I just got confused with angle AED which I need to find the value of?

Answers

Answer 1

Answer:

Answer:

you should find the value of 112°

Answer 2

Answer: Angles in triangle add to 180
So 180-79-73 =28 and 180 -37-96=47
Angles around a point add to 360 so
112 + 28 + 47 = 187 then 360 - 187 = 173
So angle AED = 173 degrees

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Using distributive property combine 13c - 7c= Show work

What is the volume of the cube? A.
48 cm3

B.
192 cm3

C.
1536 cm3

D.
4096 cm3

Answers

volume of a cube= lenght x base x hieght
v= 16*16*16
teh volume of teh cube is D. 4096 cm^3

The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10

Answers

So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
y= 0.45

hope this helps :)

What is the difference between 5√3 and √27

Answers

Answer:

2√3

Step-by-step explanation:

5√3 - √27

= 5√3 - √9√3

= 5√3 - 3√3

=2√3

Which best describes the sides of all trapezoids? A.
Opposite sides are parallel.

B.
All sides are the same length.

C.
Only one pair of sides is parallel.

D.
All sides are different lengths.

Answers

C. Only one pair of sides is parallel.

25% of 68000 is how much

Answers

$1 \% =(1)/(100) \n \n25 \% =(25)/(100)=0,25\n \n25 \% \cdot 68000 = 0,25 \cdot 68000 =17 000$

$25\%\ of\ 68000= (25)/(100) \cdot 68,000= 25\cdot680=17,000$

Trig help (Problems already solved)?The calculation for the problems are already done but I have to list a reason or what is being done in each step. "Each = and newline made" means a place I have to write what is being done in the calculation.

1. (secx + sinx)cotx = cscx + cosx
=(secx + sinx)cotx = cscx + cosx
=(1 / sinx) + cosx
=cscx + cosx

2. cosx + tanx sinx = secx
=cosx + tanx sinx = cosx + (sinx / cosx)sinx
=cosx + (sin^2x / cosx) = (1 / cosx)(cos^2x + sin^2x)
=1 / cosx
=secx

3. cscx - cosx cotx = sinx
=cscx - cosx cotx = (1 / sinx) - cosx(cosx / sinx)
=(1 / sinx) - (cos^2x / sinx)
=(1 - cos^2x) / sinx
=sin^2x / sinx = sinx

4. (cosx / (1 + cosx)) + (cosx / (1 - cosx)) = 2cotx cscx
=(cosx / (1 + cosx)) + (cosx / (1 - cosx)) = ((cosx (1 - cosx) + cosx (1 + cosx))) / (1 + cosx)(1 - cosx)
=(cosx - cos^2x + cosx + cos^2x) / (1 - cos^2x)
=2cosx / sin^2x
=2(cosx / sinx)(1 / sinx) = 2cotx cscx

Thank you to whoever decides to help me with explaining what is happening on each line.

Answers

The first identity uses the definition of the reciprocal functions $\sec x,\csc x,\cot x$ and the distributive property of multiplication.

$(\sec x+\sin x)\cot x=\left(\frac1{\cos x}+\sin x\right)(\cos x)/(\sin x)$
$=(\cos x)/(\cos x\sin x)+(\cos x\sin x)/(\sin x)$
$=\frac1{\sin x}+\cos x$
$=\csc x+\cos x$

The second uses the definition of $\tan x$ and the distributive property. Then a factor of $\frac1{\cos x}$ is pulled out, which allows you to use the identity $\sin^2x+\cos^2x=1$ .

$\cos x+\tan x\sin x=\cos x+(\sin x)/(\cos x)\sin x$
$=\cos x+(\sin^2x)/(\cos x)$
$=(\cos^2x)/(\cos x)+(\sin^2x)/(\cos x)$
$=\frac1{\cos x}\left(\cos^2x+\sin^2x\right)$
$=\frac1{\cos x}*1$
$=\frac1{\cos x}$
$=1$

The third uses the same ideas as the second: rewrite the reciprocal functions, then invoke the Pythagorean identity $\sin^2x+\cos^2x=1$ , which is equivalent to $\sin^2x=1-\cos^2x$ .

$\csc x-\cos x\cot x=\frac1{\sin x}-\cos x(\cos x)/(\sin x)$
$=\frac1{\sin x}-(\cos^2x)/(\sin x)$
$=\frac1{\sin x}\left(1-\cos^2x\right)$
$=\frac1{\sin x}\sin^2x$
$=(\sin^2x)/(\sin x)$
$=\sin x$

In the last one, you combine the fractions by enforcing common denominators. This lets you add the numerators together, and the denominator can be simplified. Once you do that, you rewrite the factors of cos and sin in the numerator and denominator to make up the cot and csc functions, and you're done.

$(\cos x)/(1+\cos x)+(\cos x)/(1-\cos x)=(\cos x(1-\cos x))/((1+\cos x)(1-\cos x))+(\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x)+\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x+1+\cos x))/(1-\cos^2x)$
$=(2\cos x)/(\sin^2x)$
$=2(\cos x)/(\sin x)\frac1{\sin x}$
$=2\cot x\csc x$

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