Parallel Lines and Angle Relationships#1 What is the value of y. Type your answer below. *

#2 If the m<4 is 110 degrees, what is m<1 ? (Give number value only.) *

#3 If e || f and a || b, what is the value of y. *
A) 87
B) 88
C) 91
D) 92
eliseelkins51 avatar

Answers

Answer 1
Answer:

Answer:

1. y = 80°

2. m<1 = 70°

3. y = 92°

Step-by-step explanation:

1. Since lines c and b are parallel lines cut across by transversal a, therefore:

y = 80° (alternate exterior angles are congruent)

2. m<1 is the supplement of m<4, because the angle that forms a linear pair with <1, corresponds with <4.

Therefore: m<1 = 180° - 110° = 70°

3. First, find the value of x.

(x + 1)° + (x - 3)° = 180° (supplementary)

x + 1 + x - 3 = 180°

2x - 2 = 180°

2x = 180 + 2 (addition property of equality)

2x = 182

x = 182/2 (division property of equality)

x = 91

(x + 1)° = y° (alternate interior angles are congruent)

Substitute x = 91

91 + 1 = y

92° = y


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Sales of Volkswagen's popular Beetle have grown steadily at auto dealerships in Nevada during the past 5 years. The sales manager has predicted in 2004 and 2005 sales would be 410 VW's. Using exponential smoothing with a alpha = 0.30 develop a forecast for 2006 through 2010. What is the forecast value for 2010?Please answer to one decimal place. (Example: 466.1)Formula: Ft = Ft-1 + alpha(At-1 - Ft-1)Actual sales data:2005 = 4502006 = 4952007 = 5182008 = 5632009 = 584

Answers

Answer:

Step-by-step explanation:

Given the data:

Year___Actual sale (At) ___forecast(Ft)

2005__450_____________410

2006__495____________ 422

2007__518____________ 443.9

2008_ 563____________ 466.1

2009_584____________ 495.2

2010__

Using the formula :

Ft = Ft-1 + alpha(At-1 - Ft-1)

Ft-1 = previous year forecast

At-1 = previous year actual

Alpha = 0.3

Forecast:

2006:

410 + 0.3(450 - 410) = 422.0

2007:

422 + 0.3(495 - 422) = 443.9

2008:

443.9 + 0.3(518 - 443.9) = 466.1

2009:

466.1 + 0.3(563 - 466.1) = 495.2

2010:

495.2 + 0.3(584 - 495.2) = 521.8

Forecasted value for 2010 = 521.8

Final answer:

By utilizing the method of exponential smoothing with alpha=0.3 and applying the forecasting formula iteratively, the forecasted sales of Volkswagen Beetles for 2010 in Nevada is 525.7 units.

Explanation:

The exponential smoothing method is commonly used in business and economics for forecasting future data in situations where historical data is available. The forecast value for 2010 using exponential smoothing with alpha = 0.30 can be obtained by implementing the provided formula in an iterative manner. This formula takes into account the actual data point from the previous year (At-1) and the forecasted data point for that year (Ft-1).

Let us use the forecast value for 2004 and 2005, which was predicted as 410 for each year, as our initial forecast value (F1).

By applying the formula Ft = Ft-1 + alpha * (At-1 - Ft-1) iteratively for each year from 2006 to 2009, we get:

  • Forecast for 2006 (F_2006) would be 410 + 0.30*(450-410) = 422.
  • Then, the forecast for 2007 (F_2007) is 422 + 0.30*(495-422) = 443.9.
  • The forecast for 2008 (F_2008) is 443.9 + 0.30*(518-443.9) = 466.1.
  • For 2009 (F_2009), the forecast is 466.1 + 0.30*(563-466.1) = 496.37.
  •  

 

Using these forecasted rates, we then forecast for the year 2010. The forecast for 2010 (F_2010) is calculated by 496.37 + 0.30*(584-496.37) giving 525.67 (rounded to one decimal place). Hence the forecast for the year 2010 using exponential smoothing with the alpha as 0.30 is estimated to be 525.7 VolksWagen Beetles.

Learn more about Exponential Smoothing here:

brainly.com/question/31358866

#SPJ3

What is the sum of the polynomials? (8x2-9y2-4x)+(x2-3y2-7x)

Answers

The sum of the polynomials (8x²-9y²-4x)+(x²-3y²-7x) is:

 1. You must add the terms whose variables and exponents are the same. 
 2. Let's rewrite the polynomials:

 (8x²-9y²-4x)+(x²-3y²-7x)
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 3. Therefore, the result is:

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 3. What is the sum of the polynomials?

 The answer is: 
9x²-11x-12y²

Answer:

D

Step-by-step explanation:

Help pls with answer!!!Rewrite the function in the given form.

Answers

Answer:

g(x) = (-2)/(x-1)+5\n\n

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = (5x-7)/(x-1)\n\ng(x) = (5x-5-2)/(x-1)\n\ng(x) = ((5x-5)-2)/(x-1)\n\ng(x) = (5(x-1)-2)/(x-1)\n\ng(x) = (5(x-1))/(x-1)+(-2)/(x-1)\n\ng(x) = 5+(-2)/(x-1)\n\ng(x) = (-2)/(x-1)+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation g(x) = (-2)/(x-1)+5\n\n to the form g(x) = (a)/(x-h)+k\n\n

We can see that

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  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
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Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

The diagonals AC and BD of the convex quadrilateral ABCD with area 28 intersect each other at point O. The lines which are parallel to the diagonal AC come through the midpoints of segments BO and DO . Find the area of the portion of the quadrilateral that is between those lines.

Answers

Answer:

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Step-by-step explanation (note, the suggested way is not the shortest one):

all the details are in the attached picture.

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of

Answers

CHECK THE ATTACHMENT FOR COMPLETE QUESTION

Answer:

We can show that ΔABC is congruent to ΔA'B'C' by a translation of 2 unit(s) Left and a Reflection across the x axis.

Step-by-step explanation:

We were given triangles ABC and A'B'C' of which were told are congruents,

Now we can provide the coordinates of A and A' from the given triangles ΔABC and ΔA'B'C' ,if we choose a point of A from ΔABC and A' from ΔA'B'C' we have these coordinates;

A as (8,8) and A' (6,-8) from the two triangles.

If we shift A to A' , we have (8_6) = 2 unit for that of x- axis

If we try the shift on the y-coordinates we will see that there is no translation.

Hence, the only translation that take place is of 2 units left.

It can also be deducted that there is a reflection

by x-axis to form A'B'C' by the ΔABC.

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Answers

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