Ryan left the science museum and drove south at 53 km/h. How far has he traveled after 8 minutes
Answers
Answer:
7 km
Explanation:
53 km in 1 hour/ 60 minutes. .89 km a minute.
Related Questions
Thermal conductors don’t have to be hot to transfer heat. According to Ch.16, explain a situation when an ice cube would still transfer heat to another object it is in contact with.
The formula for speed is v = s/t. a. True b. False
The particles of a solid are linked together in a network. if the temperature of the solid increases, the particles gain energy. if they gain enough energy, the particles can break free of the network. then, they are able to move around more freely.in the event described above, what kind of change is taking place?
Which particle is used as a beam to treat cancer?
Answers
Answer:
Osmosis and cellular transport
Explanation:
Answers
Answers
Answer:
Plasma
Explanation:
Plasmais the most common because plasma is a gas that has been energized to the point that some of the electrons break
Answers
The buoyancy of an object depends on its density relative to the density of the fluid it's placed in, typically water in everyday scenarios. When an object is placed in a fluid (like water), it will float if its average density is less than that of the fluid. In other words, if the object is less dense than the fluid, it will float.
In this case, both pieces of wood have the same density of 0.90 grams per milliliter (g/ml), which is less dense than water. Therefore, both the 1-pound piece of wood and the 10-pound piece of wood will float in water.
However, it's important to note that the buoyant force acting on these objects will be the same for a given volume of wood because they have the same density.
The 10-pound piece of wood will displace more water (have a larger volume) to support its weight, while the 1-pound piece of wood will displace less water (have a smaller volume) to support its weight. The 10-pound piece of wood will have more of its volume submerged compared to the 1-pound piece due to the weight difference, but both will float.
(b) What will the voltmeter read if the dielectric is now pulled partway out so it fills only one-third of the space between the plates?
Answers
(A) 3.9
When a dielectric is inserted between the plates of a capacitor, the capacitance of the capacitor increases according to the equation:
(1)
where
C' is the final capacitance
k is the dielectric constant
C is the original capacitance
The capacitance is inversely proportional to the to voltage across the plates:
(2a)
where Q is the charge stored and V the potential difference across the plates. We can rewrite C' (the capacitance of the capacitor filled with dielectric) as
(2b)
Substituting (2a) and (2b) into (1), we find
(3)
where
V = 45.0 V is the original voltage across the capacitor
V' = 11.5 V is the voltage across the capacitor filled with dielectric
Solving for k,
(B) 22.8 V
When the dielectric is partially pulled away, the system can be assimilated to a system of 2 capacitors in parallel, of which one of them is filled with dielectric and the other one is not.
Keeping in mind that the capacitance of a parallel-plate capacitor is proportional to the area of the plates:
and in this case, the area of the capacitor filled with dielectric is just 1/3 of the total, we can write:
where C1 is the capacitance of the part non-filled with dielectric, and C2 is the capacitance of the part filled with dielectric. The total capacitance of the system in parallel is
Substituting,
This is equivalent to a capacitor completely filled with a dielectric with dielectric constant k=1.97. Therefore, using again eq.(3), we find the new voltage:
False