Solve the problem.The Bay area of California was shaken by an earthquake on October 17, 1989. The epicenter was located at Loma Prieta. The diameter of the earthquake's horizontal waves that shocked the area measured about 120 miles. How many square miles were affected by this earthquake?

Answers

Answer 1
Answer: As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
area of a circle =πr*r

d=120
r=120/2r=6060*60=36003600*π=11309.734
11309.734 square miles

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What is the French word for shepherds crook

Answers

The answer would be:

Houlette de berger.
"shepherd's crook"  means   "houlette de berger"  in french

Anxiety disorders are

Answers

An Anxiety disorder is a medical condition characterised by persistent, excessive worry. Anxiety disorders can take a number of forms. Common to all of these is an anxiety so distressing, it can interfere with a person's ability to carry out or take pleasure in day-to-day life.

Energy waves traveling at the speed of light are called _____.conduction particles
convection waves
radiation
atomic energy

Answers

RADIATION

There are three types of heat transfer or heat propagation; conduction, convection and radiation. Heat transfer is the process by which heat projects externally however, depending on the temperature and pressure. Also called the movement of heat from a low temperatured state which increases as heat progresses.
Conduction is the heat transfer by contact, immediate contact.
Convection is the transfer of heat through air and water.
Radiation is the transfer of heat regardless of the presence of atoms or particles.

Radiation is the answer.


Natalie and Will are discussing socialization. Natalie says that socialization occurs when an animal becomes accustomed to the people in the household. Will says that socialization is easily attained if the animal is first exposed to humans after 12 weeks of age. Who is correct?A. Only Natalie
B. Only Will<~~~My answer and its wrong :(
C. Neither Natalie nor Will
D. Both Natalie and Will

Answers

The correct answer for this question is this one: "C. Neither Natalie nor Will." Natalie and Will are discussing socialization. Natalie says that socialization occurs when an animal becomes accustomed to the people in the household. Will says that socialization is easily attained if the animal is first exposed to humans after 12 weeks of age.

Answer:

A. only Natalie

Explanation:

The answer above is wrong. The correct answer is A "only Natalie" because the socialization process, while best done during the 2-12 weeks, it does not happen onlyin that period. As long as the animal gets accustomed to living in the household, it is being socialized

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 13 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 22 cm such that the combination does not rotate?

Answers

Answer:

F_2 = 29.54 N

Explanation:

As we know that the combination is maintained at rest position

So we will take net torque on the system to be ZERO

so we know that

\tau = \vec r * \vec F

here we will have

\vec r_1 * F_1 = \vec r_2 * F_2

so we have

13 * 50 = 22 * F_2

so we have

F_2 = (13 * 50)/(22)

F_2 = 29.54 N

Final answer:

The concept of torques and equilibrium is used to calculate the pulling force on the larger flywheel, which is found to be approximately 29.55 Newtons. This force will balance the system and prevent it from rotating.

Explanation:

To solve this problem, we need to understand the concept of torque and equilibrium. We know that torque (τ) is the rotational equivalent of linear force. It's calculated by the formula τ = force × radius. Thus, for the system to stay at equilibrium (not rotate), the torques need to balance each other out.

On the smaller flywheel, the torque τ₁ is given by the pulling force (F₁ = 50 N) and the radius (r₁ = 13 cm, or 0.13 m), hence τ₁ = F₁ × r₁ = 50 N x 0.13 m = 6.5 N.m.

In order for the system to stay at equilibrium, the same amount of torque needs to be applied to the larger flywheel. We already know the radius of the larger flywheel (r₂ = 22 cm, or 0.22 m). To keep the system at equilibrium, the pulling force F₂ on the larger flywheel should be such that the torque τ₂ = τ₁ = 6.5 N.m. From the formula τ = F × r, we can solve for F₂ as follows: F₂ = τ₂ / r₂ = 6.5 N.m / 0.22 m = 29.55 N, approximately. Therefore, a pulling force of about 29.55 N should be applied to the cord connected to the larger flywheel to prevent the system from rotating.

Learn more about Torques and Equilibrium here:

brainly.com/question/34217227

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When using a film camera, what must you do to bring an object into focus?a.move the lens toward or away from the film.
b.close the diaphragm.
c.adjust the speed of the shutter.
d.adjust the angle of the mirror.

Answers

Answer:

a. move the lens toward or away from the film.

Explanation:

Lets discuss the function of different components of the camera

a). Lens : Lens position is set to focus the image on the film as we know that

(1)/(d_i) + (1)/(d_0) = (1)/(f)

here we know that position of lens can adjusted by changing the value of distance from object and that will help to focus the image on the film.

b).  diaphragm. = It is used to control the intensity of light to enter into the lens so that light is adjusted.

c). speed of the shutter = By changing the speed of shutter we can control the light entering into the lens which can control the brightness of picture

d) Angle of mirror : by adjusting the angle of mirror we can set the orientation of the image that is formed

Answer:

option (A) is correct

Explanation:

To bring the object in focus, you can change  the distance between the film and the lens by moving the lens towards or away from the film.

As the lens is used to click the pictures of objects which are placed at different distances from the camera.

By using the lens formula

1 / f = 1 / v - 1 / u

Where, f is the focal length of the lens, u be the distance between lens and the object and v be the distance between image and the lens.

We can say that f is constant and u is constant so, we have  to change the value of v that means the distance between the lens and the film to focus the images of the objects on the film.