PHYSICS HIGH SCHOOL

While standing on a balcony a child drops a penny. The penny lands on the ground floor 1.5 s later. How fast was the penny traveling vertically when it struck the ground floor? *The height of the balcony is 11.025 meters

Answers

Answer 1

Answer:

14.7 m/s.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 1.5 s

Acceleration due to gravity (g) = 9.8 m/s².

Height = 11.025 m

Final velocity (v) = 0 m/s

Initial velocity (u) =?

We, can obtain the initial velocity of the penny as follow:

H = ½(v + u) t

11.025 = ½ (0 + u) × 1.5

11.025 = ½ × u × 1.5

11.025 = u × 0.75

Divide both side by 0.75

u = 11.025/0.75

u = 14.7 m/s

Therefore, the penny was travelling at 14.7 m/s before hitting the ground.

Related Questions

View the image below and answer the question.The illustration above is an example of which of Newton's Laws?aUniversal Law of GravitationbNewton's Second LawcNewton's First LawdNewton's Third Law
A juggler throws a bowling pin straight up with an initial speed of 9.20m/s. How much time elapses before the pin reaches the juggler's hands?
Identify some common fuels
A rock containing valuable minerals that can be mined is called A. An inorganic compound B. An igneous rock C. An ore D. An organic compound
Which mass extinction occurs the slowest? A. Asteroids B. Climate Change C. Volcanic Eruption

Evelyn learns that a sound wave can be recorded electronically as an analog signal or as a digital signal. She investigates these two signal types. She records her voice using a tape recorder, which uses an analog signal to produce sound when played back. She also records her voice using a computer, which uses a digital signal to produce sound when played back. Evelyn replays each recording 100 times.a. Describe a difference that Evelyn would most likely hear between the two recordings after being replayed 100 times.

b. Explain why the two recordings would sound different after being replayed 100 times.

Answers

Answer:

can u help me with this too, i currently have it in an assignment and i dont know the answer

Explanation:

Final answer:

Analog signals physically degrade each time they are played, causing a decrease in sound quality. Digital signals, however, will not experience any quality decline when being replayed multiple times because they are stored in binary form.

Explanation:

a. After being replayed 100 times, a major difference that Evelyn would most likely hear between the two recordings is that the analog recordings might have a loss in sound quality, and are likely to sound a bit more worn down or degraded. The digital recording, on the other hand, would sound just as it did the first time, having a high quality, and no loss of detail.

b. The reason for the difference in degradation is largely because of the nature of the two types of signals. An Analog signal is continuous and is an accurate representation of the sound wave as it varies in amplitude over time. However, an analog recording such as a tape, physically degrades each time it is played. Noise begins to rise while a decline in high-frequency content seems to appear. Digital signals, which are quantized representations of those same sound waves, do not degrade over time, because information is essentially coded in binary form. So, unless the file itself is damaged or corrupted, playing it back any number of times won't diminish its quality.

Learn more about Analog vs Digital Signals here:

brainly.com/question/34840075

#SPJ3

Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of mass 2m hanging from it. Part A If the energies of the two systems are the same, what is the ratio of the oscillation amplitudes?

Answers

Answer:

$(A_1)/(A_2)=1$

Explanation:

given,

two identical spring have identical spring constant

mass 'm' is hanging on one spring and mass of '2m' on another wall.

energy of the two system is same

energy of the system having mass 'm'

$E = (1)/(2)m\omega_1^2A_1^2$

energy of the system having mass '2m'

$E = (1)/(2)(2m)\omega_1^2A_1^2$

now, Energy are same

$(1)/(2)m\omega_1^2A_1^2= (1)/(2)(2m)\omega_1^2A_1^2$

$(A_1^2)/(A_2^2)=(2\omega_2^2)/(\omega_1^2)$

we know $k = mw^2$

$(A_1)/(A_2)=\sqrt{\frac{2(k)/(m_2)}{{(k)/(m_1)}}$

$(A_1)/(A_2)=\sqrt{(2m_1)/(m_2)}$

$(A_1)/(A_2)=\sqrt{(2m)/(2m)}$

$(A_1)/(A_2)=1$

Notes on electric bulb

Answers

The question describes a hazardous practice that should be avoided in the home.
Areas of the glass having ink, marker, or Post-its on them can cause uneven heating
of the glass, leading to uneven expansion and, sooner or later, fracture of the glass.

Describe briefly how fossil fuels were formed

Answers

Fossil fuels are formed by organic remains that have been buried under rock. "Organic remains" can include animals and plants (think of oil and dinosaurs).

Fossil fuels were formed by the compression of dead plants and animals due to high pressure and temperature.
Some fossil fuels are coal, petroleum and natural gas

Using echos to find an object

Answers

Using echoes to find and object is called echo location.

The answer is Echolocation

5. You head downstream on a river in an outboard.The current is flowing at a rate of 1.50 m/s. After
30.0 min, you find that you have traveled 24.3 km.
How long will it take you to travel back upstream to
your original point of departure?

Answers

Answer:

hope this helps you're welcome

Final answer:

The time it will take to travel back upstream to your original point of departure is approximately 38.6 minutes, as determined by calculating the boat's speed against and with the river current.

Explanation:

This question involves understanding the concepts of velocity, time, and distance in physics. It relates to a situation where you are traveling downstream on a river with a certain current and later traveling back upstream against the current.

Firstly, we need to understand that the speed of the boat when it is moving downstream is its own speed plus the speed of the current. Given that you covered 24.3 km in 30 minutes (or 0.5 hours), we can calculate the boat's downstream speed as 24.3 km / 0.5 hours = 48.6 km/h.

The speed of the current is given as 1.50 m/s, which is approximately 5.4 km/h. So, the boat's own speed would be 48.6 km/h (downstream speed) - 5.4 km/h (current speed) = 43.2 km/h.

When heading back upstream, the boat's effective speed would be its own speed minus the speed of the current, which is 43.2 km/h - 5.4 km/h = 37.8 km/h. Now, to find out the time it would take to travel back upstream to the original point, we divide the total distance by the boat's effective speed, i.e., 24.3 km / 37.8 km/h = approximately 0.643 hours or around 38.6 minutes.