What is the value of current when the voltage is 8 volts
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TRUE or FALSE. According to universal gravitation, both mass and air resistance affect the gravitational attraction between objects.
A unit of power equal to 746 watts is a(n)__
Solve the problem.The Bay area of California was shaken by an earthquake on October 17, 1989. The epicenter was located at Loma Prieta. The diameter of the earthquake's horizontal waves that shocked the area measured about 120 miles. How many square miles were affected by this earthquake?
A heater with an effective resistance of 4.8 ohms is connected to 240.0 volts if it operated approximately 25% of the time and electricity costs $0.10 per kWh what will be the electrical bill for30 days
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Answer: melting point.
Explanation:
Freezing point is the temperature at which liquid phase changes to solid phase. Freezing point of water is .
Melting point is the temperature at which solid phase changes to liquid phase. Melting point of water is .
Melting and freezing are reversible processes which takes place at for water.
Boiling point is the temperature at which vapor pressure of the liquid becomes equal to atmospheric pressure.
Sublimation point is the temperature at which gaseous phase changes to solid phase.
Thus the freezing point of water is the same as its melting point.
The freezing point of water is the same as its melting point. (option a)
The freezing point of a substance refers to the temperature at which it changes from a liquid state to a solid state. In the case of water, this is when it turns from liquid water into ice. It's crucial to note that the freezing point of a substance is the same as its melting point, which is the temperature at which the solid changes back into a liquid. So, the answer is option a. The freezing point of water is the same as its melting point.
Hence the correct option is (a).
To know more about freezing point here
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Answer:
8.70 seconds.
Explanation:
1. Use the kinematic equation: v = u + at,
v = final velocity
u = initial velocity
a = acceleration
t = time.
Find variables and numbers:
v = ?
u = 20 m/s
a = -2.3 m²
v = 0 m/s
Rearrange values: t = (v - u) / a.
Plugging in the values: t = (0 - 20) / (-2.3) = 20 / 2.3
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Volume = (1/3) · (pi) · (radius)² · (height).
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Gravitational force = 9.1 x 10⁴ newtons
Mass = 1.1 x 10⁴ kilograms
Gravitational field strength = 9.1 x 10⁴ newtons / 1.1 x 10⁴ kilograms
= ( 9.1 / 1.1) (newton / kilogram)
= 8.3 newton/kg
or 8.3 m/s² .
a. What is the period and frequency of the pendulum’s motion?
b. How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
c. What is the acceleration due to gravity on the surface of the planet in m/s2? Determine the number of g-forces.
Show any necessary calculations.
Answer:
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All this work for 5 points is a big rip-off, but I'm going to try it anyway,
for myself, just to see if I can do it.
a). From the graph, I count 9 complete cycles in 5 seconds.
So the frequency is 9/5 = 1.8 per second = 1.8 Hz.
The period is 1/frequency = 5sec / 9 cycles = 0.555... sec .
b). Velocity = first derivative of displacement = 1/4 cycle behind =
5/36 sec delayed with respect to displacement = 0.13888... sec.
Acceleration = first derivative of velocity = 2nd derivative of displacement =
1/4 cycle behind velocity = 1/2 cycle behind displacement =
5/36 (0.13888...) sec delayed with respect to velocity, =
5/18 (0.2777...) sec delayed with respect to displacement.
c). For small swing angles, the period of an ideal pendulum anywhere is
T = 2pi √(length / local gravity) .
The astronaut has already done the pendulum and transmitted the data to us, so
we can use his data and this formula to calculate the local gravity where he is.
P = 2pi √(length / local gravity)
5/9 sec = 2π √(0.2m / gravity)
√(0.2m / gravity) = 5/9sec / 2π
Take the reciprocal of each side: √(gravity) / √(0.2) = 18π / 5
Multiply each side by √(0.2): √(gravity) = 18π √(0.2) / 5
Square both sides: Gravity = (324 π²) (0.2) / 25 = 25.582 m/sec²
This is about 2.608 times the Earth's gravity. So it should not surprise us
that the astronaut got fed up playing with his pendulum after only 5 seconds,
and went back to his landing capsule to lie down.
Note:
Even though it's a highly classified secret, closely guarded for reasons of
national security and all that stuff, we can be pretty sure that our man has
landed on Jupiter. His data and our calculations have produced a value of
25.582 m/s² for the acceleration of gravity where he is. This compares with
the value of 24.79 m/s² measured by previous robotic space-probe missions
to Jupiter. The difference is less than 3.1% .
The only remaining questions are:
-- How is he managing to sit on top of the planet's gaseous envelope, playing
with his pendulum and staying in radio contact with us, without falling in ?
-- According to the graph, the pendulum was practically at zero displacement
when he released it at Time=0, and the first thing it did when he let go of it
was to swing out to 0.04 radians before turning back. This troubles me.
Either the pendulum was already swinging before Time=0 on this graph,
or else his data have been seriously doctored.