Jill needs to create a chart for technology club that shows what percentage of total students in the school play video games. Which chart or graph should she use? Bar graph Column chart Line graph Pie chart

Answers

Answer 1
Answer:

Answer:

It's pie chart because it shows the percentage of multiple things.

Explanation:

And I did an exam aced it and got this question right.


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________________________ is an information system that stores user data in many different geographical locations and makes that data available on demand.

Answers

Answer:

CDN(content delivery network)

Explanation:

Content delivery network(CDN) which can as well be regarded as Content Distribution Network helps in acheiving high website performance, it essential in reduction of latency, through making the time a request is made using a website to when the website is fully loaded to be short and Minimal. It important in a situation whereby there is traffic loads from the users as well as server. It should be noted that CDN

is an information system that stores user data in many different geographical locations and makes that data available on demand. CDN's usefulness is also found in Cloud computing network such as Software as a service(SaaS). Google doc is an example.

Technician A says a 2:1 gear ratio doubles the amount of torque. Technician B says a 2:1 gear ratio reduces the speed by half. Which technician is correct? A. Technician A only
B. Neither Technician A nor Technician B
C. Both Technician A and Technician B
D. Technician B only

Answers

b, a 2 to 1 increases doubles speed and reduces speed by half

A vowel word is a word that contains every vowel. Some examples of vowel words are sequoia, facetious, and dialogue. Determine if a word input by the user is a vowel word.

Answers

Answer:

vowels = ("a", "e", "i", "o", "u")

word = input("Enter a word: ")

is_all = True

for c in vowels:

   if c not in word:

       is_all = False

if is_all == True:

   print(word + " is a vowel word.")

else:

   print(word + " is not a vowel word.")

Explanation:

Initialize a tuple, vowels, containing every vowel

Ask the user to enter a word

Initially, set the is_all as True. This will be used to check, if every vowel is in word or not.

Create a for loop that iterates through the vowels. Inside the loop, check if each vowel is in the word or not. If one of the vowel is not in the vowels, set the is_all as False.

When the loop is done, check the is_all. If it is True, the word is a vowel word. Otherwise, it is not a vowel word.

#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The function will look for the search string within the #target string. # #The function should return a string representing where in #the target string the search string was found: # # - If search string is at the very beginning of target # string, then return "Beginning". For example: # string_finder("Georgia Tech", "Georgia") -> "Beginning" # # - If search string is at the very end of target string, # then return "End". For example: # string_finder("Georgia Tech", "Tech") -> "End" # # - If search string is in target string but not at the # very beginning or very end, then return "Middle. For # example: # string_finder("Georgia Tech", "gia") -> "Middle" # # - If search string is not in target string at all, then # return "Not found". For example: # string_finder("Georgia Tech", "Idaho") -> "Not found" # #Assume that we're only interested in the first instance #of the search string if it appears multiple times in the #target string, and that search string is definitely #shorter than target string. # #Hint: Don't be surprised if you find that the "End" case #is the toughest! You'll need to look at the lengths of #both the target string and the search string. #Write your function here!

Answers

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End"#if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

In open addressing with linear probing we must consider how to encodeA. Occupies positions

B. Available positions

C. All other answers

D.empty positions

Answers

Answer: B)Available positions

Explanation:Open addressing is the addressing method for the components that are present in the hash table. collision are controlled and managed by this process. The total count of keys is less or equal to the size of table.

Linear probing is the mechanism that helps in controlling of the collision happening by the process of key collection maintenance by encoding of the available positions of the element in the hash table.So,the correct option is option(B).

Write a method called allDigitsOdd that returns whether every digit of a positive integer is odd. Return true if the number consists entirely of odd digits (1, 3, 5, 7, 9) and false if any of its digits are even (0, 2, 4, 6, 8). For example, the call allDigitsOdd(135319) returns true but allDigitsOdd(9145293) returns false.

Answers

Answer:

Sample output:

Enter integer 3232423

true

Enter integer 12131231

false

Explanation:

Above is the output of the program and for the solution check the screenshots attach to understand clearly the program.

Thanks