Peyton already has 15 dollars. Every hour (x) that she works at the corner store, she earns another 3 dollars (y). How many total dollars will Peyton have after 15 hours of work?

Answers:

• Gradient of f:    

• Gradient of f at point p:

• Directional derivative of f and P in direction of v:

• The maximum rate of change of f at P:  

• The (unit) direction vector in which the maximum rate of change occurs at P is:  

Step by step solutions:

Given that:

A: Gradient of f

B: Gradient of f at point P:

Just put the coordinates of p in above formula:

C: The directional derivative of f and P in direction of v:

The directional derivative is found by dot product of :

D: The maximum rate of change of f at P is calculated by evaluating the magnitude of gradient vector at P:

E: The (unit) direction vector in which the maximum rate of change occurs at P is:

That vector v is the needed unit vector in this case.

we divided by to make that vector as of unit length.

Learn more about vectors here:

brainly.com/question/12969462

Answer:

a) The gradient of a function is the vector of partial derivatives. Then

b) It's enough evaluate P in the gradient.

c) The directional derivative of f at P in direction of V is the dot produtc of and v.

d) The maximum rate of change of f at P is the magnitude of the gradient vector at P.

e) The maximum rate of change occurs in the direction of the gradient. Then

is the direction vector in which the maximum rate of change occurs at P.

Sorry this is so late.

The answer is "Add the left side of equation 2 to the left side of equation 1"

Answer:

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Step-by-step explanation:

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative and equating zero

iii) solve and find 'x' values

iv) Find second derivative then find the minimum value at x=a

v) Find second derivative then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

step1:- find first derivative and equating zero

 ……………(1)

the point is x=0

step2:-

Again differentiating with respective to 'x', we get

on simplification , we get

put x= 0 we get   > 0

then find the minimum value at x=0

Final answer:-

The minimum value of the given function is f(0) = 0

Answer:

a. t = 2.48 will be a period within 2009.

b. 56.16 million

Step-by-step explanation:

Here is the complete question

Apple introduced the first iPod in October 2001. Sales of the portable music player grew slowly in the early years but began to grow rapidly after 2005. But the iPod era is coming to a close. Smartphones with music and video

Apple introduced the first iPod in October 2001. Sales of the portable music player grew slowly in the

END OF THE IPOD ERA

players are replacing the iPod, along with the category of device it helped to create. Sales of the iPod worldwide from 2007

through 2011 (in millions) were

approximately

N(0= -2.65t2 + 13.13t+ 39.9 (0 < t< 4)

in year t, where t= 0 corresponds to 2007. Show that the worldwide sales of the iPod peaked sometime in 2009. What was the approximate largest number of iPods sold worldwide from 2007 through 2011?

a. Show that the worldwide sales of the iPod peaked sometime in 2009

N(t) = -2.65t² + 13.13t + 39.9

To find the maximum value of N(t), we find dN(t)/dt and equate it to zero

dN(t)/dt = d[-2.65t² + 13.13t + 39.9]/dt

dN(t)/dt = -5.3t + 13.13 = 0

-5.3t = - 13.13

t = -13.13/(-5.3)

t = 2.477

t ≅ 2.48

d²N(t)/dt² =d[-5.3t + 13.13]/dt = -5.3 < 0. So, t = 2.48 is a maximum point

Since t = 2 is 2009 and t = 3 is 2010, t = 2.48 will be a period within 2009.

b. What was the approximate largest number of iPods sold worldwide from 2007 through 2011?

The approximate largest number of ipods sold is when t = 2.48

N(2.48) = -2.65(2.48)² + 13.13(2.48) + 39.9

N(2.48) = -16.29856 + 32.5624 + 39.9

N(2.48) = 56.16384

N(2.48) ≅ 56.16 million

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}