5. A lawnmower designer wants to build a lawnmower that measures 3 feet in height, 2 feet in width, and 5 feet in length. She needs to construct a three-dimensional scale model of the lawnmower first. Which measurements are appropriate for the scale model?-7in high, 6in wide, and 9in long
-6in high, 4in wide, and 10in long
-9in high, 4in wide, and 10in long
-9in high, 6in wide, and 10in long​

Answers

Answer 1
Answer:

Answer:

The second one. 6in high, 4in wide, and 10 long


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The width of a rectangle is two-thirds of its length, and its area is 216 square meters. What is the length? is it 27 or 12

Answers

Answer:

The length of rectangle =18 m.

Step-by-step explanation:

Suppose of length of rectangle=x

Width of rectangle =(2)/(3)x

Area of rectangle =216 m^2

We have to find the length of rectangle .

Area of rectangle =length* breadth

Substitute the values in the given formula

216=x* (2)/(3)x

216=(2)/(3)x^2

2x^2=216* 3 By multiplication property of equality

x^2=(216* 3)/(2) ( by division property of equality )

x=√(324)=18

Substitute the value then we get

Width of rectangle =(2)/(3)* 18=12 m

Hence, the length of rectangle =18 m.

Suppose a city with population 500,000 has been growing at a rate of 7% per year. If this rate continues, find the population of this city in 11 years.

Answers

use compound interest formula.........m

I need help figuring out how to find AC I'm not very good at this part.​

Answers

Answer:

AC= 33

Step-by-step explanation:

AC= ABC = 25+8

The tub of a washer goes into its spin cycle, starting from rest and gainiing angular speed steadily for 8.0 s when it is turning at 5.0 rev/s. At this time the person doing the laundry opens the lid and a safety switch turns off the washer. The tub smoothly slows to rest in 12.0 s. Through how many revolutions does the tub turn whil it is in motion.

Answers

Angular acceleration is change of angular velocity over time:
α = 5 / 8 = 0.625 rev / s²
Number of revolutions of the 1st part:
α · t² /2 = 0.625 * 8² / 2 = 20 rev.
The 2nd part:
α = 5/12 = 0.41667 rev/s²
5 * 12 - ( 0.41667 * 12² / 2 ) = 60 - 30 = 30 rev.
In total: 20 + 30 = 50 revolutions 

If a rhino stampede runs at about 13.5 m/s. if they went 77 how long would it take them in seconds​?

Answers

Answer:

5.7 seconds

Step-by-step explanation:

Lets assume that 77 has units of meters (m).

The expression the relates time(T), speed(S), and distance(D) is:

    D = S*T

We are given S = 13.5 m/s and D = 77m

 D = S*T

 77m = (13.5 m/s)*(T)

T = (77 m)/(13.5 m/s)

T = 5.7 seconds

 

Final answer:

To find the time it would take for a rhino stampede running at a speed of 13.5 m/s to travel 77 meters, we use the formula Time = Distance/Speed, which gives us a result of approximately 5.7 seconds.

Explanation:

This is a classic physics problem where you are asked to calculate the time. The question is asking for the time it would take for a rhino stampede running at a speed of 13.5 m/s to reach a certain distance, which is 77 meters.

To find the time, you need to use the formula for time, which in terms of speed and distance is: Time = Distance/Speed.

Step 1: Plug in the given values into the formula. So Time = 77m / 13.5 m/s.

Step 2: Do the division. The result comes out to be around 5.7 seconds. Therefore, it will take about 5.7 seconds for the rhino stampede to reach 77 meters.

Learn more about Time Calculation here:

brainly.com/question/34080240

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Serena has $50 to spend. She buys 5 packages of hotdog buns and 5 packages of beef hotdogs. Each package of buns cost $3.85 and each package of beef hotdogs cost $4.20. How much money does Serena have left after these purchases?​

Answers

she will have 9.75 left