EXAMPLE: If the function f(x) = 2x==x+4 is restricted to a domain interval of
-4 sxs 4, is the domain over the interval continuous or discrete,
and what is the range of the function?
EXAMPLE: If the function f(x) = 2x ==x+4 is restricted - 1

Answers

Answer 1
Answer:

The range of the given function in interval notation is 2\le y\le6.

The given function is f(x)=(1)/(2)x+4 and the domain interval is -4\le x\le4.

The domain and range are defined for a relation and they are the sets of all the x-coordinates and all the y-coordinates of ordered pairs respectively.

Substitute x=4 in the given function, we get

f(4)=(1)/(2)*4+4

f(4)=6

Substitute x=-4 in the given function, we get

f(-4)=(1)/(2)*(-4)+4

f(4)=2

So, the range is 2\le y\le6

Therefore, the range of the given function is 2\le y\le6.

To learn more about the domain and range visit:

brainly.com/question/28135761.

#SPJ3

Answer 2
Answer:

Answer:b

Step-by-step explanation:


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Furnace repairs Rj's plumbing charges $55 plus $40 per hour for emergency service. Gary remembers being billed over $150 for an emergency call. How long was Rj there?Use an inequality

Answers

You set it up as a y=mx+b problem 150=55x+40 then you subtract 40 from 150 making 110=55x so x=2

A and B and vertical angles. If A=(2x-10) and B= (x+8), find the measure of A

Answers

Answer:

18

Step-by-step explanation:

2x-10=x+8

2x-x=8+10

x=18

Answer is 18 hoped this help

Question below. no links please!

Answers

Answer:

3

Step-by-step explanation:

colinear points mean along the same line

Line m has 3 points labeled

Line n has 3 points labeled

Each line has only 3 points labeled

This is an edit from my previous answer.

Initially I wrote that there were 5 collinear points. My line of reasoning was that A,B,C are on one line (making them collinear), and points D,B,E are on another line (another set of collinear points).

However, if the question is asking how many collinear points are on one particular line, then the answer would be 3 collinear points. You can focus on either line and it's the same number of collinear points.

Definition: The term "collinear" means all points fall on the same straight line.

An island has a popularity of 1500 and is growing at a rate of 3% per year. what will the popularity be after 6 years?Ans:1791​

Answers

Step-by-step explanation:

Growth in population each year = 3%(1500)

= 3/100 × 1500

= 3 × 15

= 45

Therefore, the growth in population in 6 years

= 6 × 3%(1500)

= 6 × 45

= 270

Hence, the population after 6 years = 1500 + 270

= 1770

Trisha Long wants to buy a boat in five years. She estimates the boat will cost $15,000 at that time. What must Trisha deposit today in an account earning 5% annually to have enough to buy the boat in five years?

Answers

We use the formula for compound growth to figure this problem out. Formula is:

P=P_(0)(1+(r)/(n))^(nt)

Where,

  • P is the future value
  • P_(0) is the initial deposite
  • r is the rate of interest annually
  • n is the number of times compounding occurs (n=1 for annual compounding, n=2 for semiannual compounding etc.)
  • t is time

Given P=15,000, r=5%=0.05 (in decimal), n=1 (since annual compounding), and t=5 years, we can solve:

15000=P_(0)(1+(0.05)/(1) )^((1)(5))\n15000=P_(0)(1+0.05)^(5)\nP_(0)=(15000)/((1+0.05)^(5))\nP_(0)=(15000)/(1.05^(5))\nP_(0)=11,752.89

So, Trisha Long needs to deposit $11,752.89 today in the account.


ANSWER: $11,752.89

\bf \qquad \textit{Compound Interest Earned Amount}\n\nA=P\left(1+(r)/(n)\right)^(nt)\qquad \begin{cases}A=\textit{compounded amount}\to &15000\nP=\textit{original amount deposited}\nr=rate\to 5\%\to (5)/(100)\to &0.05\nn=\begin{array}{llll}\textit{times it compounds per year}\n\textit{annually means, once}\end{array}\to &1\nt=years\to &5\end{cases}

solve for "P", to see how much Principal she should deposit today

F(x)=2

x

2



5

x



8

2x

2

−5x−8

g

(

x

)

=

g(x)=







5

x

+

4

−5x+4

Find:

(

g



f

)

(

x

)

Find: (g∘f)(x)

Answers

Answer:

(g\ o\ f)(x) = -10x^2 + 25x + 44

Step-by-step explanation:

Given

f(x) = 2x^2 - 5x - 8

g(x) = -5x+4

Required

Find:\ (g\ o\ f)(x)

In functions;

(g\ o\ f)(x) = g(f(x))

Substitute f(x) = 2x^2 - 5x - 8 in (g\ o\ f)(x) = g(f(x))

(g\ o\ f)(x) = g(f(2x^2 - 5x - 8))

Solving for g(f(2x^2 - 5x - 8))

If g(x) = -5x+4

then

g(f(2x^2 - 5x - 8)) = -5(2x^2 - 5x - 8) + 4

Open Bracket

g(f(2x^2 - 5x - 8)) = -10x^2 + 25x + 40 + 4

g(f(2x^2 - 5x - 8)) = -10x^2 + 25x + 44

Recall that:

(g\ o\ f)(x) = g(f(2x^2 - 5x - 8))

This implies that

(g\ o\ f)(x) = -10x^2 + 25x + 44