The mass of a baseball is 0.145 kg and its acceleration as it falls to the ground is 9.81 m/s2. How much force is acting on the baseball

Answers

Answer 1
Answer:

Answer:

The answer is 1.42 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

Force = 0.145 × 9.81 = 1.42245

We have the final answer as

1.42 N

Hope this helps you


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y axis:NandW and also f x axis:T and F T away from car.

What is suedo force.​

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What is pseudo force?

A pseudo force, also called a fictitious force or an inertial force, is an apparent force that acts on all bodies whose motion is described using a non-inertial frame of reference, such as a rotating reference frame.

A 1850 kg car traveling at 13.8 m/s collides with a 3100 kg car that is initally at rest at a stoplight. The cars stick together and move 1.91 m before friction causes them to stop. Determine the coefficient of kinetic friction between the cars and the road, assuming that the negative acceleration is constant and all wheels on both cars lock at the time of impact.

Answers

To solve this problem, it is necessary to apply the concepts related to the conservation of momentum, the kinematic equations for the description of linear motion and the definition of friction force since Newton's second law.

The conservation of momentum can be expressed mathematically as

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where,

m_(1,2)= Mass of each object

v_(1,2) = Initial Velocity of each object

v_f= Final velocity

Replacing we have that,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

1850*13.8+3100*0 = (1850+3100)v_f

v_f = 5.1575m/s

With the final speed obtained we can determine the acceleration through the linear motion kinematic equations, that is to say

v_f^2-v_i^2 = 2ax

Since there is no initial speed, then

v_f^2 = 2ax

5.1575^2 = 2a (1.91)

a = 6.9633m/s^2

Finally with the acceleration found it is possible to find the friction force from the balance of Forces, like this:

F_f = F_a \n\mu N = m*a \n\mu = (ma)/(N)\n\mu = (ma)/(mg)\n\mu = (a)/(g)\n\mu = (6.9633)/(9.8)\n\mu = 0.7105

Therefore the Kinetic friction coefficient is 0.7105

Use a(t) =−32 feet per second squared as the acceleration due to gravity. a ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second. for how many seconds will the ball be going upward?

Answers

Since the ball is moving by uniformly accelerated motion, its vertical velocity at time t is given by
v(t)= v_0 - a t
where we took upward as positive direction, and where v_0 is the initial velocity, a the acceleration and t the time.

The instant at which v(t)=0 is the instant when the ball reverses its velocity (from upward to downward). This means that the difference between the time t at which v(t)=0 and the instant t=0 is the total time during which the ball was going upward:
0=v_0 - at
By plugging numbers into the equation, we find
t= (v_0)/(a)= (56 ft/s)/(32 ft/s^2)=1.75 s

A small child weighs 60 N. If mommy left him sitting on top of the stairs, which are 12 m high, how much energy does the child have!Please help ASAP

Answers

Answer:

6000 joules

Explanation:

I jus learned dis

Answer:6000j

Explanation:

Hope that helps

Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Much farther away than two kilometers Much closer than one kilometer About two kilometers away About one kilometer away It is impossible to predict.

Answers

Answer:

About two kilometers away

\rm distance=2.401\ km

Explanation:

Given:

The time gap between the light and sound to travel to the house, t=7\ s

Since the clouds are formed in the troposphere region of the atmosphere which extends from 8 kilometers to 12 kilometers above the earth-surface and the velocity of light is 300000 kilometers per second so it is visible almost instantly, hence we neglect the time taken by the light to travel to the house from the clouds.

∴Distance between the lightning-strike and the house:

\rm distance=v* t

we have the speed of sound as: v=343\ m.s^(-1)

So,

\rm distance=343* 7

\rm distance=2401\ m

\rm distance=2.401\ km