MATHEMATICS COLLEGE

If a 45 gal hot water tank holds 375 lb of water, what weight of water will a 62 gal tank hold

Answers

Answer 1

Answer:

Answer:

517 lb

Step-by-step explanation:

Hello,thanks for asking here in brainly I think I can help you with this

you can easily solve this by using a rule of three

Step one

45 gal⇒ 375 lb

62 gal ⇒ x lb?

do the relation

$(45\ gal)/(375\ lb)=(62\ gal)/(x)\n\nsolve\ for\ x\n\n\n(x*45\ gal)/(375\ lb)=62\ gal\nx=(62\ gal*375\ lb)/(45\ gal) \nx=516.66\ lb\nx=517\ lb$

the weight of water holded in a 62 gal tank is 517 lb

I hope it helps, Have a great day.

Answer 2

Answer: I hope this helps you

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When 12 is subtracted from 3 times a number, the result is 24. Find the number.A) 8

B) 12

C) 4

D) 6

Answers

C the answer to the problem

Gary took 7 hours to mow 4 lawns, then at that rate, how many lawns could be mowed in 35 hours. using a double number line

Answers

Answer: 20 lawns

Step-by-step explanation:

35÷7=5

5×4=20

A painter can finish painting a house in 3 hour

Answers

Answer:

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Step-by-step explanation:

Bruuuuuuuuu + bruh - brooo x π to the pawer of 420 = what please answer this seriously with evidence and reasoning

need help asap please help me if i get rong i will cry

Answers

Answer:

= bruv

Step-by-step explanation:

you spelt power wrong too

Skyler solved an equation incorrectly, as shown below:Step 1: 12 + x = 36
Step 2: x = 36 + 12
Step 3: x = 24

Which statement best explains why Step 2 is incorrect in Skyler's solution?

Answers

Answer:

Step 2 is incorrect.

Step-by-step explanation:

It's incorrect because I'm pretty you need to do inverse operation. To get 24 you must subtract, not add.

Sample annual salaries (in thousands of dollars) for employees at a company are listed. 51 53 48 62 34 34 51 53 48 30 62 51 46 (a) Find the sample mean and sample standard deviation. (b) Each employee in the sample is given a $5000 raise. Find the sample mean and sample standard deviation for the revised data set. (c) Each employee in the sample takes a pay cut of $2000 from their original salary. Find the sample mean and the sample standard deviation for the revised data set. (d) What can you conclude from the results of (a), (b), and (c)?

Answers

Answer:

Mean increase or decrease (same quantity) according to the quantity of the increment or reduction

As all elements were equally affected the standard deviation will remain the same

Step-by-step explanation:

For the original set of salaries: ( In thousands of $ )

51, 53, 48, 62, 34, 34, 51, 53, 48, 30, 62, 51, 46

Mean = μ₀ = 47,92

Standard deviation = σ = 9,56

If we raise all salaries in the same amount ( 5 000 $ ), the nw set becomes

56,58,53,67,39,39,56,58,53,35,67,56,51

Mean = μ₀´ = 52,92

Standard deviation = σ´ = 9,56

And if we reduce salaries in the same quantity ( 2000 $ ) the set is

49,51,46,60,32,32,49,51,46,28,60,49,44

Mean μ₀´´ = 45,92

Standard deviation σ´´ = 9,56

What we observe

1.-The uniform increase of salaries, increase the mean in the same amount

2.-The uniform reduction of salaries, reduce the mean in the same quantity

3.-The standard deviation in all the sets remains the same.

We can describe the situation as a translation of the set along x-axis (salaries). If we normalized the three curves we will get a taller curve (in the first case) and a smaller one in the second, but the data spread around the mean will be the same

Any uniform change in the data will directly affect the mean value

Uniform changes in values in data set will keep standard deviation constant

Final answer:

The mean salary is affected by each employee's changes in salary, such as raises and pay cuts, but the standard deviation (the spread of salaries) remains the same provided the change is the same for all individuals.

Explanation:

To answer this question, we need to calculate the sample mean and sample standard deviation in each case. The sample mean is the average of the data, while the sample standard deviation is a measure of the amount of variation or dispersion in the data set.

(a) Calculate the sample mean and sample standard deviation of the initial salaries. This involves summing all the salaries and dividing by the total number to get the mean, then calculating the standard deviation using the formula: square root of [sum of (each salary - mean salary)² divided by (total number of salaries - 1)].
(b) When each employee is given a $5000 raise, the mean will increase by 5, while the standard deviation will remain the same because raises do not affect the dispersion of the team's salaries.
(c) Similarly, when each employee takes a pay cut of $2000, the mean salary will decrease by 2, but the standard deviation will again remain the same because pay cuts do not affect the dispersion of the team's salaries.
(d) We can conclude that while the mean is affected by changes in individual salaries (like raises and pay cuts), the standard deviation is not, provided the change is the same for all individuals. Therefore, it shows that while supply changes can affect the central tendency (mean), they do not impact how spread out the salaries are (standard deviation).

Learn more about Mean and Standard Deviation here:

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