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Consider the balanced equation for the following reaction:7O2(g) + 2C2H6(g) → 4CO2(g) + 6H2O(l)
Determine the amount of CO2(g) formed in the reaction if 8.00 grams of O2(g) reacts with an excess of C2H6(g) and the percent yield of CO2(g) is 90.0%.

Answers

Answer 1

Answer:

Answer: The amount of carbon dioxide formed in the reaction is 5.663 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=(8g)/(32g/mol)=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $(4)/(7)* 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\n\n\text{Mass of carbon dioxide}=(0.143mol* 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}* 100\n\n\text{Experimental yield of carbon dioxide}=(90* 6.292)/(100)=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

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Which description is not a property of a base? (2 points)a
pH lower than 7

b
Turns litmus paper blue

c
Bitter taste

d
Slimy feel

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i think it’s A
because if the pH is lower than 7 than it is acidic

Answer:

the answer is a hope it helps.

Explanation:

Briefly explain why sublimation occurs.

Answers

Answer:

Sublimation is basically cause by the heat absorption and this process is an endothermic since it require extra energy.

It basically provide sufficient energy to molecules to control the various type of attractive forces from the neighbors and then convert it into the vapor phase.

Sublimation occur when the particle of gases become cold because some substances has high vapor pressure. Sublimation is the endothermic change and it occur below the triple point in terms of pressure and temperature.

Which aqueous solution is colored?1.
CuSO4(aq)
2.
BaCl2(aq)
3.
KCl(aq)
4.
MgSO4(aq)

Answers

Answer: Copper (II) Sulfate! (CuSO4)

Explanation:

This is because compared to the other salts, it is the visible color blue. The other ones are plain white. Happy holidays! Don’t stress :)

50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximately 1. 74 X 10 -5. What is the pH of the resulting solution?

Answers

Answer:

4.76

Explanation:

In this case, we have to start with the buffer system:

$CH_3COOH~->~CH_3COO^-~+~H^+$

We have an acid ( $CH_3COOH$ ) and a base ( $CH_3COO^-$ ). Therefore we can write the henderson-hasselbach reaction:

$pH~=~pKa+Log([CH_3COO^-])/([CH_3COOH])$

If we want to calculate the pH, we have to calculate the pKa:

$pH=-Log~Ka=4.76$

According to the problem, we have the same concentration for the acid and the base 0.1M. Therefore:

$[CH_3COO^-]=[CH_3COOH]$

If we divide:

$([CH_3COO^-])/([CH_3COOH])~=~1$

If we do the Log of 1:

$Log~1=~zero$

So:

$pH~=~pKa$

With this in mind, the pH is 4.76.

I hope it helps!

Determine the rate of a reaction that follows the rate law:rate = k[A]”[B]", where:
k= 1.5
[A] = 1 M
[B] = 3 M
m = 2
n = 1

Answers

The rate of the reaction is 4.5 mol L⁻¹s⁻¹.

What is meant by rate of a reaction ?

Rate of a reaction is defined as the change in concentration of any one of the reactants or products of the reaction, in unit time.

Here,

The concentration of A, [A] = 1 M

The concentration of B, [B] = 3 M

The partial order with respect to A, m = 2

The partial order with respect to B, n = 1

The rate constant of the reaction, k = 1.5

The rate of the reaction,

r = k[A]^m [B}^n

r = 1.5 x 1² x 3

r = 4.5 mol L⁻¹s⁻¹

Hence,

The rate of the reaction is 4.5 mol L⁻¹s⁻¹.

To learn more about rate of a reaction, click:

brainly.com/question/29049197

#SPJ2

Answer:

k= 1.5

[A] = 1 M

[B] = 3 M

m = 2

n = 1

Explanation:

rate = k[A]”[B]"

1. What is the angular distance north or south from the earth's equator beginning at0° at the equator and ending at 90° at either pole?
a. Weather
b. Altitude
c. Latitude
d. Climate

Answers

Answer:

c. Latitude

Explanation:

The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.

The equator is a line of latitude that divided the earth into two hemispheres.

Only the equator is a great circle as a line of latitude. Others are small circles.

Weather is the atmospheric condition of a place over a short period of time
Climate is the average weather condition at a place over a long period of time.
Altitude of a place is its elevation above a reference plane.

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Consider the balanced equation for the following reaction:7O2(g) + 2C2H6(g) → 4CO2(g) + 6H2O(l)Determine the amount of CO2(g) formed in the reaction if 8.00 grams of O2(g) reacts with an excess of C2H6(g) and the percent yield of CO2(g) is 90.0%.

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What is meant by rate of a reaction ?

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Consider the balanced equation for the following reaction:7O2(g) + 2C2H6(g) → 4CO2(g) + 6H2O(l)
Determine the amount of CO2(g) formed in the reaction if 8.00 grams of O2(g) reacts with an excess of C2H6(g) and the percent yield of CO2(g) is 90.0%.