/_A and /_B are vertical angles. If m_A = (2x – 4) and mZB = (x + 1)º,then find the value of x.

Answers

Answer 1

Answer: 1. Set each equation to each other. 2x-4=x+1
2. Subtract x from 2x. 2x-x-4=x-x+1
3. Add 4 to both sides. x-4+4=1+4
4. Answer to value of x=5.

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What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?f(x) = x4 – 3x2 – 4
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f(x) = (x – 2)(x – 3)(x – 2i)(x – 3i)
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Answers

In the question "What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?" The given roots are i, -2 and 2. Recall that for any polynomial having complex root, the conjugate of the complex root is also a root of the polynomial, thus -i is also a root of the required equation. Thus the required equation is obtainrd thus: f(x) = (x - i)(x + i)(x - 2)(x + 2) = (x^2 + 1)(x^2 - 4) = x^4 - 4x^2 + x^2 - 4 = x^4 - 3x^2 - 4 In the question "Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?" The required equation is obtained thus: f(x) = -(x - 4)^2 = -(x^2 - 8x + 16) = -x^2 + 8x - 16 In the question "Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1" Recall that for any polynomial having complex root, the conjugate of the complex root is also a root of the polynomial, thus -2i and -3i are also roots of the required equation. Thus the required equation is obtained thus: f(x) = (x + 2i)(x + 3i)(x - 2i)(x - 3i).

I need help with 1+1 First answer gets Brainliest(Please explain how you got the answer)

Answers

Answer:

Step-by-step explanation:

Solve 5m − 3h = 45 for h. Show your work.

Answers

Answer:

h = $-15 +(5)/(3)$ .

Step-by-step explanation:

Given : 5m − 3h = 45.

To find : Solve for h.

Solution : We have given 5m − 3h = 45.

On subtracting both sides by 5m.

- 3h = 45 - 5m.

On dividing both sides by -3 .

h = $(45 - 5m)/(-3)$ .

h = $(45)/(-3) +(5)/(3)$ .

h = $-15 +(5)/(3)$ .

Therefore , h = $-15 +(5)/(3)$ .

5m-3h= 45
-5m -5m
(-3h= 45-5m)/(-3) to get h alone.
h= (-45/3)-(5/-3)m, simplify
h=-15+(5/3)m

Admission to a baseball game is $4.50 for general admission and $6.00 for reserved seats. The receipts were $4210.50 for 845 paid admissions. how many of each ticket were sold?

Answers

Let's solve this problem using a system of equations. Let's assume the number of general admission tickets sold is represented by 'x' and the number of reserved seats sold is represented by 'y'.

We know that the total number of paid admissions is 845, so we can write the equation:

x + y = 845 (Equation 1)

We also know that the total receipts from ticket sales is $4210.50. Since the price for general admission is $4.50 and the price for reserved seats is $6.00, we can write the equation:

4.50x + 6.00y = 4210.50 (Equation 2)

Now, we can solve this system of equations to find the values of 'x' and 'y'.

From Equation 1, we can rewrite it as:

x = 845 - y

Substituting this value of 'x' into Equation 2, we get:

4.50(845 - y) + 6.00y = 4210.50

Expanding and simplifying:

3802.50 - 4.50y + 6.00y = 4210.50

Combine like terms:

1.50y = 408.00

Divide both sides by 1.50:

y = 272

Substituting this value of 'y' back into Equation 1, we can solve for 'x':

x + 272 = 845

x = 573

Therefore, 573 general admission tickets and 272 reserved seats were sold.

Rewrite A=P +Prt in a different format