8. Follow-up When the ferry leaves Guemes Island and heads backtoward Anacortes, its speed increases from 0 to 5.8 m/s in 9.25 s. What
is its average acceleration?
Answers
The average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².
Given the data in the question;
- Initial speed;
- Final speed;
- Time taken;
To determine the average acceleration, we use the first equation of motion:
Where v is final speed, u is initial speed, a is acceleration and t is time taken.
We substitute our given values into the equation
Therefore, the average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².
Answer:
0.63m/s²
Explanation:
The average acceleration can be derived from using the formula:
V = u + at
Where v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration (m/s²)
t = time (s)
V = u + at
V - u = at
a = v - u/t
a = ∆V/t
According to the provided information; v = 5.8m/s, u = 0m/s, t = 9.25s
a = ∆V/t
a = (5.8-0)/9.25
a = 5.8/9.25
a = 0.627
a = 0.63m/s²
Hence, the average acceleration is 0.63m/s²
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(a) the orange exerts on the apple?
(b) the apple exerts on the orange?
Answers
Final answer:
The orange exerts a gravitational force on the apple, which can be calculated using the formula for gravitational force. The apple exerts an equal and opposite gravitational force on the orange.
Explanation:
(a) The orange exerts a gravitational force on the apple. The magnitude of this force can be calculated using the formula for gravitational force: F = G * (m1 * m2) / r^2, where G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass. Plugging in the values, we have F = (6.67430 x 10^-11 N*m^2/kg^2) * (0.12 kg * 0.20 kg) / (0.75 m)^2. Solving this equation gives us the magnitude of the force of gravity between the orange and apple.
(b) The apple exerts an equal and opposite gravitational force on the orange, as described by Newton's third law of motion. This means that the magnitude of the force of gravity exerted by the apple on the orange is the same as the force of gravity exerted by the orange on the apple.
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Final answer:
The force of gravity between two objects can be calculated using Newton's universal law of gravitation. The force the orange exerts on the apple, and vice versa, is 2.138 x 10^-11 N. However, the apple's force on the orange is in the opposite direction.
Explanation:
The subject of this question is gravity, a fundamental force in physics. The force of gravity between two objects can be calculated using Newton's law of universal gravitation, which states that every point mass attracts every other point mass by a force pointing along the line intersecting both points. The equation is F = G * ((m1*m2)/r^2), where F is the force of gravity between the two objects, G is the gravitational constant (6.674 x 10^-11 N(m/kg)^2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the two objects.
(a) Using this equation, we can find that the force the orange exerts on the apple is F = (6.674 x 10^-11) * ((0.20*0.12)/0.75^2) = 2.138 x 10^-11 N.
(b) According to Newton's third law of motion, every action has an equal and opposite reaction. Thus, the force the apple exerts on the orange is equal in magnitude and opposite in direction to the force the orange exerts on the apple, or -2.138 x 10^-11 N. The negative sign indicates that this force is in the opposite direction.
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Some things you could take into consideration are the weight of the jumpers. There height, well more like overall mass. Gravity would be another key factor. The angle at which she jumped could be another variable. Wind resistance could be another important thing. How far she is attempting to jump is an important variable.
Those are just some of the basic things.
Hope I helped. :)
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Here are the following choices.
A. bar graph
B. line graph
C. histogram
D. scatterplot
The correct answer is "Bar Graph"