MATHEMATICS HIGH SCHOOL

Factor completely 9r^3-72r^2

Answers

Answer 1
Answer:

Answer:

9r²(r - 8)

Step-by-step explanation:

Step 1: Write expression

9r³ - 72r²

Step 2: Factor out 9

9(r³ - 8r²)

Step 3: Factor out r²

9r²(r - 8)

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What is the greatest common factor 15abc^2 and 25a^3bc
1. The price of gas has increased over time due to inflation and other factors. Assume that the equation y = 1.26(1.10) x represents the price of gas for the years after 2000.Using this equation, fill in the following T-table for the years 2000, 2002, 2004, 2006, 2008, and 2010. Use X = 0, 2, 4, 6, 8, and 10 to represent these years (the number of years after 2000). Round your answers to the nearest cent.

What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m

Answers

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius - 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m² = 6 m( 2 x radius - 6 m ) 
100 m² = 12 m x radius - 36 sq m 
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
11.333 m = radius 

the area beneath an arc: 

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h² ).

r² = (11.333 m)² = 128.444 m² 
r - h= 11.333 m - 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m 

Area = 138.828 m² - 53.333 m² 

Area = 85.4 m²

Garland started the week with an odometer reading of 58,240 miles and a full tank. He ended the week with an odometer reading of 58,615, and he re-filled the tank with 15 gallons of gas. How many miles per gallon did he get to the nearest whole number? (Points : 2) 25
24
23
22

Answers

Answer:

A. 25.

Step-by-step explanation:

We have been given that Garland started the week with an odometer reading of 58,240 miles and a full tank. He ended the week with an odometer reading of 58,615, and he re-filled the tank with 15 gallons of gas.

To find the mileage for Garland's bike we will divide total distance traveled by total used fuel.

\text{Mileage}=\frac{\text{Total distance}}{\text{Total amount of fuel}}

\text{Mileage}=\frac{\text{58,615 miles - 58,240 miles}}{\text{15 gallons}}

\text{Mileage}=\frac{\text{375 miles}}{\text{15 gallons}}

\text{Mileage}=\frac{\text{25 miles}}{\text{ gallon}}

Therefore, Garland get a mileage of 25 miles per gallon and option A is the correct choice.
your answer is 25 miles per gallon!

Solve the compound inequality. y - 3 > 5 OR y + 3 < -2

Answers

Answer: y < -5 or y > 8

Step-by-step explanation:

y-3>5\quad \text{or}\quad y+3<-2\n\underline{\ \ \ +3}\ \underline{\ +3}\qquad \underline{\quad \ \ -3}\ \underline{\ \ \ -3}\ny\quad \ \ >8\quad \text{or}\quad y\quad \ \ <-5

Graph:  ←---------o -1            8 o------------→

Interval Notation: (-∞, -5) ∪ (8, ∞)

What's the answer ? ..... ​

Answers

Answer:

B) 10m^3(m^3+2)

Step-by-step explanation:

Hope this helps
Answer: B.
Explanation: when you distribute 10m^3 and multiply it to just m^3, you add the exponents which would give you 10m^6 then 10m^3 multiplied by just 2 will give you 20m^3. Which all together will be the initial problem 10m^6+20m^3

The type of drink you purchase depends on the buttom you push so you would say that the buttoms ( a,b,c,d,e, and f) qre possible values of the

Answers

i don’t know what to do with myself anymore i just want to be

A science class planted a tree in the school courtyard that was 6 inches tall. It is growing 4 inches eachweek. Write a function rule for the height, h, of the tree based on the weeks, w, since it was planted.
(1 point)
h = 6w + 4
h = 4w + 6
h = 4w
h = 4w – 6

Answers

h = 6 + 4*weak

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