Why We can’t Cure Aging? Support your answer?

Answers

Answer 1

Answer: We can’t cure aging because it is inevitable. Aging is a part of life and it leads to death which is also inevitable and inescapable. We can’t stop our aging because it is natural and normal to age

Related Questions

A particle (q = 5.0 nC, m = 3.0 μg) moves in a region where the magnetic field has components Bx = 2.0 mT, By = 3.0 mT, and Bz = −4.0 mT. At an instant when the speed of the particle is 5.0 km/s and the direction of its velocity is 120° relative to the magnetic field, what is the magnitude of the acceleration of the particle in m/s2?
A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10.0 m/s. The instant before the stone hits the ground below, it is traveling at a speed of 30.0 m/s. If the physics student were to throw the rock horizontally outward from the cliff instead, with the same initial speed of 10.0 m/s, what is the magnitude of the velocity of the stone just before it hits the ground? Ignore any effects of air resistance.
A straight trail with a uniform inclination of 16° leads from a lodge at an elevation of 600 feet to a mountain lake at an elevation of 7,000 feet. What is the length of thetrail (to the nearest foot)?O A. 6,658 ftOB. 25,396 ftOC. 7,282 ftOD. 23,219 ft
Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was ?s = 1. Around 1962, three companies independently developed racing tires with coefficients of 1.6. This problem shows that tires have improved further since then. The shortest time interval in which a piston-engine car initially at rest has covered a distance of one-quarter mile is about 4.43 s. (A) Assume the car's rear wheels lift the front wheels off the pavement as shown in the figure above. What minimum value of ?s is necessary to achieve the record time?
Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the transition from n=3 to n= 2.

An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency. the electric field has amplitude 7.20×10−3v/m.what is the intensity of the wave in a medium\?

Answers

The intensity of the electromagnetic wave which travels in an insulating magnetic material in a medium is 5.766×10⁻⁸ W/m².

What is the intensity of the wave?

The intensity of a wave is the total power delivered per unit area. It can be given as,

$I=(P)/(A)$

It can also be given as,

$I=(E^2)/(2)\sqrt{(k\varepsilon_o)/(\mu_r\mu_o)}$

Here, ( $\mu_r$ ) is relative permeability, ( $\mu_0$ ) is physical constant, (k) is dielectric constant, (E) is the amplitude of electric field, and $\varepsilon_o$ is the permittivity of free space.

Here, the electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency.

As the electric field has amplitude 7.20×10−3v/m. Thus, put the values in the above formula to find the intensity as,

$I=((7.20*10^(-3))^2)/(2)\sqrt{(3.64*8.85*10^(-12))/(5.18*(4\pi*10^(-7)))}\nI=5.766*10^(-8)\rm W/m^2$

Hence, the intensity of the electromagnetic wave which travels in an insulating magnetic material in a medium is 5.766×10⁻⁸ W/m².

Learn more about the intensity of the wave here;

brainly.com/question/18109453

Ans: Intensity = I = $5.8 * 10^(-8) W/m^2$

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = $\sqrt{ (1)/(\mu\epsilon) }$

v = $\sqrt{ (1)/(\mu_r\mu_ok\epsilon_o) }$
$\mu_r = 5.18 \n\mu_o = 4 \pi * 10^(-7) \nk = 3.64 \n\epsilon_o = 8.85 * 10^(-12)$

Plug in the values:
v = $\sqrt{ (1)/((5.18)(4\pi*10^(-7))(3.64)(8.85*10^(-12))) }$
v = $6.9 * 10^7$ m/s

Now that we have "v", we can use the following formula to find the intensity of wave:

$I = (k\epsilon_o*v*E_(max)^2)/(2)$

$I = ((3.64)(8.85*10^(-12))*(6.9*10^7)*(7.20*10^(-3))^2)/(2)$

Intensity = I = $5.8 * 10^(-8) W/m^2$

3. Which object has more inertia?A. A tractor trailer rig moving at 2 m/s
B. A pingpong ball rolling a 2 m/s
C. A bowling ball rolling at 1m/s
D. A car rolling at 5 m/s

Answers

Answer:

A. A tractor trailer rig moving at 2 m/s

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of an object such as a tractor trailer rig is greatly dependent or influenced by its mass; the higher quantity of matter in a tractor trailer rig, the greater will be its tendency to continuously remain at rest.

Hence, the object that has more inertia is a tractor trailer rig moving at 2 m/s because it has more mass than all the other objects in the category. Also, the mass of an object is directly proportional to its inertia.

