Calculate the mass percent of oxygen in KMnO4.

Answers

Answer 1
Answer:

Answer: 40.496%

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Which of the following is an example of physical change?

Answers

Answer:

The glass cup falling from the counter

Explanation:

the glass isn't changing in any chemical way. it's still made of the same material, just broken apart.

Final answer:

Physical changes involve the alteration of the state or appearance of matter, without changing the composition. An example is solid wax turning into liquid wax when heated, or steam condensing inside a cooking pot.

Explanation:

The question asks for an example of a physical change. Physical changes involve alterations in the state or appearance of matter, without changing its composition. For example, solid wax turning into liquid wax when heated is a physical change. The wax is still the same substance, it's just in a different state. Similarly, steam condensing inside a cooking pot is also a physical change. The water vapor turns back into liquid water, but it's still water. These are distinguished from chemical changes, which transform one substance into a different substance.

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For your sink at home, the flow rate in is 5000 units/hr. Accumulation is 2500 units. What is the accumulation rate if the out flow is 60 units/min? multiple choicea) 2400 units/hr b) 400 units/hr c)100 units/hr d) 1400 units/hr e) 3400 units/hr

f) other ____________________

Answers

Answer:

  • Option d) 1400 units/hr

Explanation:

Using law of conservation of mass, you can do a mass balance or volume balance:

  • Volume in - Volume out = Volume accumulation

If you divide by time unit, you get flow balance:

  • Volume in / time - Volume out / time = Volume accumulation / time

  • Flow rate in - Flow rate out =  Accumulation rate

Here you have:

  • Flow rate in = 5000 units/h

  • Flow rate out = 60 units/min

        Convert to rate in units/h: (60 units /min) × (60 min/h) = 3600 units/h

        Flow rate out = 3600 units/h

Then:

  • Accumulation rate = 5000 units/h - 3600 units/h = 1400 units/h

Ascorbic acid (vitaminc.Does not contain a traditional carboxylic acid group, but it is, nevertheless, still fairly acidic (pka = 4.2). Identify the acidic proton and explain your choice using resonance structures, if necessary:

Answers

Let us see the structure of ascorbic acid


As shown there is no COOH group however the OH group can lose a proton and forms conjugate base

The conjugate base formed is stabilized due to resonance

More the stability of conjugate base more the strength of acid

Hence ascorbic acid behaves as an acid

If the crucible originally weighs 3.715 g and 2. 000 g of hydrate are added to it , what is the weight of the water that is lost if the final weight of the crucible and anhydrous salt is 5.022?

Answers

For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.

From the problem, you know that 1) = 2.000 g.

Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).

1) = 5.022 g - 3.715 g = 1.307 g

Now you can complete our original task.

Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.


Final answer:

The weight of the water lost is 0.693 g.

Explanation:

To calculate the weight of the water that is lost, we need to find the weight of the anhydrous salt. The anhydrous salt is the crucible with the added hydrate, minus the weight of the crucible. So, the weight of the anhydrous salt is 5.022 g - 3.715 g = 1.307 g. Since the weight of the hydrate is 2.000 g, the weight of the water that is lost is equal to the difference between the weight of the hydrate and the weight of the anhydrous salt, which is 2.000 g - 1.307 g = 0.693 g.

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What will the pressure of the gas be if the temperature rises to 87°C?A. 60 kPa
B. 161 kPa
C. 16 kPa
D. 41 kPa

Answers

Answer:

A. 60 kPa

Explanation:

P2 = p1 times t2 / t1

How many sodium ions are in 1.4 kg of sodium chloride, NaCl?

Answers

Answer:

1.44 x 10²⁵ ions of Na⁺

Explanation:

Given parameters:

Mass of NaCl  = 1.4kg  = 1400g

Unknown:

Number of ions of sodium  = ?

Solution:

The compound NaCl in ionic form can be written as;

      NaCl →  Na⁺ + Cl⁻

In 1 mole of NaCl we have 1 mole of sodium ions

 Now, let us find the number of moles in NaCl;

  Number of moles  = (mass)/(molar mass)  

    Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol

Number of moles  =  (1400)/(58.5)     = 23.93mol

 So;

   Since 1 mole of NaCl gives 1 mole of Na⁺  

    In 23.93 mole of NaCl will give 23.93 mole of Na⁺

1 mole of a substance  = 6.02 x 10²³ ions of a substance

  23.93 mole of a substance  =  6.02 x 10²³ x  23.93

                                                   = 1.44 x 10²⁵ ions of Na⁺