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The number of protons in one atom of an element determines the atom’s atomicnumber.

What is atomic number?

The atomicnumber is the number of protons present basically in an atom's nucleus. The number of protons characterize the individuality of an element i.e., an element with 6 protons is a carbonatom, no matter however many neutrons may be prevalent.

The massnumber of an element is determined by the number of protons and neutrons combined: mass number = protons + neutrons.

To determine the number of neutrons in an atom, subtract the number of protons, or atomic number, from the mass number.

The atomic number is the number of protons in a nucleus that always equals the number of electrons in orbit around that nucleus (in a nonionized atom).

Thus, it can be concluded that the atomicnumber is determined by the number of protons in atom.

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The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge. The atomic number tells you the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element.

A group of atoms that are held together by covalent bonds so that they move as a group

Answer:

B.

Explanation:

Correct:  b. The mass of the Carbon-14 sample is greater than the Carbon-12 sample, but the reactivity of both samples was the same .

- C-14 has two additional neutrons, so is heavier than C-12.  The chemical properties will be the same, however.

Answer: Kilograms (kg)

Explanation:

Answer:

(g)

Explanation:

(g) is the symbol of a gram which is the metric unit that measures mass.

Hope that helps!

Answer: -

1.8

End point passed.

Explanation: -

Volume of HI solution = 47.0 mL = 0.047 L

Strength of HI solution = 0.47 M

Since HI is a strong acid, all of HI will dissociate to give H +.

[H+ ] =0.47 M x 0.047 L

= 0.02209 mol

Volume of KOH = 25.0 mL = 0.025 L

Strength of KOH = 0.25 M

Since KOH is a strong base, all of KOH will dissociate to give OH-.

[OH-] = 0.25 M x 0.025L

= 0.00625 mol

Since [H+] and [OH-] react to form water,

[H+] unreacted = 0.02209 – 0.00625 = 0.01584 mol

Using the formula

pH = - log [H+]

= - log 0.01584

= 1.8

As the strong acid HI is being titrated by strong base KOH, the pH at the end point should be 7.

The pH has already crossed that. Thus the titration end point has already passed

Final answer:

After titration, there are more moles of HI than KOH, implying excess HI (acid) is present. The remaining acid concentration is 0.2 M and consequently, the final pH of the solution is approximately 0.70.

Explanation:

In the case of the titration of a 47.0 mL of 0.47 M HI solution with 25.0 mL of 0.25 M KOH, we first need to understand that HI is a strong acid and KOH is a strong base. When we titrate a strong acid with a strong base, the equivalence point occurs at a pH of 7.0.

First, we calculate the moles of the acid and the base: moles of HI = 0.47 mol/L * 0.047 L = 0.02209 mol, and moles of KOH = 0.25 mol/L * 0.025 L = 0.00625 mol. Since there are more moles of HI than KOH, we will have extra HI left after the titration. Hence, it is a strong acid-strong base titration before the equivalence point i.e. when we have excess acid.

The remaining acid concentration is (0.02209 mol - 0.00625 mol) / (0.047 L + 0.025 L) = 0.2 M and pH of a strong acid is basically the negative logarithm of the acid's concentration. Therefore, the pH is -log[H+] = -log(0.2) = approx. 0.70.

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