This is my question ​
this is my question ​ - 1

Answers

Answer 1
Answer:

Answer:

c

Step-by-step explanation:

Answer 2
Answer:

Answer:

Technically it is supposed to be 37.7 but in this case, the answer is C: 37.68 cm

Step-by-step explanation:

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B2+10b+25/b29-9 . B+3/B+5

Answers

b4 + b3 - 45b2 - 27b + 25—————————————————————————b2
the answer is (b+5)(b+5)/b(29-5)

I need help ASAP pic below

Answers

Answer:

Step-by-step explanation:

2) ∠A + ∠B = 146       {Exterior angle theorem}

5y + 3 + 4y + 8 = 146

5y + 4y + 3 + 8 = 146           {combine like terms}

         9y + 11 = 146

               9y = 146 -11

               9y = 135

                 y = 135/9

y = 15

3) m∠A = 5y + 3

              = 5*15 + 3

              = 75 + 3

A = 78

4) m∠B = 4y + 8

            = 4*15 + 8

            = 60 + 8

      m∠B = 68

5) m∠ACB + m∠A + m∠B = 180   {Angle sum property of triangle}

 m∠ACB  + 78 + 68 = 180

           m∠ACB + 146 = 180

                       m∠ACB = 180 - 146

                      m∠ACB = 34

6. How can you use the value of x to show that KL = 15?

Answers

Answer:

wherever the variable (x) is, replace the variable with whatever value it has and solve the equation.

Step-by-step explanation:

If amanda hikes at an average speed of 2.72 miles per hour, how long will it take her to hike 6.8 miles

Answers

i hope this helps you

What axis is the axis of symmetry on?

Answers

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.

If cos Θ = negative two over five and tan Θ > 0, what is the value of sin Θ? negative square root / 21 negative square root / 21 over 5 square root / 21 over 5 square root of 21 over 2

Answers

Answer:  The correct option is (B) negative square root 21 over 5.

Step-by-step explanation:  Given that for an angle \theta,

\cos \theta=-(2)/(5),~~~\tan \theta>0.

We are to find the value of \sin \theta.

We know that

Cosine is negative in Quadrant II and Quadrant III.

Tangent is positive in Quadrant 1 and Quadrant III.

So, the given angle \theta lies in the Quadrant III.

We will be using the following trigonometric identity:

\cos^2\theta+\sin^2\theta=1.

We have

\cos \theta=-(2)/(5)\n\n\n\Rightarrow √(1-\sin^2\theta)=-(2)/(5)\n\n\n\Rightarrow 1-\sin^2\theta=(4)/(25)\n\n\n\Rightarrow \sin^2\theta=1-(4)/(25)\n\n\n\Rightarrow \sin^2\theta=(21)/(25)\n\n\n\Rightarrow \sin \theta=\pm(√(21))/(5).

Since the angle \theta lies in Quadrant III and sine is negative in that quadrant, so

\sin\theta=-(√(21))/(5).

Thus, option (B) is correct.

Answer:

sin\theta=-(√(21))/(5) Option B is the correct option.

Step-by-step explanation:

It is given in the question cos\theta =-(2)/(5) and tan\theta >0

We have to calculate the value of sin\theta

We can see in the figure attached since cos∅ = -2/5

Here negative sign is showing that angle theta is lying either in quadrant 2nd or 3rd.

And tan\theta >0 is showing as angle is either in quadrant 1 or 3rd.

Therefore it is confirm that angle is lying in quadrant 3 where sine is always negative.

Thereforesin\theta=-(√(21))/(5) will be the answer.