What is the energy needed to raise an electron in the hydrogen atom from the second energy level to the third energy level ?a.) 1.52x10^4 J b.) 3.63*10^-19 J c.) 2.18x10^-19 J d.) 4.48x10^-9 J e.) 3.03*10^-19J
Answers
is the energy needed to raise an electron in the hydrogen atom from the second energy level to the third energy level.
What are Energy Levels?
The electrons that surround an atom around the nucleus are located in regions called "energy levels". It represents the 3-D space that surrounds the nucleus where the electrons are present. It is divided into several energy levels such as first energy level, second energy level and so on.
The level that is closest to the nucleus is the first energy level, then the second one is further away from it, then the third one is a little further away and so on. Each energy level has different number of electrons like first has 2 electrons, second has 8, third has 8 and so on. The electrons which are further away from the nucleus are called valence electrons.
For given above information,
E = - /
where,
= 13.6 eV (1 eV = 1.602×10-19 Joules) and n = 1,2,3… and so on so that the ground state has energy
= -13.6 eV and the second energy level (the first excited state) has energy
= -13.6/4 eV = -3.4 eV.
So,
1eV = 1.602×J
Energy difference can be calculated by -13.6eV (-
)
= Final energy;
= Initial energy
1.88 eV is equals to x
So, x= 3.03*
Thus, is the energy needed to raise an electron in the hydrogen atom from the second energy level to the third energy level.
Learn more about Energy Level, here:
#SPJ2
Related Questions
A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. How many grams of N2 must react to form 1.7 grams of ammonia, NH3? 0.0058 g .052 g 1.4 g 2.8 g
Isooctane has the molecular formula C8H18. What is its empirical formula
A strong acid with a concentration of 0.01 Mol/L would have a pH of __________.2134
Which nuclear emission is negatively charged?(1) an alpha particle (2) a beta particle (3) a neutron (4) a positron
Answers
The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.
Molarity can be defined as the moles of solute in a litre of solution. The solution of potassium nitrate has been prepared to be of Molarity 0.2 M. The moles of solute present in the solution can be calculated as:
Molarity = moles volume (L)
The given volume = 50 ml
1000 ml = 1 L
50 ml = 0.05 L
Molarity of the solution = 0.2 M
The moles of solute:
0.2 = moles 0.05
Moles of Potassium nitrate = 4
The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.
For more information about the moles of solute, refer to the link:
n = M x V
n = 0.20 x 0.05
n = 0.01 moles of solute
Question 16 options:
This is the answer >>>>>>>>As the phase changes occur, the freedom of motion of the particles increases.
As the phase changes occur, the freedom of motion of the particles decreases.
As the phase changes occur, the freedom of motion of the particles compresses.
As the phase changes occur, the freedom of motion of the particles is constant.
Answers
Answer:
A) As the phase changes occur, the freedom of motion of the particles increases.
Explanation:
As the phase changes occur, the freedom of motion of the particles increases.
C6H12O6 + 6O2 → 6CO2 + 6H2O
Which compounds are the reactants and which are the products?
A.
reactants: C6H12O6 + 6O2
products: 6CO2 + 6H2O
B.
reactants: 6CO2 + 6H2O
products: C6H12O6 + 6O2
C.
reactants: 6CO2 + C6H12O6
products: 6H2O + 6O2
D.
reactants: 6H2O + 6O26CO2 + C6H12O6
products: 6CO2 + C6H12O6
Answers
Reactants on left (see on the arrow), products on right.
Final answer:
For the given chemical equation illustrating cellular respiration, the reactants comprise glucose (C6H12O6) and oxygen (6O2), and the products are carbon dioxide (6CO2) and water (6H2O). This symbolizes how in living cells, glucose and oxygen are transformed into energy, leading to the release of carbon dioxide and water as byproducts.
Explanation:
In the given chemical equation for cellular respiration, C6H12O6 (glucose) and 6O2 (oxygen) are the reactants and 6CO2 (carbon dioxide) and 6H2O (water) are the products.
This represents the process in living cells where glucose and oxygen are transformed into energy, releasing carbon dioxide and water as byproducts. Therefore, the correct answer is option A: Reactants are C6H12O6 + 6O2 and products are 6CO2 + 6H2O.
Learn more about Cellular Respiration here:
#SPJ11
Answers
Answer: Both technicians are correct
Explanation: A chemical tester and exhaust gas analyzer are two important ways to check for gasket leakage
Answers
Joseph Proust
Ernest Rutherford
J. J. Thomson
Answers
Answer:
J.J. Thomson
Explanation:
Answer:
D
Explanation:
took the test