NEED THIS QUESTION ASAP!

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Answer 1

Answer:

Answer:

1. The last one

2. The third one

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Division time :) and i'm stuck with this.
1. Line L passes through point (-1, 2) and (-3,-2) on a coordinate plane. LineM passes through the points (1.1) and (-1, W). For what value of W will makeline L and line M parallel.
Which point represents the value of –(–2) on the number line?
PLS HELPPP ITS NOT THAT HARD
You can use both the t statistic and the z statistic to test hypotheses about the mean of population. The test that uses the t statistic is typically referred to as a t test, while the test that uses z statistic is commonly called a z test. Which of the following statements are true of the t statistic? Check all that apply. The t statistic uses the same formula as the z statistic except that the t statistic uses the estimated standard error in the denominator. The t statistic provides an excellent estimate of z, particularly with small sample sizes. The formula for the t statistic is t = (M – μ) / σM. The t statistic does not require any knowledge of the population standard deviation.

Hey can you please help me posted picture of question

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The correct option is (B) $16x^2 + 8x + 1$

Explanation:
Add all the boxes:
There are 16 (x^2) boxes;
There are 8 (x) boxes;
And the constants = 1

So it becomes:
$16x^2 + 8x + 1$

And the product is (4x+1)(4x+1)
4x(4x+1) + 1(4x+1)
16x^2 + 4x + 4x + 1
$16x^2 + 8x + 1$ (Same)

The directional derivative of f(x, y) at (2, 1) in the direction going from (2, 1) toward the point (1, 3) is −2/ √ 5, and the directional derivative at (2, 1) in the direction going from (2, 1) toward the point (5, 5) is 1. Compute fx(2, 1) and fy(2, 1

Answers

Answer:

the partial derivatives are

fx =5/9

fy =(-13/18)

Step-by-step explanation:

defining the vector v (from (2,1) to (1,3))

v=(1,3)-(2,1) = (-1,2)

the unit vector will be

v'=(-1,2)/√5 = (-1/√5,2/√5)

the directional derivative is

fv(x,y) = fx*v'x + fy*v'y = fx*(-1/√5)+fy(2/√5) =-2/√5

then defining the vector u ( from (2, 1) toward the point (5, 5) )

u=(5,5)-(2,1) = (3,4)

the unit vector will be

u'=(3,4)/5 = (3/5,4/5)

the directional derivative is

fu(x,y) = fx*ux + fy*uy = fx*(3/5)+fy(4/5)=1

thus we have the set of linear equations

-fx/√5*+2*fy/√5 =(-2/√5) → -fx + 2*fy = -2

(3/5) fx+(4/5)*fy=1 → 3* fx+4*fy = 5

subtracting the first equation twice to the second

3*fx+4*fy -(- 2fx)*-4*fy = 5 -2*(-2)

5*fx=9

fx=5/9

thus from the first equation

-fx + 2*fy = -2

fy= fx/2 -1 = 5/18 -1 = -13/18

thus we have

fx =5/9

fy =(-13/18)

Suppose you are climbing a hill whose shape is given by the equation z = 900 − 0.005x2 − 0.01y2, where x, y, and z are measured in meters, and you are standing at a point with coordinates (120, 80, 764). The positive x-axis points east and the positive y-axis points north. (a) If you walk due south, will you start to ascend or descend? ascend descend Correct: Your answer is correct.

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Answer:

Ascend

Step-by-step explanation:

In order to solve this problem, we are going to use some principles of vector calculation. The concepts we are going to use are Partial derivatives, gradient vector, velocity vector, direction vector, and directional derivative.

The gradient vector is a vector that describes how is the 'slope' in the space of a multivariable function at a specified point; it is built as a vector of partial derivatives. The vector velocity is a vector that describes the direction and speed of the movement of a body, if we make the velocity a unitary vector (a vector whose norm is 1), we obtain the direction vector (because we are not considering the real norm of the vector, just direction). Finally, the directional derivative is a quantity (a scalar) that describes the slope that we get on a function if we make a displacement from a particular point in a specific direction.

The problem we have here is a problem where we want to know how will be the slope of the hill if we stand in the point (120, 80, 764) and walk due south if the hill has a shape given by z=f(x,y). As you see, we have to find the directional derivative of z=f(x,y) at a specific point (120, 80, 764) in a given displacement direction; this directional derivative will give us the slope we need. The displacement direction 'u' is (0,-1): That is because 'y' axis points north and our displacement won't be to the east either west (zero for x component), just to south, which is the opposite direction of that which the y-axis is pointing (-1 for y component). Remember that the direction vector must be a unitary vector as u=(0,-1) is.

