Why might a job that pays 1,000/hour not be enough to live on? PLEASE HELP WILL MARK BRAINLIEST!

Answers

Answer 1
Answer: Because of other expenses such as taxes, bills, etc
Answer 2
Answer:

Answer:

you only work for one hour OR the money is inflated

Step-by-step explanation:

if you work for a small amount of time it is not enough money and if it is inflated the money is worth less


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A+b+c+d=770
a+b=c+d
a-b=49
c-d=211
Find numbers.

Answers

a+b = c+d
a+b = 770/2    ( a+b+c+d = 770)
a+b = 385
c+d = 385

a+b+a-b = 385+49
         2a  = 434
           a  = 434/2
           a  = 217
 a-b=49
217-49= b
b         = 168

c+d+c-d = 385+211
         2c = 596
           c = 596/2
           c = 298

c-d = 211
c-211= d
298-211 = d
           d  = 87

Therefore, a=217, b=168, c=298, d=87

Please help me solve this guys
I’m really struggling

Answers

Answer:

(y - 1) = 4(x +1)

Step-by-step explanation:

slope =  4

B = -4

given point (-1,1)

y = 4x -4 (this is the slope intercept form)

(Y - Y_(1 )) = M (X - X_(1) ) (point slope form)

(y - 1) = 4(x +1) ... that is the point slope form

Work out the value of 3c-4d when c=5 and d= ½

Answers

3(5) - 4(1/2)
15 - 2 = 13

When exercising Alison Berns 120 cal every 15 minutes how many calories does Allison burn during 75 minutes

Answers

120x75=9000

Hope this helps

Which of the number(s) below are potential roots of the function?p(x) = x4 + 22x2 – 16x – 12

Answers

Potential\ roots\ of\ the\ function:\n\np(x)=x^4+22x^2-16x-12\ are:\n\n\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\}

Answer:

6,1,3

Step-by-step explanation:

1. You and a friend both would like a salad and a small drink. Between the two of you you have $8.00. A salad costs $2.49 and a small drink is $0.99. Can either of you have a second salad or a drink? (1 point)yes, one salad
yes, one of each
yes, one drink
no, you cannot

Answers

C. One drink. Total would be $6.96(2 salads 2 drinks). Adding 1 more drink(salads are out of the question) would make it $7.95

Answer:

1. C

2. D

3. C

4. D

Step-by-step explanation: