Answer:
The mass per unit volume percentage is equal to 3.43%
Explanation:
given
mass=7 grams
volume = 2 * 102 ml = 204ml
The percentage mass per volume is given by
%(m/v) = w grams of solute * 100 / Volume of solution in ml
=
= 3.43%
The percent mass/volume (% m/v) for a solution containing 7.00 g of dextrose in 2.00×102 mL of solution is calculated as (7.00 g / 2.00×102 mL) * 100 = 3.47%, so the dextrose solution is 3.47% m/v.
The percent mass/volume (% m/v) is a way of expressing the concentration of a solute in a solution. It is calculated as the mass of the solute divided by the volume of the solution, multiplied by 100%. In this case, to calculate the % m/v for a solution that contains 7.00 g of dextrose in 2.00×102 mL of solution, you would use the following equation:
% m/v = (mass of solute / volume of solution) * 100
Substituting the given values into this equation, you get:
% m/v = (7.00 g / 2.00×102 mL) * 100 = 3.47%
Therefore, the dextrose solution is 3.47% m/v.
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The number of water molecules in a 1.50 mol block of ice is calculated by multiplying the number of moles of water by Avogadro's number. The result is approximately 9.033 x 10^23 water molecules.
In chemistry, the amount of substance in moles is related to the number of particles (atoms, molecules) through Avogadro's number. Avogadro's number, which is 6.022 x 1023 particles/mol, tells us the number of molecules in one mole of a substance.
To calculate the number of water molecules in 1.50 mol of water, you would multiply the number of moles of water by Avogadro's number:
1.50 mol of water x 6.022 x 1023 water molecules/mol of water = 9.033 x 1023 water molecules
Therefore, there are approximately 9.033 x 1023 water molecules in a 1.50 mol block of ice.
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Answer:
The three subatomic particles are the particles contained in the iota. They are protons, neutrons, and electrons. Protons and electrons convey a positive and negative charge, individually, while neutrons don't convey any change
Explanation:
217g of water.
What is the molality of the solution?
Answer:
THE MOLARITY IS 2.22 MOL/DM3
Explanation:
The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water
Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol
Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;
37.5 g of Na2S = 217 g of water
( 37.5 * 1000 / 217 ) g = 1000 g of water
So, 172.81 g/dm3 of the solution
So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass
Molarity = 172.81 g/dm3 / 78 g/mol
Molarity = 2.22 mol/dm3
The molarity of the solution is 2.22 mol/dm3
Answer:
The answer is 2.22mol
Explanation:
The answer is; Transverse waves
Fiber optic cables transmit information using monochromatic light pulses. All electromagnetic waves (light included) are transverse waves. This means that the particles move perpendicular to the direction of the wave. This is unlike sound waves that are longitudinal waves (particles move parallel to the direction of the wave).
Fiber optic cables transmit data using light waves, which are essentially electromagnetic waves. The wave characteristics of light, especially total internal reflection, interference, and diffraction, facilitate effective data transmissions through these fibers. Factors like high bandwidth, low signal loss, and reduced crosstalk further contribute to their advantage over traditional cables.
Based on the principles of optics, electromagnetic waves, particularly light waves, are what you could find in a fiber optic cable. Fiber optic cables work by transmitting data as pulses of light through strands of fiber made from glass or plastic. This process utilizes the characteristic phenomenon of total internal reflection. When light rays enter the fiber, they bounce off the walls of the fiber cable, undergoing multiple total internal reflections, which ensures that no light escapes the fiber and all signals are conveyed effectively.
Light's wave characteristics are crucial in enabling this functionality. The wave nature of light helps explain properties such as interference and diffraction, essential for the transmission of data in fiber optic networks. These principles are especially relevant when light interacts with small objects such as the core/cladding of the fiber, a subject area often referred to as wave or physical optics.
Another advantage is the high bandwidth of fiber optics, made possible because lasers can emit light with characteristics that allow far more data transmission than electric signals on a single conductor. Meanwhile, properties like low loss and reduced crosstalk enhance the functional superiority of fiber optic cables over traditional copper cable systems.
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Answer:
Explanation:
When an electron moves from a lower energy level to a higher energy level, energy is absorbed by the atom. When an electron moves from a higher to a lower energy level, energy is released and photon is emitted.
this emitted photon is depicted as a small wave-packet being expelled by the atom in a well-defined direction.
Answer:
The answer is: true
Explanation:
In redox reactions, the half-reactions of oxidation and reduction always occur simultaneously in pair.
The oxidation half-reaction involved the lost of electrons from a reduced substance (A) to form a oxidized substance (A⁺):
A ⇒ A⁺ + e-
In contrapossition, during the reduction half-reaction the oxidized substance (B⁺) gains electrons to form the reduced subtance (B):
B⁺ + e- ⇒ B
The overall redox reaction is obtained by the addition of the two half-reactions:
A ⇒ A⁺ + e-
B⁺ + e- ⇒ B
-----------------
A + B⁺⇒ A⁺ + B
The electrons gained by B are provided by A, which lost the same number of electrons. Thus, the oxidation/reduction reactions are paired.
Yes, it's true that an oxidation reaction always pairs with a reduction reaction, thereby making up a redox reaction where one substance is oxidized (loses electrons) and another is reduced (gains electrons). The oxidized species is the reducing agent while the reduced one is the oxidizing agent.
The statement is true: an oxidation reaction is indeed always paired with a reduction reaction. This can be exemplified in the redox reactions where one substance is oxidized (loses electrons) while another is reduced (gains electrons). These reactions always occur together. The species that is oxidized is called the reducing agent, while the species that is reduced is called the oxidizing agent. Therefore, in every redox reaction, there will always be an oxidation process coupled with a reduction process.
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