Find the magnitude and direction of an electric field that exerts a 4.80×10−17N westward force on an electron. (b) What magnitude and direction force does this field exert on a proton?

Answers

a). The magnitude along with the direction of the electric field releasing westward force of $4.80$ × $10^(-17)$ N would be:

$3$ × $10^(-36)$ N/C is Eastward Direction

b). The magnitude along with the force of the direction that this field releases on proton would be:

$4.8$ × $10^(17) N$ in Eastward Direction

Electric Field

a). Given that,

Force $=$ $4.80$ × $10^(-17)$ N

As we know,

Force $=$ Charge × Electric Field

So,

∵ Electric Field $= Force/Charge$

$= 4.8$ × $10^(17)$ ) $/(1.6$ × $10^(-19)$ $)$

$= 3$ × $10^(36)N/C$

The direction of the field would be opposite i.e. Eastward direction due to the field carrying a -ve charge.

b). The magnitude carried by the force working on the proton would be the same with an opposite direction due to +ve charge.

∵ Force $=$ $4.80$ × $10^(-17)$ N in Eastward direction.

Learn more about "Magnitude" here:

brainly.com/question/9774180

Explanation:

(a) E = F/q

E = 4.8×10^-17/1.6×10^-19

E = 300 N/C

(b) same magnitude of electric field is exerted on proton

A body of mass 80kg was lifted vertically through a distance of 5.0 metres. Calculate the work done on the body. ( Acceleration due to gravity g=10ms²)

Answers

Answer:

80×5×10=4000J

so therefore, work done on the body is 4000J

A large aquarium has portholes of thin transparent plastic with a radius of curvature of 1.95 m and their convex sides facing into the water. A shark hovers in front of a porthole, sizing up the dinner prospects outside the tank.a) If one of the sharks teeth is exactly 46.5 cm from the plastic, how far from the plastic does it appear to be to observers outside the tank? (You can ignore refraction due to the plastic.)b) Does the shark appear to be right side up or upside down?c) If the tooth has an actual length of 5.00 cm, how long does it appear to the observers?

Answers

Answer:

Explanation:

For refraction through a curved surface , the formula is as follows

μ₂ / v - μ₁ / u = (μ₂ -μ₁ )/R , Here μ₂( air) = 1 , μ₁ ( water) = 4/3 , R = 1.95 m

u , object distance = - .465 m

1 / v + 1.333 / .465 = (1 -1.333 )/1.95

1 / v + 2.8667 = - .171

1 / v = - 2.8667 - .171 = - 3.0377

v = - .3292 m

= - 32.92 cm

image will be formed in water.

c ) magnification = μ₁v / μ₂u , μ₁ = 1.33 , μ₂ = 1 , u = 46.5 , v = 32.92 .

= (1.33 x 32.92) / (1 x 46.5)

= .94

size of image of teeth = .94 x 5

= 4.7 cm .

An object moving with uniform acceleration has a velocity of 10.5 cm/s in the positive x-direction when its x-coordinate is 2.72 cm. If its x-coordinate 2.30 s later is ?5.00 cm, what is its acceleration? The object has moved to a particular coordinate in the positive x-direction with a certain velocity and constant acceleration; then it reverses its direction and moves in the negative x-direction to a particular x-coordinate in time t. We are given an initial velocity vi = 10.5 cm/s in the positive x-direction when the initial position is xi = 2.72 cm (t = 0). We are given that at t = 2.30 s, the final position is xf = ?5.00 cm. The acceleration is uniform so that we have the following equation in terms of the constant acceleration a. Xf-Xi=Vit-1/2at^2 Now we substitute the given values into this equation. (___cm)-(___cm)=(___cm/s)(__s)+1/2a(___s)

Answers

Answer:

Acceleration = 8.27 cm/s²

Explanation:

We are given;

initial velocity; v_i = 10.5 cm/s

Initial position; x_i = 2.72 cm

Time; t = 2.30 s

final position; x_f = 5.00 cm

To find the acceleration, we will make use of the formula;

x_f - x_i = (v_i * t) - (½at²)

Plugging in the relevant values, we have;

5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)

2.28 = 24.15 - 2.645a

24.15 - 2.28 = 2.645a

2.645a = 21.87

a = 21.87/2.645

a = 8.27 cm/s²

Using the kinematic equation, the acceleration of the object was calculated to be approximately8.27 cm/s² given its initial velocity, position, time, and final position.

We are given:

Initial velocity (vᵢ) = 10.5 cm/s

Initial position (xᵢ) = 2.72 cm

Time (t) = 2.30 seconds

Final position ( $x_f$ ) = 5.00 cm