CHEMISTRY COLLEGE

Write balanced net ionic equations and the corresponding equilibrium equations for the stepwise dissociation of the triprotic acid H3PO4.

Answers

Answer 1

Answer:

Answer:

$H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^(-)(aq); \ Ka_1$

$H_2PO_4^(-)(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^(-2)(aq); \ Ka_2$

$HPO_4^(-2)(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^(-3)(aq); \ Ka_3$

Explanation:

Hello!

In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:

$H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^(-)(aq); \ Ka_1$

$H_2PO_4^(-)(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^(-2)(aq); \ Ka_2$

$HPO_4^(-2)(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^(-3)(aq); \ Ka_3$

Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:

Ka1 > Ka2 > Ka3

Best regards!

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At 25.0 ⁰C the henry's law constant for hydrogen sulfide(H2S) gas in water is 0.087 M/atm. Caculate the mass in grams of H2S gas that can be dissolved in 400.0 ml of water at 25.00 C and a H2S partial pressure of 2.42atm.

Answers

Answer: The mass of hydrogen sulfide that can be dissolved is 2.86 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the gas.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_(H_2S)=K_H* p_(liquid)$

where,

$K_H$ = Henry's constant = $0.087M/atm$

$p_(H_2S)$ = partial pressure of hydrogen sulfide gas = 2.42 atm

Putting values in above equation, we get:

$C_(H_2S)=0.087M/atm* 2.42atm\n\nC_(H_2S)=0.2105M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.2105 M

Molar mass of hydrogen sulfide = 34 g/mol

Volume of solution = 400.0 mL

Putting values in above equation, we get:

$0.2105M=\frac{\text{Mass of hydrogen sulfide}* 1000}{34g/mol* 400.0mL}\n\n\text{Mass of }H_2S=(0.2105* 34* 400)/(1000)=2.86g$

Hence, the mass of hydrogen sulfide that can be dissolved is 2.86 grams.

6 CO2 + 6 H2O
How many atoms of each element are in
the equation?

Answers

Answer:

There are 6 Carbon dioxides, and 6 waters, but there are 6 carbons, 18 oxygens, and 12 hydrogens.

Explanation:

Answer:

6 carbon atoms

18 oxygen atoms

12 hydrogen atoms

Draw all the structural isomers for the molecular formula C3H8O. Be careful not to draw any structures by crossing one line over another; the system needs to know where you intend connections to be between atoms.

Answers

Answer:

The three isomers having the molecular formula $C_(3) H_(8)O$ are drawn in the figure below.

Explanation:

Identify two ions that have the following ground-state electron configurations Part B
[Ar]3d^5
Check all that apply.
A- Fe2+
B- Fe3+
C- Mn2+
D- V+
E- Sc2+

Answers

Answer: $Fe^(2+):24:[Ar]3d^5$

$Mn^(2+):23:[Ar]3d^5$

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies.

The electronic configuration for given elements is as follows:

$Fe:26:[Ar]3d^64s^2$

$Fe^(2+):24:[Ar]3d^5$

$Fe^(3+):23:[Ar]3d^4$

$Mn:25:[Ar]3d^54s^2$

$Mn^(2+):23:[Ar]3d^5$

$V:23:[Ar]3d^34s^2$

$V^+:22:[Ar]3d^34s^1$

$Sc:21:[Ar]3d^14s^2$

$Sc^(2+):19:[Ar]3d^1$

Final answer:

The ions Fe2+ and Mn2+ have the ground-state electron configuration [Ar]3d^5.

Explanation:

The ground-state electron configuration [Ar]3d^5 indicates a level of electrons in 3d subshell after the Argon core electron configuration. Now, iron (Fe) has a base atomic configuration of [Ar]3d^6 4s2. When it loses 2 electrons (to form Fe2+), it tends to lose from both the 3d and the 4s sublevels, giving [Ar]3d^5 (which is our required configuration).

However, it's also important to consider Manganese (Mn), which has a base configuration of [Ar]3d^5 4s2. It usually loses 2 electrons from the 4s sublevel first when it forms Mn2+ which results in a configuration [Ar]3d^5.

So, the two ions with the electron configuration [Ar]3d^5 are Fe2+ and Mn2+.

Learn more about Electron Configuration here:

brainly.com/question/31812229

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lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL?

Answers

Answer:

The concentration is 0.036 mg/mL

Explanation:

Concentration = 0.2 mM = 0.2/1000 = 2×10^-4 M = 2×10^-4 mol/L × 180,000 mg/1 mol × 1 L/1000 mL = 0.036 mg/mL

HELP ASAP WHICH ONE IS THE ANSWE A OR B OR C OR D ???? ! !!!

Answers

Answer:

1. C

2.B

Explanation:

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