PHYSICS COLLEGE

A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applianceb) the resistance of the heating element in the iron
c) the total cost of running all of the appliances non-stop for 5 days if the electricity rate is $0.1 per KW-Hr.

Answers

Answer 1

Answer:

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

= (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

Answer 2

Answer:

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

Given,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

They all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit.

★Solution of(a)

By using the formula of powerwe can find out the current.

P=V×I

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

[.°.I=P/V]

Here,electriccurrent is inversely proportional to the potential differenceandelectric currentisdirectly proportional topower.

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

★Solutionof(b)

Resistance of Heating coil of Iron

By using theformula of Ohm's Law we can find out the resistance of heatingcoil of iron.

V=I×R

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

[.°.R=V/I]

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R=V/I

=> R = 120/10

.°. R = 12Ω

★Solutionof(c)

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

10.4⁰ and 169.6⁰

Explanation:

The force experienced by the moving electron in the magnetic field is expressed as F = qvBsinθ where;

q is the charge on the electron

v is the velocity of the electron

B is the magnetic field strength

θ is the angle that the velocity of the electron make with the magnetic field.

Given parameters

F = 1.40*10⁻¹⁶ N

q = 1.6*10⁻¹⁹C

v = 3.94*10³m/s

B = 1.23T

Required

Angle that the velocity of the electron make with the magnetic field

Substituting the given parameters into the formula:

1.40*10⁻¹⁶ = 1.6*10⁻¹⁹ * 3.94*10³ * 1.23 * sinθ

1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁹⁺³sinθ

1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁶sinθ

sinθ = 1.40*10⁻¹⁶/7.75392 * 10⁻¹⁶

sinθ = 1.40/7.75392

sinθ = 0.1806

θ = sin⁻¹0.1806

θ₁ = 10.4⁰

Since sinθ is positive in the 1st and 2nd quadrant, θ₂ = 180-θ₁

θ₂ = 180-10.4

θ₂ = 169.6⁰

Hence, the angle that the velocity of the electron make with the magnetic field are 10.4⁰ and 169.6⁰

The brakes of a car moving at 14m/s are applied, and the car comes to a stop in 4s. (a) What was the cars acceleration? (b) How long would the car take to come to a stop starting from 20m/s with the same acceleration? (c) How long would the car take to slow down from 20m/s to 10m/s with the same acceleration?

Answers

(1) The acceleration of the car will be $a=-3.5(m)/(s^2)$

(2) The time taken $t=5.7s$

(3) The time is taken by the car to slow down from 20m/s to 10m/s $t=2.9s$

What will be the acceleration and time of the car?

(1) The acceleration of the car will be calculated as

$a=(v-u)/(t)$

Here

u= 14 $(m)/(s)$

$a=(0-14)/(4) =-3.5(m)/(s^2)$

(2) The time is taken for the same acceleration to 20 $(m)/(s)$

$a=(v-u)/(t)$

$t=(v-u)/(a)$

u=20 $(m)/(s)$

$t=(0-20)/(-3.5) =5.7s$

(3) The time is taken to slow down from 20m/s to 10m/s with the same acceleration

From same formula

$t=(v-u)/(a)$

v=10 $(m)/(s)$

u=20 $(m)/(s)$

$t=(10-20)/(-3.5) =2.9s$

Thus

(1) The acceleration of the car will be $a=-3.5(m)/(s^2)$

(2) The time taken $t=5.7s$

(3) The time is taken by the car to slow down from 20m/s to 10m/s $t=2.9s$

To know more about the Equation of the motion follow

brainly.com/question/25951773

(a) $-3.5 m/s^2$

The car's acceleration is given by

$a=(v-u)/(t)$

where

v = 0 is the final velocity

u = 14 m/s is the initial velocity

t = 4 s is the time elapsed

Substituting,

$a=(0-14)/(4)=-3.5 m/s^2$

where the negative sign means the car is slowing down.

(b) 5.7 s

We can use again the same equation

$a=(v-u)/(t)$

where in this case we have

$a=-3.5 m/s^2$ is again the acceleration of the car

v = 0 is the final velocity

u = 20 m/s is the initial velocity

Re-arranging the equation and solving for t, we find the time the car takes to come to a stop:

$t=(v-u)/(a)=(0-20)/(-3.5)=5.7 s$

(c) $2.9 s$

As before, we can use the equation

$a=(v-u)/(t)$

Here we have

$a=-3.5 m/s^2$ is again the acceleration of the car

v = 10 is the final velocity

u = 20 m/s is the initial velocity

Re-arranging the equation and solving for t, we find

$t=(v-u)/(a)=(10-20)/(-3.5)=2.9 s$

What allows two or more atoms to be held together? shared protons shared electrons shared energy shared neutrons

Answers

It is shared electrons.

The following information should be considered:

In the case when two or more atoms can be together at the time when they share electrons with each other.
By sharing, they create a covalent bond and that way the atoms can be stable.

learn more: brainly.com/question/2514933?referrer=searchResults

Answer:

try electrons i hope this helps!!

Explanation:

Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to construct the clock with a pendulum. The pendulum will be a very thin, very light wooden bar with a thin, but heavy, brass ring fastened to one end. The length of the rod is 80 cm and the diameter of the ring is 10 cm. She is planning to drill a hole in the bar to place the axis of rotation 15 cm from one end. She wants you to tell her the period of this pendulum.

Answers

Answer:

The period of the pendulum is $T = 1.68 \ sec$

Explanation:

The diagram illustrating this setup is shown on the first uploaded image

From the question we are told that

The length of the rod is $L = 80 \ cm$

The diameter of the ring is $d = 10 \ cm$

The distance of the hole from the one end $D = 15cm$

From the diagram we see that point A is the center of the brass ring

So the length from the axis of rotation is mathematically evaluated as

$AP = 80 + 10 -5 -15$

$AP = 70 \ cm = (70)/(100) = 0.7 \ m$

Now the period of the pendulum is mathematically represented as

$T = 2 \pi \sqrt{(AP)/(g) }$

$T = 2 \pi \sqrt{(0.7)/(9.8 ) }$

$T = 1.68 \ sec$

The sun does not normally affect the tides to a noticeable degree. however, under certain circumstances the gravitational pull of the sun does affect the tides. under what two (2) conditions.the sun does not normally affect the tides to a noticeable degree. however, under certain circumstances the gravitational pull of the sun does affect the tides. under what two (2) conditions.

Answers

The answers are :
1) when the sun, moon, and earth are in a line only
2) when the gravitational forces of the Moon and the Sun are
perpendicular to one another with respect to the Earth.

Answer:

High and low tides are result of combined effect of gravitational pull of the sun and the moon. When the two align in a straight line, the range of tides is maximum. This happens on new moon and full moon day.

On the other hand, when the sun and the moon align at right angles, the effect of gravity is minimum and the range of the tides is minimum.

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