PHYSICS COLLEGE

How do you perceive the importance of online safety security ethics and etiquette

Answers

Answer 1

Answer:

Answer:

is called online etiquette, or netiquette for short.

...

Here are some tips to help you get started:

Create Complex Passwords.

Boost Your Network Security.

Use a Firewall.

Click Smart.

Be a Selective Sharer.

Protect Your Mobile Life.

Practice Safe Surfing & Shopping.

Keep up to date.

Related Questions

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You're carrying a 3.6-m-long, 21 kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35 cm from its tip. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A Part complete How much force must you exert to keep the pole motionless in a horizontal position? Express your answer in newtons. F = 114 N Previous Answers
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If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection?

Answers

Answer:

The new angle of deflection north pole becomes smaller.

Explanation: The angle of deflection is the angle formed when an object changes course from its original course of direction or target.

The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.

As the wire is continously being lowered farther from the compass,the angle of deflection of the north pole ontinues to become smaller when compared to its initial deflection.

Assume the following values: d1 = 0.880 m , d2 = 1.11 m , d3 = 0.560 m , d4 = 2.08 m , F1 = 510 N , F2 = 306 N , F3 = 501 N , F4 = 407 N , and MA = 1504 N⋅m . Express the Cartesian components of the resultant force and the couple moment in newtons and newton-meters to three significant figures separated by commas.

Answers

Answer:

= 2630.6 N.m

Explanation:

(FR)x = ΣFx = -F4 = -407 N

(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N

(MR)B =ΣM + Σ(±Fd)

= MA + F1(d1 +d2) + F2d2 - F4d3

= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)

= 2630.64 N.m (counterclockwise)

Final answer:

The Cartesian components of the resultant force and the couple moment are calculated by summing up all the forces and moments acting on the object. The resultant force is 1724 N and the couple moment is 29.764 N*m.

Explanation:

The resultant force and couple moment in the Cartesian coordinate system can be obtained by summing up all the forces and moments acting on the object. In this case, we have the forces F1, F2, F3, F4 and the couple moment MA acting on the object. The resultant force (FR) can be calculated as the sum of all the forces, i.e., FR = F1 + F2 + F3 + F4. Using the values given, FR = 510 N + 306 N + 501 N + 407 N = 1724 N. The resultant moment (MR) can be calculated as the sum of all the moments, i.e., MR = d1*F1 + d2*F2 + d3*F3 + d4*F4 - MA. Using the values given, MR = 0.880 m * 510 N + 1.11 m * 306 N + 0.560 m * 501 N + 2.08 m * 407 N - 1504 N*m = 29.764 N*m. Therefore, the Cartesian components of the resultant force and the couple moment are 1724 N and 29.764 N*m respectively.

Learn more about Resultant force and moment here:

brainly.com/question/34367496

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A truck’s suspension spring each have a spring constant of 769 N/m. If the potential energy of the right front spring is 250 J, how far is the spring compressed?

Answers

The energy stored in the body in a rest state is called potential energy.

There are two types of mechanical energy. The mechanical energy is consist of the following:-

Kinetic energy
Potential energy

According to the question, the solution is:-

The formula we used is $PE= (1)/(2)kx^(2)$

After putting the value the equation is stated as follows:-

$250 =(1)/(2) *769*x^(2)$

Hence the $x^(2)$ is equal to:-

$x^(2) = 651\nx= 0.81$ m

The spring compressed in 0.81m

For more information, refer to the link:-

brainly.com/question/13784481

Answer:

x = 0.81 m

Explanation:

given,

spring constant, k = 769 N/m

Potential energy of the spring = 250 J

distance of spring compression = ?

using conservation of energy

potential energy will equal to the spring energy

$PE = (1)/(2)kx^2$

$250= (1)/(2)* 769* x^2$

x² = 0.650

x = 0.81 m

Hence, the spring is compressed to 0.81 m

HELP ASAP PLEASE!!!In which direction(s) does the ground shake during an earthquake?
A. sideways
B. up and down
C. back and forth
D. all of the above

Answers

Answer: D i am pretty sure

Explanation:

Answer:

all

Explanation:

As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. increases proportionally D. decreases proportionally

Answers

the answer is c. as an object is in motion speeds up or “becomes heavier”, it’s kinetic energy increases proportionally: double the velocity and you quadruple the kinetic energy. this is why a tiny bullet traveling at high speed does so much more damage than a huge truck bumping into something at 1 mph. so the answer is c

Answer:

Explanation:

A 55-liter tank is full and contains 40kg of fuel. Find using Sl units: • Density p. • Specific Weight y • Specific Gravity Answer tolerance = 1%. Be sure to include units. The sign of the answers will not be graded, use a positive value for your answer. Your answers: p= (Enter a positive value) y = (Enter a positive value) SG = (Enter a positive value)

Answers

Answer:

Density of the fuel is 727.3 kilograms per cubic meter.

Specific weight of the fuel is 7127.3 Newtons per cubic meter.

Specific gravity of the fuel is 0,727.

Explanation:

In order to use SI units, we have to convert liters to cubic meters. Knowing that a liter is a cubic decimeter and a cubic decimeter is $1*10^(-3)$ cubic meters, we know that the tank has 0,055 cubic meters of fuel (because it is full).

Now that we have things in SI units, we calculate density:

$p_(fuel)= (mass)/(volume) = (40 kg)/(0.055 m^(3) ) =727.3 (kg )/(m^(3) )$

Knowing the mass per unit of volume, we can calculate weight per unit of volume thanks to Newton's second law (mass times acceleration, g in this case, equals force (weight)), i.e. specific weight:

$y=p*g=727,3 (kg)/(m^(3))*9.8(m )/(s^(2))=7127,3 (N)/(m^(3))$

With density we can also calculate how dense the fuel is related to a reference (water), i.e. specific gravity. SG is a dimensionless number that tell us how much denser (SG>1) or lighter per unit of volume (SG<1) a substance is than water. We use water as a reference because it is one of the most used substances in our life, and it is a standard density (1000 kg per cubic meter at 4°C and 1 atm).

$SG=(p_(fuel) )/(p_(water) ) =(727.3 (kg )/(m^(3) ))/(1000 (kg )/(m^(3) )) =0,727$