According to kineric molecular theory which statement descrives the particles in a sample of an ideal gas

Answers

Answer 1

Answer:

Answer:

According to the kinetic molecular theory, which statement describes the particles in a sample of an ideal gas? The motion of the gas particles is random and in a straight-line.

Explanation:

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Which element is capable of forming long chains by forming single, double, or triple bonds with itself?
3.50 L of 0.200 M hydrochloric acid is prepared using 12.0 M HCl(aq) stock solution to which water is added. What volume of the stock solution is required? a. 7.00 mL b. 8.40 mL c. 17.1 mL d. 58.3 mL
The diagram shows a ball resting at the top of a hill. Which statement best describes the energy in this system
3 x 1023 molecules of element Z have a mass of 38 g. What is the mass of 1 mole?
Which solution has the greatest buffer capacity?

Which balanced equation represents an endothermic reaction?(1) C(s) + O2(g) → CO2(g)
(2) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
(3) N2(g) + 3H2(g) → 2NH3(g)
(4) N2(g) + O2(g) → 2NO(g)

Answers

Answer:

4) N2(g) + O2(g) → 2NO(g)

Explanation:

In a chemical equation, the location of the word "heat" can be used to quickly determine whether the reaction is endothermic or exothermic. If heat is released as a product of the reaction, the reaction is exothermic. If heat is listed on the side of the reactants, the reaction is endothermic.

However in the options given, heat was not mentioned. this means we would have to undergo elimination process.

Option 2 represents combustion of methane, heat is a natural by product of any combustion reaction. hence, the correct answer cannot be 2.

Option 1 - The C=O bonds in CO2 have a high bond energy (the energy you would need to break them) which is more than either of the C-C or O=O bonds in the elements and their sum. Thus to create C and O2 from CO2 you would have to put in energy to break the two C=O bonds. You would get some back from the C-C and O=O bonds but less. Thus you need to add a lot of energy to convert CO2 into its elements. (You can decompose it at high temperatures.)

The reverse process gives off heat. So again, the correct answer cannot be 1.

Option 3 - The heat of formation of H2 ( g ) and N2( gas) under the standard condition is zero ( 0), and heat of formation of NH3 ( g ) is -46.11 kj / mol, so for the formation of 2 moles of NH3( g ) it would be - 92.22 kj,

The -ve symbol is indicative of the above reaction is exothermic in nature. So again, the correct answer cannot be 3.

Our only option left is 4 - The standard enthalpy of formation of nitric oxide (NO) in the gas phase is about +90 kJ/mol, which is endothermic. The primary reason for this is that the nitrogen-nitrogen triple bond is very strong (941 kJ/mol). The energy cost to break that bond as well as the oxygen-oxygen double bond (495 kJ/mol) is not compensated by the forming of the nitrogen-oxygen double bond (607 kJ/mol). Endothermic reactions are the result of breaking strong bonds and forming weaker ones.

N2 (g) + O2 (g) ---» 2NO (g) represents an exothermic reaction.

What is the word equation for molecules of magnesium reacting with molecules of oxygen to produce molecules of magnesium oxide?magnesium + magnesium oxide = oxygen
magnesium + oxygen =magnesium oxide
magnesium oxide = magnesium
magnesium + oxygen magnesium + oxygen

Answers

Answer: magnesium + oxygen =magnesium oxide

Explanation: When Magnesium reacts with the molecules of oxygen , Magnesium oxide is produced.

Mg (s) + O (g) → MgO (s)

In this equation, both magnesium and oxygen are present in its elemental state.

Magnesium is present in solid form and oxygen is present in gaseous form.

The Bonding between the Magnesium and the oxygen is purely IONIC bonding as Magnesium loses its 2 valence electrons to complete its octet and oxygen gains its electrons to make its electron count 8 in the valence shell.

Answer: (B) Magnesium + oxygen =magnesium oxide

Explanation:

Which period is older than the Triassic period? Cambrian Cretaceous Jurassic Paleogene.

Answers

The Triassic period is one of the geological periods and is the shortest of the Mesozoic era. Cambrian is the older era than the Triassic period.

What is Cambrian and triassic period?

The Triassic period existed 250 -200 million years ago and started after the vastest and most extreme devastation ever. It is the 1st period of the Mesozoic and is known for the movement of the Dinosaurs on the land, flying pterosaurs and swimming plesiosaurs and ichthyosaurs.

The Cambrian is the period of the Paleozoic era and is the most important period because of the appearance of many animals. In this period, the temperature raised on the planet and the ice sheets melted at a very dangerous rate leading to mass devastation.

Therefore, option A.Cambrian is older than the Triassic period.

Learn more about Cambrian and Triassic periods here:

brainly.com/question/11417834

Answer:

A: Cambrian!

Explanation:

got it right on ed :)

A vineyard has 145 acres of Chardonnay grapes. A particular soil supplement requires 5.50 g for every square meter of vineyard. How many kilograms of the soil supplement are required for the entire vineyard? (Recall that 1 km2 = 247 acres.) Express your answer in kilograms to three significant figures.

