229 = b(0.85) - b(0.49)

360 = b(0.36)

b = 360÷0.36

b = 1000

Using equation 1

589 = a - 1000(0.49)

a = 589+490 = 1079

Subtract equation 2 from 4

529-409= e(0.85) - e(0.49)

120 = 0.36e

e = 120/0.36

e = 333.33

Using equation 2

409 = c + 333.33(0.49)

c = 409 - 333.33(0.49)

c = 245.67

Therefore the demand equation is;

Qd = 1079 - 1000Pd

The supply equation is ;

Qs = 245.67 + 333.33Ps

The equilibrium price is at Qs = Qd and Ps = Pd

1079-1000P = 245.67 +333.33P

P = (1079-245.67)/(1000+333.33)

P = $0.625

Qd = 1079 - 1000(0.625)

Qs = Qd = 454