MATHEMATICS COLLEGE

Item 19Question 1
A person hikes 4 miles in 2.5 hours. Find the unit rate in miles per hour.








































A person hikes 4 miles in 2.5 hours. Find the unit rate in miles per hour.

Answers

Answer 1
Answer:

Answer:

Its 24

Step-by-step explanation:

im not sure

Related Questions

The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000. The ship building association wishes to find out whether their welders earn more or less than $20,000 annually. The alternate hypothesis is that the mean is not $20,000. If the level of significance for this two-tailed test is 0.10, what is/are the critical value(s)
Ten students begin college at the same time. The probability of graduating in four years is 63%. Which expanded expression shows the first and last terms of the expression used to find the probability that at least six will graduate in four years?
Algebra 2. pls help:(
T is the same as the quotient of 175 and p
The measure of the exterior angle of the triangle is?

Need help due 3 minutes!!!!!

Answers

Answer:

in standered form -

3x²+4x−14=0

Step-by-step explanation:

Hope this helps :)

Suppose a quiz contains 20 true/false questions. You know the correct answer to the first 10 questions. You have no idea of the correct answer to questions 11 through 20 and decide to answer each using the coin toss method. Calculate the probability of obtaining a total quiz score of at least 85%

Answers

Answer:

0.1719

Step-by-step explanation:

Given that:

A quiz contains 20 questions and 10 questions have been answered rightly

We are to determine the probability of getting a total quiz score of 85%

i.e 0.85 (20) = 17

Let's not forget that 10 is correctly answered out of 17. that implies that we only have 7 more questions to make a decision on.

where;

n = 10,

p + q = 1, 0.5 + q = 1

q = 1 - 0.5

q = 0.5

Let X be the random variable that follows the binomial distribution. Then ;

P(X = x) =(^n_x) p^x q^(n -x)

where x = 7

P(X \geq 7) =P(X=7)+P(X=8)+P(X=9)+P(X=10)

P(X \geq 7) =(^(10)_7})\ 0.5^7 \ 0.5 ^(10-7) + (^(10)_(8))\ 0.5^8 \ 0.5 ^(10-8)+(^(10)_9})\ 0.5^9 \ 0.5 ^(10-9)+ (^(10)_(10)})\ 0.5^(10) \ 0.5 ^(10-10)

P(X ≥ 7) = 0.1719

The area of a triangle can be found using the formula:Area=1/2=base=height
Find the area of the triangle pictured below where the measurements are given in meters, (M)
2m
5m
​

Answers

Answer:

5 squared units

Step-by-step explanation:

Area of triangle

= (1)/(2) * base * height \n \n = (1)/(2) * 2 * 5 \n \n = 5 \: {unit}^(2)

A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor. a. Write the differential equation satisfied by y in terms of proportionality k.
b. Find k (in units of day−1, assuming that 10% of the population knows the rumor at time t=0 and 40% knows it at time t=2 days.
c. Using the assumptions in part (b), determine when 75% of the population will know the rumor.
d. Plot the direction field for the differential equation and draw the curve that fits the solution y(0)=0.1 and y(0)=0.5.

Answers

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

a)

(dy)/(dt)\ \alpha\ y(1-y)

(dy)/(dt)=ky(1-y)

where k is the constant of proportionality, dy/dt =  rate at which the rumor spreads

b)

(dy)/(dt)=ky(1-y)\n(dy)/(y(1-y))=kdt\n\int\limits {(dy)/(y(1-y))} \, =\int\limit {kdt}\n\int\limits {(dy)/(y)} +\int\limits {(dy)/(1-y)} =\int\limit {kdt}\n\nln(y)-ln(1-y)=kt+c\nln((y)/(1-y)) =kt+c\ntaking \ exponential \ of\ both \ sides\n(y)/(1-y) =e^(kt+c)\n(y)/(1-y) =e^(kt)e^c\nlet\ A=e^c\n(y)/(1-y) =Ae^(kt)\ny=(1-y)Ae^(kt)\ny=(Ae^(kt))/(1+Ae^(kt)) \nat \ t=0,y=10\%\n0.1=(Ae^(k*0))/(1+Ae^(k*0)) \n0.1=(A)/(1+A) \nA=(1)/(9) \n

y=((1)/(9) e^(kt))/(1+(1)/(9) e^(kt))\ny=(1)/(1+9e^(-kt))

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

y=(1)/(1+9e^(-0.8959t))\n0.75=(1)/(1+9e^(-0.8959t))\nt=3.68\ days

Suppose you have saved m dollars for the party. Since you have been doing a lot of chores, your father decides to give you double the amount you have saved. You spend s dollars to throw the party. Which expression represents the amount of money you have left?

Answers

Answer:

m+2m-s

Step-by-step explanation:

Answer:

A: M + 2m - s

Step-by-step explanation:

Need Assitance
*Show Work*​

Answers

Answer:

66 2/3 %

Step-by-step explanation:

First find the students not in the 8th grade

24 - 8 = 16

16 students are not in the 8th grade

Take the fraction of the students not in the 8th grade over the total

16/24 = 2/3

Change to a decimal

.66666666666

Multiply by 100 to change to a percent

66.666666%

66 2/3 %

Answer:

66.67% of students are not in eighth grade

Step-by-step explanation:

8/24=1/3

1/3=0.33333333333

1-0.33333333333=0.66666666667

0.66666666667=66.67%
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