MATHEMATICS COLLEGE

over 6 days, Dan jogged 7.5 miles, 6 miles, 3 miles, 3 miles, 5.5 miles and 5 miles what is the mean distance that Dan jogged each day

Answers

Answer 1
Answer: To start add together all of the miles over 6 days. Added together it equals 30 miles.

Then take 30 miles divided by how many days.
30 divided by 6.
30 divided by 6=5
5 miles is the mean distance.

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There are 25 marbles in the box. There are 10 red marbles , 8 blue marbles , and 7 yellow marbles . What percent of the marbles are NOT yellow ?A. 28%
B. 72%
C. 32%
D. 40%

Answers

I think it is 32 which is c or 40% which is D but I got 43%
40 percent Woolf be the answer because they are pulling out the smallest number but it still is a big percentage

Solve for x.
8x=4x−32
A)x = 8
B)x = 4
C) x=−4
D) x=−8

Answers

Answer:

x=-8

Step-by-step explanation:

i took the quiz

Answerd

                     

Step-by-step explanation:

Do these pairs of values (x and y) represent two quantities that are proportional?HELP ME PLEASE

Answers

Yes, it is proportional. The answer would be B.

Explanation:

The common difference in the X factors is 2, and t he common difference in the y factors is 1.

Answer:

its b but i am not sure because my text was different

Solve the differential equation x^2 y"-xy' +y 0

Answers

Answer:

y(x)\ =\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

Step-by-step explanation:

Given differential equation is

x^2y                     (1)

Let's assume that

x=e^t

=>\ t\ =\ logx

then,

(dx)/(dt)=e^t

and\ (d^2x)/(dt^2)=e^t

We can write,

(dy)/(dx)=(dy)/(dt).(dt)/(dx)

                      =e^(-t)(dy)/(dt)

Similarly,

(d^2y)/(dt^2)=(d^2y)/(dt^2).(dt^2)/(dx^2)

                            =e^(-2t).(d^2y)/(dt^2)

Putting these values in equation (1), we will get

e^(2t).e^(-2t).(d^y)/(dt^2)-e^t.e^(-t)(dy)/(dt)+y=0

=>(d^2y)/(dt^2)-(dy)/(dt)+y=0

So, the characteristics equation can be given as

D^2-D+1=0

=>D\ =\ (1+√(1-4))/(2)\ or\ (1-1√(1-4))/(2)

=>D=\ (1)/(2)+i(√(3))/(2)\ or\ (1)/(2)-i(√(3))/(2)

Hence, the general solution of the equation can be give by

y(t)\ =\ e^{(t)/(2)}[C_1cos(√(3))/(2)t+C_2sin(√(3))/(2)t]

Now, by putting the value of t in above solution, we will have

y(x)\ =\ e^{(1)/(2)logx}[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

y(x)=\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

Hence, the solution of above given differential equation can be given by

y(x)=\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

                           

Helppppppppppppp plzzzzzzzzzzzzzz

Answers

Answer:

d. a reflection across the y-axis
The answer to this it d.

5 23 18 8 4
Order of operations

Answers

Answer:

no u

Step-by-step explanation:

Answer:

hmm lets see sorry i cant help i wish i could but its been a while

Step-by-step explanation:
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