What is negative 2/3 + 4/6

Answers

Answer 1
Answer:

Answer: 0

Step-by-step explanation:

The common denominator is 6

-2/3 = -4/6

-4/6 + 4/6 = 0


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Which descriptions of a histogram are true? Check all that apply..A peak is a bar that is lower than the other bars around it.
A peak is where the frequency is lowest.
A peak is where the frequency is the highest.
A cluster is a group of bars, meaning the frequency is higher in these intervals.
A peak is a bar that is higher than the other bars around it.
Intervals on a histogram where there are no bars mean the frequency is 0.
If the graph is symmetrical, the data is clustered toward the right side.
If the graph is symmetrical, the data is evenly distributed.

Answers

The correct statement about histogram is as follows;

A peak is where the frequency is the highest.

A cluster is a group of bars, meaning the frequency is higher in these intervals.

A peak is a bar that is higher than the other bars around it.

Intervals on a histogram where there are no bars mean the frequency is 0.

If the graph is symmetrical, the data is evenly distributed.

We have to determine, which descriptions of a histogram are true?

According to the question,

A histogram meaning can be stated as a graphical representation that condenses a data series into an easy interpretation of numerical data by grouping them into logical ranges of different heights which are also known as bins.

Characteristics of a Histogram are as follows;

A histogram is used to display continuous data in a categorical form.  

In a histogram, there are no gaps between the bars, unlike a bar graph.  

The width of the bins is equal.

A histogram is a type of representation of a data set where bars are used to represent the frequencies.

The area of these bars is said to be proportional to the frequency of the variable.

The peak of a histogram represents the highest value of frequency. Also, the peak is a bar that is higher than the other bars around it.

In a histogram intervals wherein bars cannot be seen would represent the frequency of that would zero.

Also, if the histogram is said to be symmetrical, then the data should be distributed evenly.

A peak is where the frequency is the highest.

A cluster is a group of bars, meaning the frequency is higher in these intervals.

For more details refer to the link given below.

brainly.com/question/9298915

Answer:

A peak is where the frequency is the highest.

A cluster is a group of bars, meaning the frequency is higher in these intervals.

A peak is a bar that is higher than the other bars around it.

Intervals on a histogram where there are no bars mean the frequency is 0.

If the graph is symmetrical, the data is evenly distributed.

Step-by-step explanation:

You originally draw a design for an art contest on a 4 in. x 5 in. card. The second phase of the contest requires the drawing to be transferred to an 8.5 in x 11 in. standard sheet of paper and utilize as much of the space on the paper as possible. You determine that the largest size one of the dimensions of your drawing can be is 10.5 in. What is the length of the other dimension if the two drawings are similar? Type your exact answer in the blank without the units, and round to the nearest tenths.

Answers

By using ratio and proportion the problem can be solve. First assume that 10.5 in is the length of the new drawing, and let w be the width 4 / 5 = w / 10.5 W = 10.5 ( 4 / 5) W = 8.4 in So the new dimensions are 8.4 in x 10.5 in 

Answer:

8.4

Step-by-step explanation:

HELP ME PLEASE IF YOU DO YOU WILL GET BRAINLESS AND PLEASE EXPLAIN THE BEST YOU CAN

Answers

Answer:

<3=75°

Step-by-step explanation:

Angle 3 and angle 2x+95 are supplementary( supplementary angles add up to 180°)

So <3+2x+95=180

<3+2x=180-95

<3+2x=85( let's call this equation 1)

Next, angle 5 and angle 8x+71 are opposite angles (opposite angles are equal) therefore <5=8x+71

Now, <3 and <5 are co-interior angles(co-interior angles are supplementary)

So <3+8x+71=180

<3+8x=180-71=109

Thus, <3+8x=109(let's call this equation 2)

Now solving equation 1 and 2 simultaneously:

Make <3 the subject of equation 1

<3=85-2x

Put <3=85-2x into equation 2

85-2x+8x=109

6x=24

x=24/6=4

Now, remember that angle 2x+95 becomes

2(4)+95

8+95=103°

Therefore<3=180-105=75°

The sum of two integers is 44. The difference of the two integers is 8.What is the smaller integer?

Answers

Answer:

18

Step-by-step explanation:

44/2=22

the difference between the two numbers= 8

8/2=4

(22-4) + (22+4) = 18+26 = 44

the smaller number = 18

Answer:

The smaller integer is 18.

Step-by-step explanation:

x is the larger integer, and y is the smaller integer.

x + y = 44

x - y = 8

For x - y = 8, add y to both sides and get x = 8 + y.

Change x in x + y = 44 for 8 + y.

8 + y + y = 44

8 + 2y = 44

2y = 36

y = 18

Consider the function f(x)=x3+15x2+74x+120. If f(x)=0 for x=−6, for what other values of x is the function equal to 0? List the values separated by commas.

Answers

Answer:

other x values are -5,-4

Step-by-step explanation:

f(x)=0 for x=−6

Apply synthetic division to get the quotient . using that we find other two values of x

-6                1           15             74          120

                   0          -6           - 54          -120                    

                  -------------------------------------------------

                    1           9             20         0

the quotient is x^2+9x+20=0

now factor the left hand side, product is 20 and sum is 9

x^2+9x+20=0\n(x+5)(x+4)=0\nx+5=0 , x=-5\nx+4=0, x=-4

So  other x values are -5,-4

The solution to 8x = 32 is x = __.

Answers

\huge\text{Hey there!}!

\large\text{8x = 32}

\large\text{DIVIDE 8 to  BOTH SIDES}

\mathsf{(8x)/(8) = (32)/(8)}

\large\text{Cancel out: } \mathsf{(8)/(8)}\large\text{ because that gives you } \mathsf{1}

\large\text{Keep: }\mathsf{(32)/(8)}\large\text{ because it helps us solve for }\mathsf{x}

\mathsf{(32)/(2)\ = x \ or\ x =  (32)/(8)}

\mathsf{(32)/(8) = 32/ 8 \rightarrow \bf 4}

\boxed{\boxed{\large\text{Answer: \bf x = 4}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}