Answers

1.36.10 ^ 6 kg of supplements are required for the entire vineyard

Further explanation

7 main quantities have been determined based on international standards, namely:

1. Length, meters (m)

2. Time, second (s)

3. Mass, kilograms (kg)

4. Temperature, kelvin (K)

5. Light intensity, candela (cd)

6. Electric current, ampere (A)

7. Amount of substance, mol (m)

Derivative magnitude is a quantity derived from one or more principal quantities. So in addition to 7 principal quantities, other quantities are derived quantities

An area with the formula length x width is a unit derived from the length of the principal. The international standard unit is square meters (m²).

other area units: Km², hm², dam², m², dm², cm², and mm²

Hectare is an SI unit

1 Hectare is equal to 100 a (Are) or 10000 m² (ten thousand square meters) or 100 x 100 m 1 Hectares = 2.47 acres

In the question , there is a 145 acres vineyard, with the supplement is given 5.5 gram / m² vineyard.

So for 1 km², a supplement =

1 km² = 10⁶ m²

5.5 gram / m² = 5.5.10⁶ grams / km²

whereas 1 km² = 247 acres and vineyard = 145 acres so

$5.5.10^6*(145)/(247)$

= 3.2287.10⁶ grams

= 3.23.10³ kg (3 significant numbers: 3,2 and 3)

Learn more

Convert the following metric units of weight

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conversion factor

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convert a mass of 2.93 pounds to ounces

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Keywords: area, convert, acres

The soil supplement required for the entire vineyard is $\boxed{3.23 * {{10}^3}{\text{ kg}}}$ .

Further Explanation:

There are two types of units. One is basic or fundamental while the other ones are derived units. Basic units cannot be further reduced and other quantities are expressed in these units. Derived units are those that can need basic units to express themselves. Area, density, volume and velocity are some examples of derived units.

Seven basic units are present in the SI system. These are as follows:

1. Meter (m)

2. Kilogram (kg)

3. Second (s)

4. Kelvin (K)

5. Ampere (A)

6. Mole (mol)

7. Candela (Cd)

Firstly, the area of vineyard has to be converted into ${\text{K}}{{\text{m}}^2}$ . The conversion factor for this is,

$1{\text{ acre}} = \left( {\frac{1}{{247}}} \right){\text{ K}}{{\text{m}}^2}$

Therefore the area of vineyard can be calculated as follows:

$\begin{aligned}{\text{Area of vineyard}} &= \left( {145{\text{ acres}}} \right)\left( {\frac{{1/247{\text{ K}}{{\text{m}}^2}}}{{1{\text{ acre}}}}} \right)\n&= 0.587045{\text{ K}}{{\text{m}}^2}\n\end{aligned}$

The area is again converted into ${{\text{m}}^{\text{2}}}$ . The conversion factor for this is,

$1{\text{ K}}{{\text{m}}^2} = {10^6}{\text{ }}{{\text{m}}^2}$

So the area of vineyard can be calculated as follows:

$\begin{aligned}{\text{Area of vineyard}}&= \left( {0.587045{\text{ K}}{{\text{m}}^2}}\right)\left( {\frac{{{{10}^6}{\text{ }}{{\text{m}}^2}}}{{1{\text{ K}}{{\text{m}}^2}}}}\right)\n&= 587045{\text{ }}{{\text{m}}^2}\n\end{aligned}$

The amount of supplement required for the entire vineyard can be calculated as follows:

$\begin{aligned}{\text{Amount of supplement required}}&= \left( {587045{\text{ }}{{\text{m}}^2}} \right)\left( {\frac{{5.50{\text{ g}}}}{{1{\text{ }}{{\text{m}}^2}}}} \right)\n&=3.2287475 * {10^6}{\text{ g}}\n\end{aligned}$

The amount of supplement is to be converted into kg. The conversion factor for this is,

$1{\text{ g}} = {\text{1}}{{\text{0}}^( - 3)}{\text{ kg}}$

Therefore the amount of supplement can be calculated as follows:

$\begin{aligned}{\text{Amount of supplement}}&= \left({3.2287475 * {{10}^6}{\text{ g}}} \right)\left( {\frac{{{{10}^( - 3)}{\text{ kg}}}}{{1{\text{ g}}}}} \right)\n&= 3.2287475 * {10^3}{\text{ kg}}\n&\approx 3.23 * {10^3}{\text{ kg}}\n\end{aligned}$

Learn more:

What is the mass of 1 mole of viruses: brainly.com/question/8353774
Determine the moles of water produced: brainly.com/question/1405182

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Basic concepts of chemistry

Keywords: supplement, vineyard, 5.50 g, 3.23*10^3 kg, conversion factor, basic units, fundamental units, derived units, area, volume, density, kg, m, Km, acre.

The heart is protected from the bones by the .

Answers

The heart is protected from the bones by the rib cage or the thoracic cage. It protects both the heart and the lungs. The rib cage is composed of 12 pair of ribs, the sternum and thoracic vertebrae. All ribs are connected to the thoracic vertebrae. The rib cage also do not only protect the heart and lungs but also support the body and aid in respiratory function.

How many centimeters would be one - half of a meter beA. 100
B. 500
C. 50
D. 5

Answers

~Hello There!~

Considering that there are 100 cm in a meter, half of that would be 50.

Your answer is C. 50.

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

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