Which factors are needed for organisms to live earth

Answers

Answer 1

Answer:

Answer: sunlight, water, air, habitat, and food.

Explanation: we are all living organisms and we all have our five basic necessities for survival; sunlight, water, air, habitat, and food.

Related Questions

Every substance melts at 0 degrees Celsius and boils at 100 degrees Celsius.True False
An element has an atomic number of 30. How many protons and electrons are in a neutral atom of the element? A. 30 protons, 30 electrons B. 15 protons, 15 electrons C. 60 protons, 30 electrons D. 30 protons, 0 electrons
What role in photosynthesis does chlorophyll play
When a mixture of iron powder and sulphur is heated it glows more brightly than that of iron filings and sulphur.Explain this observation
Given the reaction: Mg(s) + 2 AgNO3(aq) → Mg(NO3)2(aq) + 2 Ag(s) Which type of reaction is represented?

In order to get a reaction started the reactants of this type of reaction require the greatest amount of energy:a. fusion
b. fission
c. physical
d. chemical

Answers

The answer is A. Fusion is a reaction type that in order to initiate the reaction a greatest amount of energy should be inputted. This reaction involves two or more atomic nuclei coming very close to each other then colliding and eventually joining to form a new nucleus. The energy needed to do this is very large.

2H2 + O2 mc002-1.jpg 2H2O The number of moles of hydrogen that is needed to produce 0.253 mol of water is

Answers

Answer : The number of moles of hydrogen gas needed are, 0.253 mole

Explanation : Given,

Moles of water = 0.253 mole

Now we have to calculate the moles of hydrogen gas.

The given balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced reaction we conclude that,

As, 2 moles of water obtained from 2 moles of hydrogen gas

So, 0.253 moles of water obtained from $(2)/(2)* 0.253=0.253mole$ of hydrogen gas

Therefore, the number of moles of hydrogen gas needed are, 0.253 mole

Mol --> Mol is a one step, XMol H2 = .253mol H20 x 2/2 = .253 mol H2

A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.

Answers

The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.

Final answer:

By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.

Explanation:

To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.

The molar mass of O2 is approximately 32.00 g/mol.

A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.

B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.

C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.

Learn more about Gas Laws here:

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A liquid mixture in which particles can be seen and easily separated by settling or filtration is aa. solution.
b. suspension.
c. solvent.
d. solute.

Answers

The answer for this statement is letter B. suspension. The liquid mixture in which particles can be seen and easily separated by settling or filtration is a suspension.

Answer:

suspension

Explanation:

I've been given the formula C5H12O. I need to determine the structure and IUPAC name by looking at the IR, proton NMR, and carbon NMR.

Answers

Alcohol isomers :
(1) CH3CH2CH2CH2CH2OH = n-pentanol (pentane-1-ol)
(2) CH3CH2CH2CH(OH)CH3 = 2-pentanol (pentane-2-ol)
(3) CH3CH2CH(OH)CH2CH3 = 3-pentanol (pentane-3-ol)
(4) CH3CH2CH(CH3)CH2OH = 2-methyl-1-butanol
(5) CH3CH2C(CH3)(OH)CH3 = 2-methyl-2-butanol
(6) CH3CH(OH)CH(CH3)CH3 = 3-methyl-2-butanol
(7) CH2(OH)CH2CH(CH3)CH3 = 4-methyl-1-butanol
(8) CH3CH(CH3)CH2CH2OH = 3-methyl-1-butanol
(9) CH3C(CH3)2CH2OH = 2,2-dimethyl-1-propanol

Ether isomers:
(1) CH3CH2CH2CH2-O-CH3 = methyl butyl ether
(2) CH3CH2CH2-O-CH2CH3 = ethyl propyl ether
(3) CH3CH(CH3)CH2-O-CH3 = methyl isobutyl ether
(4) CH3CH2CH(CH3)-O-CH3 = methyl sec-butyl ether
(5) CH3CH2-O-CH(CH3)CH3 = methyl isopropyl ether

In polar coordinates, the origin is called the _____.

Answers

In polar coordinates, the origin is called the pole. Polar coordinate system is actually a two dimensional coordinate system. In this type of system the reference point is known by the name of pole. I hope that this is the answer that you were looking for and the answer has come to your desired help.

Answer:

In polar coordinates, the origin is called the pole.

Explanation:

The position of a point in a polar coordinate system is defined by using the distance from a fixed point and an angle made with a fixed ray from that point. It is a two-dimensional coordinate system.

The polar coordinates is defined as

$P(r,\theta)$

Where, r is radius and θ is the angle with the polar axis, i.e. positive axis.

In a coordinate system (0,0) is called origin.

In polar coordinate system (0,0) is called pole.

Therefore, in polar coordinates, the origin is called the pole.

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If 62.0 grams of magnesium metal (Mg) react with 55.5 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the excess reactant will be left over when the reaction is complete? Be sure to write out the balanced equation for this reaction and to show all of your work.