Let's find the gradient vector:

$z=900-0.005x^2-0.01y^2\n(\partial z)/(\partial x)=-0.005*2*x=-0.01x\n(\partial z)/(\partial y)=-0.01*2*y=-0.02y\n \nabla (z)=(-0.01x,-0.02y)$

Evaluate the gradient vector at (120,80) (764 is z=f(120,80); you may confirm)

$\nabla (z(120,80))=(-0.01*120,-0.02*80)=(-1.2,-1.6)$

Finally, find the directional derivative; if you don't remember, it can be found as a dot product of the gradient vector and the direction vector):

$D_(u,P_0)= \nabla (z)_(P_0)\cdot u\nD_(u,P_0)= (-1.2,-1.6)\cdot (0,-1)=1.6$

As you see, the slope we find is positive, which means that we are ascending at that displacement direction.

Need Help Fast!!!!!!!!!!!!!!!!!!

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7.2, 3, 8.09, 2.22, 5.06, 2.5

Help to solve y'''-y''-4y'+4y=5-e^x+e^2x

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By solving the equation " $y'''-y''-4y'+4y=5-e^x+e^2x$ " we get " $y = Ae^x+Be^(2e)+Ce^(-2x)+(5)/(4)+(xe^x)/(3) +(xe^(2x))/(4)$ ".

As we know the auxiliary equations,

$m^3-m^2-4m+4=0$
$(m-1)(m-2)(m+2) =0$

here,

m = 1, 2, -2

Thus,

The general equation will be:

→ $y = Ae^x+Be^(2x)+Ce^(-2x)$

Particularly,

$5 = (5)/(4)$
$e^x= x((1)/(1-4)e^x ) = -(xe^x)/(3)$
$e^(2x) = x((e^(2x))/((2+2)(2-1)) )= (xe^(2x))/(4)$

hence,

The complete equation will be:

→ $y = Ae^x+Be^(2e)+Ce^(-2x)+(5)/(4)+(xe^x)/(3) +(xe^(2x))/(4)$

Thus the above answer is right.

Learn more:

brainly.com/question/22449567

Answer:

Step-by-step explanation:

First of all write the auxialary equation as

$m^3-m^2-4m+4 =0\n(m-1)(m-2)(m+2)=0$

m=1,2,-2

Hence general solution is

$y=Ae^x+Be^(2x) +Ce^(-2x)$

Particular solution of 5 is

$(5)/(4)$

Particular solution of e^x is

$x((1)/(1-4) e^x =(-xe^x)/(3)$

Particular solution of e^2x is

$x(e^(2x) )/((2+2)(2-1)) =(xe^(2x) )/(4)$

Together full solution is

$y=Ae^x+Be^(2x) +Ce^(-2x)+(5)/(4) +(xe^x)/(3) +(xe^(2x) )/(4)$

In triangle JKL, if angle J is seven less than angle L and angle K is 21 less than twice angle L, find the measure of each angle

Answers

The measure of the angles are; J = 48, K = 57 and L = 75

What is linear pair?

Linear pair of angles are produced when two lines intersect each other at a point. The sum of angles of the linear pair is always 180 degrees.

In order to determine the measure of these angles, we have to set J as x. then find the measure of all of these angles.

J = x

K = x + 9

L = 2x - 21

Now, we can add them all together and set equal to 180;

x + x + 9 + 2x - 21 = 180

4x - 12 = 180

4x = 192

x = 48

Now that we have;

J = x = 48

K = x + 9 = 48 + 9 = 57

L = 2x - 21 = 2(48) - 21 = 96 - 21

L = 75

Hence, The measure of the angles are; J = 48, K = 57 and L = 75

Learn more about angles;

brainly.com/question/7116550

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Answer:

j=45 k=83 L=52

Step-by-step explanation:

j=x-7

k=2x-21

L=x

x-7+2x-21+x=180

4x-28=180

4x=208

x=52

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(1 point) The number of households with cable TV service in a certain community, N, begins at only 55 households and has seen a fivefold increase every 17 years. Give the constants a, b, and T so that N is represented by a function of the form N=abt/T, where t is the time in years since N was first measured.