PLEASE HELP ME OUT IF YOU CAN
PLEASE HELP ME OUT IF YOU CAN - 1

Answers

Answer 1
Answer:

Answer:

D

Step-by-step explanation:


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I need help with math 1010
completing the square
x^2-9x=10

Answers

x^2-9x=10|+20.25\nx^2-9x+20.25=30.25\n(x-4.5)^2=30.25\nx-4.5=5.5 \vee x-4.5=-5.5\nx=10 \vee x=-1

A skier has decided that on each trip down a slope, she will do 2 more jumps than before. On her first trip she did 6 jumps. Derive the sigma notation that shows how many total jumps she attempts from her fourth trip down the hill through her twelfth trip. Then solve for how many total jumps she attempts from her fourth trip down the hill through her twelfth trip.I tried to answer, but I don't really know how to even set it up... :/

Answers

The correct answers are:

Explanation:

Since she is adding two more jumps every time she goes down hill, this is an arithmetic sequence. The general form of an arithmetic sequence is

Since we want the number of jumps on her 4th through 12th trips, we will set n in the summation from 4 to 12. n=4 goes at the bottom of Σ and 12 goes at the top, to represent the values we are interested in.

Beside this, we write our general form. The first term is 6 and d, the common difference, is 2. This gives us 6+2(n-1) beside the summation:

\Sigma_(n=4)^(12) 6+2(n-1)

To evaluate this, we substitute the values 4, 5, 6, 7, 8, 9, 10, 11 and 12 in for n, adding all of the values together:

6+2(4-1)+6+2(5-1)+6+2(6-1)+6+2(7-1)+6+2(8-1)+6+2(9-1)+6+2(10-1)+6+2(11-1)+6+2(12-1)

=6+6+6+8+6+10+6+12+6+14+6+16+6+18+6+20+6+22

=180

I'll just manually compute this one. Every attempt she will add 2 more jumps.

Attempt           Jumps       Accumulated Jumps
1                          6                         6
2                          8                       14
3                         10                      24
4                         12                      36
5                         14                      50
6                         16                      66 
7                         18                      84
8                         20                    104
9                         22                    126
10                       24                    150
11                       26                    176
12                       28                    204

Total jumps from 4th trip through 12th trip: 204 - 24 = 180 jumps

Ebony earned scores of 71, 73, 83, 94, and 82 on five math tests. Determine herscore on the sixth test if her average for the six tests was 83? Enter your answer as a
whole number
Your Answer:

Answers

Answer:

Step-by-step explanation:

Given:71, 73, 83, 94, 82 avg 83 unknown number:x

83 equals 71+73+83+94 +82+x divided by number of scores.

71+73+83+94 +82+x is divided by 6

rearrange equation so that you solve for x

83 times 6

add 71, 73, 83, 94, 82

equation becomes 498=403+x

minus 403 from 498 and that is your x

HELP PLEASE MATH 1 QUESTION !!

Answers

220,000 x (1.055)^15 = 491,145

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11c+7c-13c=115
whats the value of c?

Answers

Simplify both sides of the equation

11c+7c -13c = 115

Simplify

5c= 115

Divide both sides by 5

5c/5 = 115/5

c = 23


I hope that's help !

Find x. need help w these 2 questions in the pic, thanks!

Answers

Hello,

d)

The tangential angle of mesure x intercept the same arc intercepted by the inscribed angle of mesure 70 have the same mesure:

x=70°

e)

There is a rectanglar triangle with a angle of 64°

The complement is 90°-64°=26°

The inscribed angle of mesure x has a mesure which is the half of the center angle of 26°

So x=13°

I hope i have used the right words in my answer.