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A person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s2. What is the velocityof the stroller after it has traveled 6.32 m?

Answers

Answer 1

Answer:

You're going to use the constant acceleration motion equation for velocity and displacement:

(V)final² = (V)initial²+2a(dx)

Given:

a=0.500m/s²

dx=6.32 m

(V)intial=0m

(V)final= UNKNOWN

(V)final= 2.51396m/s

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in the demolition of an old building,a 1,300 kg wrenching ball hits the building at 1.07m/s^2.Calculate the amount of force at which the wrecking ball strikes the building

Answers

Answer:

1391 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1300 × 1.07

We have the final answer as

1391 N

Hope this helps you

A runner first runs a displacement A of 3.20 km due south, and then a second displacement B that points due east. (a) The magnitude of the resultant displacement A + B is 5.38 km. What is the magnitude (in m) of B?

Answers

Answer: 4,438.96m

Explanation:

(kindly find attachment below)

From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.

By using phythagoras theorem

H² = O² + A²

(5.38)² = (3.20)² + B²

28.944 = 10.24 + B²

B² = 28.944 - 10.24

B² = 18.7044

B = √18.7044

B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m

Answer:

B = 4325 m

Explanation:

Resolving the displacement into x and y components.

Let north = positive y component

East = positive x component

So,

Rx = B

Ry = -3.20 km

Magnitude of the resultant displacement is

R = √(B^2 + (-3.20)^2)

R is given as R = 5.38 km

Making B the subject of formula;

B = √(R^2 - (-3.20)^2)

B = √(5.38^2 - (-3.20)^2)

B = 4.325 km

B = 4325 m

What is the angular width of a person's thumb viewed at arm's length? Assume that the width of the thumb is 17.3 mm and that the distance between the eyes and the thumb is 71.9 cm. Use the small-angle approximation and then convert the answer to degrees.

Answers

Answer:

$\theta_(degrees) =0.024\°=0\°1'26.62''$

Explanation:

To solve the problem it is necessary to take into account the concepts related to arc length and the radius that make up the measurements of an angle.

An angle is given by the length of arc displaced as a function of the radius, that is

$\theta = (Arc_(length))/(Radius)$

$\theta = (17.3*10^(-3))/(71.9*10^(-2))$

$\theta = 0.02406rad$

360° is equal to do $2\pi$ rad, therefore:

$\theta_(degrees) = 0.02406rad *((180\°)/(2\pi rad))$

$\theta_(degrees) =0.024\°=0\°1'26.62''$

During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between two fence posts. The limb exerts a downward force of 176 N on the wire. The left section of the wire makes an angle of 12.5° relative to the horizontal and sustains a tension of 413 N. Find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Answers

Answer:

a. 12.12°

b. 412.04 N

Explanation:

Along vertical axis, the equation can be written as

T_1 sin14 + T_2sinA = mg

T_2sinA = mg - T_1sin12.5 ....................... (a)

Along horizontal axis, the equation can be written as

T_2×cosA = T_1×cos12.5 ......................... (b)

(a)/(b) given us

Tan A = (mg - T_1sin12.5) / T_1 cos12.5

= (176 - 413sin12.5) / 413×cos12.5

A = 12.12 °

(b) T2 cosA = T1 cos12.5

T2 = 413cos12.5/cos12.12

= 412.04 N

Answer:

Magnitude - 11.83 Degree

Direction - 422.42 N

Explanation:

Given data:

Downward force on wire 176 N

Angle made by left section of wire 12.5 degree with horizontal

Tension force = 413 N

From figure

Applying quilibrium principle at point A

The vertical and horizontal force is 0

then we have

$Tcos\theta = 413 N$ ........1

$176 = 413 sin 12.5 + Tsin\theta$ .......2

$Tsin\theta = 176 - 89.39 = 86.6$ .......3

divide equation 3 by 1

we get

$\theta = tan^(-1) (0.2096)$

$theta = 11.83^o$ ...........4

from equation 3 and 4

$T = (86.6)/(sin 11.83)$

T = 422.42 N

Please give the answer

Answers

Answer:

Explanation:

just took it e2020

Answer:

60%

Explanation:

efficiency= useful/input x 100%,

Here, kinetic energy is useful for food processor (i.e. spinning blades)

600J/1000J=60%

The minimum charge on any object cannot be less than

Answers

Answer:

1.6 x 10^{-19} Coulombs

Explanation:

In Physics, the standard unit of measurement of a charge is Coulombs and it's denoted by C. Also, the symbol for denoting a charge is Q.

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

The minimum charge on any object such as an electron cannot be less than 1.6 x 10^{-19} Coulombs and it's usually referred to as the fundamental unit of charge.

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