Explain what happent to the pressure exerted by an object when the area over which it is exerted:a) increase
b) decrease

Answers

Answer 1

Answer: The pressure decreases if the area increases. If the area decreases then the pressure increases.

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James weighs 120 pounds. He ran up the steps which rose 12 feet. John weighs 91 pounds. He ran up the same steps as James. If both boys reached the top of the 12-foot stairs at the same time, which boy had the greatest horsepower?

Answers

Mass of James = 54.431kg
Distance ran by James = 3.6576m
Mass of John= 41.277kg
Distance relan by John= 3.6576m

Work done by James = 54.431kg*10N/kg*3.6576m= 1990.87J

Work done by John= 41.277kg*10N/kg*3.6576m=1509.75J

Horsepower = work done / time since time is same, James has larger horsepower

A gate with a circular cross section is held closed by a lever 1 m long attached to a buoyant cylinder. The cylinder is 25 cm in diameter and weighs 200 N. The gate is attached to a horizontal shaft so it can pivot about its center. The liquid is water. The chain and lever attached to the gate have negligible weight. Find the length of the chain such that the gate is just on the verge of opening when the water depth above the gate hinge is 10 m.

Answers

The length of the chain such that the gate is just on the verge of opening is mathematically given as

l=8.58m

What is the length of the chain?

Generally, the equation for the is mathematically given as

$F'=\gamma hA$

Therefore

$9810*10* (\pi)/(4)1^2$

Fh= 77048 N

Where

$ycp-y=((\pi r^4)/(4))/(10*(\pi D^4)/(4))$

ycp-y=0.00625

In conclusion, resultant force

x = F'' - W

x = 9810* 10*( \pi/4 )*0.25^2 *(10-l)-200

x = 4615.5-481.5 l

Therefore

77048* 0.00625 - 1 *(4615.5-481.5 l) = 0

l=8.58m

Answers

Answer:

(a) Fw = 101.01 N

(b) W = 282.82 J

(d) N = 368.61 N

(e) Net force = 0 N

Explanation:

(a) In order to calculate the magnitude of the worker's force, you take into account that if the ice block slides down with a constant speed, the sum of forces, gravitational force and work's force, must be equal to zero, as follow:

$F_g-F_w=0$ (1)

Fg: gravitational force over the object

Fw: worker's force

However, in an incline you have that the gravitational force on the object, due to its weight, is given by:

$F_g=Wsin\theta=Mg sin\theta$ (2)

M: mass of the ice block = 39 kg

g: gravitational constant = 9.8m/s^2

θ: angle of the incline

You calculate the angle by using the information about the distance of the incline and its height, as follow:

$sin\theta=(0.74m)/(2.8m)=0.264\n\n\theta=sin^(-1)(0.264)=15.32\°$

Finally, you solve the equation (1) for Fw and replace the values of all parameters:

$F_w=F_g=Mgsin\theta\n\nF_w=(39kg)(9.8m/s^2)sin(15.32\°)=101.01N$

The worker's force is 101.01N

(b) The work done by the worker is given by:

$W=F_wd=(101.01N)(2.8m)=282.82J$

(c) The gravitational force on the block is, without taking into account the rotated system for the incline, only the weight of the ice block:

$F_g=Mg=(39kg)(9.8m/s^2)=382.2N$

The gravitational force is 382.2N

(d) The normal force is:

$N=Mgcos\theta=(39kg)(9.8m/s^2)cos(15.32\°)=368.61N$

(e) The speed of the block when it slides down the incle is constant, then, by the Newton second law you can conclude that the net force is zero.

A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99 times 109 N m2/C2 exactly.(a) Find the potential V on the x axis at x = 3.00 m and at x = 3.01 m. In this part, enter your answers to exactly 6 signfificant figures.

Answers

Answer:

a) 8,990.00 V b) 8,960.13 V

Explanation:

a) The potential due to a point charge, can be found from the expression of Coulomb's Law, as follows:

$V = (k*q)/(r)$

where k = 8.99*10⁹ N*m²/C², q = 3.00*10⁻⁶ C, and r = 3.00 m.

Replacing by this values, we can find the potential V as follows:

$V = (8.99e9 N*m2/C2*3.00e-6C)/(3.00m) = 8,990.00 V$

b) Repeating the process for r = 3.01m:

$V = (8.99e9 N*m2/C2*3.00e-6C)/(3.01m) = 8,960.13 V$

Final answer:

The potential V at x=3.00 m and x=3.01 m from a point charge at the origin is 8.99 * 10^3 V and 8.97 * 10^3 V, respectively. This calculation is based on Coulomb's Law.

Explanation:

The potential V at a distance r from a point charge q is given by Coulomb's Law:

V = k*(q/r)

Here, k = 8.99 * 10^9 N*m^2/C^2 is the Coulomb constant, q = 3 µC is the charge, and r is the distance from the origin along the x-axis. For x = 3.00 m and x = 3.01 m, we can substitute these values into the equation to find V:

V1 = ((8.99 * 10^9 N*m^2/C^2)* (3 * 10^-6 C)) / 3.00 m = 8.99 * 10^3 V (to 6 significant figures)
V2 = ((8.99 * 10^9 N*m^2/C^2)* (3 * 10^-6 C)) / 3.01 m = 8.97 * 10^3 V (to 6 significant figures)

Learn more about Electric Potential here:

brainly.com/question/32897214

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A 1,200 kg car travels at 20 m/s. what is it’s momentum ?

Answers

The momentum of the car is 24000 Kg•m/s

Momentum is defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the momentum of the car as follow:

Mass = 1200 Kg

Velocity = 20 m/s

Momentum =?

Momentum = mass × velocity

Momentum = 1200 × 20

Momentum of car = 24000 Kg•m/s

Learn more about momentum:

brainly.com/question/250648

Answer:

24000 kg·m/s

Explanation:

Momentum is Mass x Velocity, so 1200 kg time 20 m/s = 24000 kg-ms/s

Suppose that a particle accelerator is used to move two beams of particles in opposite directions. In a particular region, electrons move to the right at 6020 m/s and protons move to the left at 1681 m/s. The particles are evenly spaced with 0.0476 m between electrons and 0.0662 m between protons. Assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region