A bell tower casts a 60 cm shadow. At the same time a sculpture that is 4.5 meters tall casts a 15 cm shadow. How tall is the bell tower
A bell tower casts a 60 cm shadow. At the - 1

Answers

Answer 1
Answer:

Answer: 18

Step-by-step explanation:

x/4.5= 60/15

15x=270

X = 18cm


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X/2 + 5= -8 what does x equal and show work

Answers

Answer:

x = -26

Step-by-step explanation:

x/2 + 5 = -8

First let's combine like terms.

Subtract 5 from both sides.

x/2 = -13

Multiply both sides by 2 to isolate x.

x = -26

Plug this back into the original equation to check your answer.

-26/2 + 5 = -8

-13 + 5 = -8

-8 = -8

Your answer is correct.

Hope this helps!

Answer:

x=-26

Step-by-step explanation:

x/2 + 5 = -8

x/2 + 5 - 5 = -8 - 5

x/2 = -13

x = -26

this is all of the work I did to solve what x is! I hope it helped! There are many other way to solve this problem. This is the way which a lot of ppl do.

1. An equation is shown below.3 (x-2) + 7x= 1/2(6x-2)
How many solutions, if any, does the equation have?

Answers

Answer:

x=5/7

Step-by-step explanation:

3(x-2)+7×=1/2×(6×-2)

3x-6+7×=1/2×2(3×-1)

3×-6+7×=3×-1

-6+7×=-1

7×=-1+6

7×=5

An advertising agency is estimating costs for promoting a music festival. The job will require 200 direct labor hours at a cost of $50 per hour. Overhead costs are applied at a rate of $65 per direct labor hour.1. What is the total estimated cost for this job?
2. If the company applies a markup of 20% of total costs (price quote is 120% of total costs), what price should it quote for this job?

Answers

Answer:

$23,000 and $27,600

Step-by-step explanation:

To find the total cost of the job, we do the equation: $50 x 200

This equation will calculate the cost of the direct labor.

$50 x 200 = $10,000

Now, calculate the overhead prices

The equation is 200 x $65

This equals 13,000

Now add them and you get 23,000

The cost of the job is $23,000

To find the markup, 1.2 x $23,000 = $27,600

A restaurant has a capacity of 120 patrons. If the restaurant is full, how many patrons are at the restaurant?

Answers

Answer:120?

Step-by-step explanation:

For many years, businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent survey showed that 62% of employers are likely to require higher employee contributions for health care coverage this year relative to last year. Suppose the survey was based on a sample of 800 companies likely to require higher employee contributions for health care coverage this year relative to last year. At 95% confidence, compute the margin of error for the proportion of companies likely to require higher employee contributions for health care coverage. (Round your answer to four decimal places.) Compute a 95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage. (Round your answers to four decimal places.)

Answers

Answer:

95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage.

(0.5868 , 0.6532)

Step-by-step explanation:

Step(i):-

Given the survey was based on a sample of 800 companies

Given size 'n'  = 800

A recent survey showed that 62% of employers are likely to require higher employee contributions for health care coverage this year relative to last year

sample proportion

                                p⁻ = 0.62

Step(ii):-

The margin of error for the proportion of companies likely to require higher employee contributions for health care coverage.

M.E= Z_(0.05)  \sqrt{(p^(-) (1-p^(-)) )/(n) }

M.E= 1.96\sqrt{(0.62 (1-0.62 )/(800) }

M.E  = 0.017 X 1.96

M.E = 0.03

Step(iii):-

95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage.

(p^(-) - Z_(0.05)  \sqrt{(p^(-) (1-p^(-)) )/(n) } , p^(-) +Z_(0.05)  \sqrt{(p^(-) (1-p^(-)) )/(n) })

(0.62 - 1.96\sqrt{(0.62 (1-0.62 )/(800) } ,0.62+1.96\sqrt{(0.62 (1-0.62 )/(800) }

( 0.62 - 0.0332 , 0.62+0.0332)

(0.5868 , 0.6532)

Final answer:

The margin of error for the proportion of companies likely to require higher employee contributions for health care coverage is approximately 0.0245. The 95% confidence interval for the proportion of companies likely to require higher employee contributions is (0.5955, 0.6445).

Explanation:

To compute the margin of error for the proportion of companies likely to require higher employee contributions for health care coverage, we can use the formula:

Margin of error = Z * sqrt((p * (1-p)) / n)

where Z is the Z-score corresponding to the desired confidence level (95% in this case), p is the proportion of companies likely to require higher employee contributions, and n is the sample size. Substituting the given values into the formula, we have:

Margin of error = 1.96 * sqrt((0.62 * (1-0.62)) / 800)

Calculating this value gives us a margin of error of approximately 0.0245.

To compute the 95% confidence interval for the proportion of companies likely to require higher employee contributions, we can use the formula:

Confidence interval = p ± margin of error

Substituting the given values into the formula, we have:

Confidence interval = 0.62 ± 0.0245

Calculating this value gives us a confidence interval of (0.5955, 0.6445).

Learn more about Margin of error for a proportion here:

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Problem 11. (3 pt) [MBB2012, Ex. 4.46, p. 150, Dice] An experiment consists of tossing a single die and observing the number of dots that show on the upper face. Events A, B, and C are defined as follows: (A:) Observe a number less than 4 (B:) Observe a number less than or equal to 2 (C:) Observe a number greater than 3 Find the probabilities associated with the events below using either the simple event approach or the rules and definitions from this section. (a) S (b) A|B (c) B (d) A ∩ B ∩ C (e) A ∩ B (f) A ∩ C (g) B ∩ C (h) A ∪ B (i) B ∪ C .

Answers

Hope this helps, let me know if it doesn't make sense