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how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.

Answers

Answer 1

Answer:

Answer:

See Below.

Step-by-step explanation:

Remember multiplicity rules:

If a factor has an odd multiplicity (e.g. 1, 3, 5...), then the graph will cross the x-axis at that point.

If a factor has an even multiplicity (e.g. 2, 4, 6...), then the graph will bounce off the x-axis at that point.

From the graph, we can see that at our zeros, the graph always passes through the x-axis.

Hence, we do not have any zeros with even multiplicity since the graph does not "bounce" at any of the zeros.

Answer 2

Answer:

Final answer:

To determine if a polynomial function has zeros with even multiplicity, examine the graph or the exponents of the factors in the function. If there are no real zeros or all the factors are raised to odd powers, there won't be any even multiplicity zeros.

Explanation:

In order to determine if a polynomial function has zeros with even multiplicity, we can examine the function's graph. If a polynomial function does not have any real zeros, then it does not have any zeros with even multiplicity. This is because even multiplicity zeros occur when a factor appears multiple times in the function. However, if all the factors are raised to odd powers, then there won't be any even multiplicity zeros. On the other hand, if the function does have real zeros, we can look at the graph of the function to check if any zeros occur with even multiplicity.

Learn more about Determining zeros of polynomial functions here:

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Develop a 95% confidence interval estimate of the population mean rating for Miami. If required, round your answers to two decimal places. Do not round intermediate calculations.

Answers

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (5.7, 7.0).

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean, when the population standard deviation is not provided is:

$CI=\bar x\pm t_(\alpha/2, (n-1))\cdot\ (s)/(√(n))$

The sample selected is of size, n = 50.

The critical value of t for 95% confidence level and (n - 1) = 49 degrees of freedom is:

$t_(\alpha/2, (n-1))=t_(0.05/2, 49)=2.000$

*Use a t-table.

Compute the sample mean and sample standard deviation as follows:

$\bar x=(1)/(n)\sum {x}=(1)/(50)* [6+4+6+...+9+6]=6.34\n\ns=\sqrt{(1)/(n-1)\sum (x-\bar x)^(2)}=\sqrt{(1)/(50-1)* 229.22}=2.163$

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

$CI=\bar x\pm t_(\alpha/2, (n-1))\cdot\ (s)/(√(n))$

$=6.34\pm 2.00*(2.163)/(√(50))\n\n=6.34\pm 0.612\n\n=(5.728, 6.952)\n\n\approx(5.7, 7.0)$

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (5.7, 7.0).

The directional derivative of f(x, y) at (2, 1) in the direction going from (2, 1) toward the point (1, 3) is −2/ √ 5, and the directional derivative at (2, 1) in the direction going from (2, 1) toward the point (5, 5) is 1. Compute fx(2, 1) and fy(2, 1

Answers

Answer:

the partial derivatives are

fx =5/9

fy =(-13/18)

Step-by-step explanation:

defining the vector v (from (2,1) to (1,3))

v=(1,3)-(2,1) = (-1,2)

the unit vector will be

v'=(-1,2)/√5 = (-1/√5,2/√5)

the directional derivative is

fv(x,y) = fx*v'x + fy*v'y = fx*(-1/√5)+fy(2/√5) =-2/√5

then defining the vector u ( from (2, 1) toward the point (5, 5) )

u=(5,5)-(2,1) = (3,4)

the unit vector will be

u'=(3,4)/5 = (3/5,4/5)

the directional derivative is

fu(x,y) = fx*ux + fy*uy = fx*(3/5)+fy(4/5)=1

thus we have the set of linear equations

-fx/√5*+2*fy/√5 =(-2/√5) → -fx + 2*fy = -2

(3/5) fx+(4/5)*fy=1 → 3* fx+4*fy = 5

subtracting the first equation twice to the second

3*fx+4*fy -(- 2fx)*-4*fy = 5 -2*(-2)

5*fx=9

fx=5/9

thus from the first equation

-fx + 2*fy = -2

fy= fx/2 -1 = 5/18 -1 = -13/18

thus we have

fx =5/9

fy =(-13/18)

Pls help extra points

Answers

Answer:

Step-by-step explanation:

mODE IS THE MOST FREQUENT NUMBER.

1 IS THE MOST FREQUEN NUMBER LOL

SORRY FOR CAPS, SOMETHING IS WRONG WITH MY COMPUTER

Assume that you have a balance of $5000 on your Visa credit card and that you make no more charges. If your APR is 22% and each month you make only the minimum payment of 3% of your balance, then find a formula for the balance after t monthly payments.A) 5000(0.952217)t

B) 5000(1.011117)t

C) 5000(0.987783)t

D) 5000(1.048883)t

Can someone explain to me how to solve this please

Answers

Answer:

C) 5000(0.987783)^t

Step-by-step explanation:

The monthly interest rate is the APR divided by 12, so is 22%/12 ≈ 0.018333.

Each month, the previous balance (B) has interest charges added to it, so the new balance is ...

balance with interest charges = B + (22%)/12×B = 1.018333×B

The minimum payment is 3% of this amount, so the new balance for the next month is ...

balance after payment = (1.018333B)(1 - 0.03) = 0.987783B

Since the balance is multiplied by 0.987783 each month, after t payments, the balance starting with 5000 will be ...

5000×0.987783^t . . . . . . . . . matches choice C

1 is 25% of what number?

Answers

Answer:

25% of 4 is 1.

Step-by-step explanation:

100% of 4 is 4, therefore 25 percent of 4 equals 1.

4ab-3a+3bx-2ab anyone know the answer to this problem?

Answers

Answer:

-3a+3bx+2ab

Step-by-step explanation:

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how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.​

Answers

Final answer:

Explanation:

Learn more about Determining zeros of polynomial functions here:

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how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.